Traversing a grid












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I'm wondering if there's a way to check if every square of a board can be visited such that every time you move to a new square, it can't be in the same row, column, or diagonal as the previous square. If it can, how could I find a sequence of squares that works? I've ascertained that it can't be done if $text{rows} + text{columns} leq 6$. It kind of reminds me of the n queens problem, but I'm not sure how to proceed.









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    I'm wondering if there's a way to check if every square of a board can be visited such that every time you move to a new square, it can't be in the same row, column, or diagonal as the previous square. If it can, how could I find a sequence of squares that works? I've ascertained that it can't be done if $text{rows} + text{columns} leq 6$. It kind of reminds me of the n queens problem, but I'm not sure how to proceed.









    share







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    tostito is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      I'm wondering if there's a way to check if every square of a board can be visited such that every time you move to a new square, it can't be in the same row, column, or diagonal as the previous square. If it can, how could I find a sequence of squares that works? I've ascertained that it can't be done if $text{rows} + text{columns} leq 6$. It kind of reminds me of the n queens problem, but I'm not sure how to proceed.









      share







      New contributor




      tostito is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







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      I'm wondering if there's a way to check if every square of a board can be visited such that every time you move to a new square, it can't be in the same row, column, or diagonal as the previous square. If it can, how could I find a sequence of squares that works? I've ascertained that it can't be done if $text{rows} + text{columns} leq 6$. It kind of reminds me of the n queens problem, but I'm not sure how to proceed.







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