“Riffle” two strings












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I have two strings, e.g., s1="A|P|Q|Z" and s2="r|ss|t|yy", where "|" is meant to be a separator. I would like to get the result as another string s=Ar|Pss|Qt|Zyy by joining the corresponding parts of the two strings s1 and s2 as indicated by the separators. What would be a simple way to do this?










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    3












    $begingroup$


    I have two strings, e.g., s1="A|P|Q|Z" and s2="r|ss|t|yy", where "|" is meant to be a separator. I would like to get the result as another string s=Ar|Pss|Qt|Zyy by joining the corresponding parts of the two strings s1 and s2 as indicated by the separators. What would be a simple way to do this?










    share|improve this question









    $endgroup$















      3












      3








      3


      1



      $begingroup$


      I have two strings, e.g., s1="A|P|Q|Z" and s2="r|ss|t|yy", where "|" is meant to be a separator. I would like to get the result as another string s=Ar|Pss|Qt|Zyy by joining the corresponding parts of the two strings s1 and s2 as indicated by the separators. What would be a simple way to do this?










      share|improve this question









      $endgroup$




      I have two strings, e.g., s1="A|P|Q|Z" and s2="r|ss|t|yy", where "|" is meant to be a separator. I would like to get the result as another string s=Ar|Pss|Qt|Zyy by joining the corresponding parts of the two strings s1 and s2 as indicated by the separators. What would be a simple way to do this?







      string-manipulation






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      share|improve this question










      asked 8 hours ago









      nanjunnanjun

      43729




      43729






















          1 Answer
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          $begingroup$

          Try this:



          StringSplit[{s1, s2}, "|"] // Transpose // StringRiffle[#, "|", ""] &





          share|improve this answer









          $endgroup$













          • $begingroup$
            Clean and elegant (+1).
            $endgroup$
            – David G. Stork
            8 hours ago












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          1 Answer
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          1 Answer
          1






          active

          oldest

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          active

          oldest

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          active

          oldest

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          7












          $begingroup$

          Try this:



          StringSplit[{s1, s2}, "|"] // Transpose // StringRiffle[#, "|", ""] &





          share|improve this answer









          $endgroup$













          • $begingroup$
            Clean and elegant (+1).
            $endgroup$
            – David G. Stork
            8 hours ago
















          7












          $begingroup$

          Try this:



          StringSplit[{s1, s2}, "|"] // Transpose // StringRiffle[#, "|", ""] &





          share|improve this answer









          $endgroup$













          • $begingroup$
            Clean and elegant (+1).
            $endgroup$
            – David G. Stork
            8 hours ago














          7












          7








          7





          $begingroup$

          Try this:



          StringSplit[{s1, s2}, "|"] // Transpose // StringRiffle[#, "|", ""] &





          share|improve this answer









          $endgroup$



          Try this:



          StringSplit[{s1, s2}, "|"] // Transpose // StringRiffle[#, "|", ""] &






          share|improve this answer












          share|improve this answer



          share|improve this answer










          answered 8 hours ago









          sakrasakra

          2,7781429




          2,7781429












          • $begingroup$
            Clean and elegant (+1).
            $endgroup$
            – David G. Stork
            8 hours ago


















          • $begingroup$
            Clean and elegant (+1).
            $endgroup$
            – David G. Stork
            8 hours ago
















          $begingroup$
          Clean and elegant (+1).
          $endgroup$
          – David G. Stork
          8 hours ago




          $begingroup$
          Clean and elegant (+1).
          $endgroup$
          – David G. Stork
          8 hours ago


















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