How to write this math term? with cases it isn't working
I can't find a way to write this in Latex. Any hints where to start?
math-mode
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add a comment |
I can't find a way to write this in Latex. Any hints where to start?
math-mode
New contributor
Welcome to TeX.SE.
– Mico
1 hour ago
add a comment |
I can't find a way to write this in Latex. Any hints where to start?
math-mode
New contributor
I can't find a way to write this in Latex. Any hints where to start?
math-mode
math-mode
New contributor
New contributor
New contributor
asked 1 hour ago
Debotush DamDebotush Dam
132
132
New contributor
New contributor
Welcome to TeX.SE.
– Mico
1 hour ago
add a comment |
Welcome to TeX.SE.
– Mico
1 hour ago
Welcome to TeX.SE.
– Mico
1 hour ago
Welcome to TeX.SE.
– Mico
1 hour ago
add a comment |
3 Answers
3
active
oldest
votes
A combination of a drcases
environment (provided by the mathtools
package and a plain tabular
environment gets the job done:
documentclass{article}
usepackage{mathtools} % for 'drcases' environment
begin{document}
[
begin{drcases}
g^l_{ij} = frac{partial e}{partial w^l_{ij}} = dots\
w^l_{ij} = dots
end{drcases}
qquad
begin{tabular}{@{}l}
for $l=dots$\
for $i=dots$\
for $j=dots$
end{tabular}
]
end{document}
add a comment |
Similar to Mico's approach but with the equal sign aligned.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{align*}
left.begin{aligned}
g_{ij}^i &=frac{partial e}{partial w_{ij}^I}=A(I_i)delta^{ell+1}_j\
w_{ij}^i &=w_{ij}^ell-r,g_{ij}^ell\
end{aligned}right}qquad
begin{array}{l}
text{for $ell=1,2,3,dots L$,}\
text{for $i=0,1,2,dots N^{ell+1}$,}\
text{for $j=1,2,3,dots N^{ell+1+2}$}
end{array}
end{align*}
end{document}
+1. :-) I think, though, that it's supposed to bew^l
(orw^ell
, if you prefer) rather than eitherw^I
orw^i
...
– Mico
22 mins ago
add a comment |
A combination of aligned
and alignedat
so all equals signs are aligned.
documentclass{article}
usepackage{amsmath}
newcommand{pder}[2]{frac{partial #1}{partial #2}}
begin{document}
[
left.
begin{aligned}
g_{ij}^l &= pder{e}{w_{ij}^l} = mathcal{A}(I_i^l)delta_i^{l+1}
\[2ex]
w_{ij}^l &= w_{ij}^l-rg_{ij}^l
end{aligned}
right}
qquad
begin{alignedat}{2}
&text{for} &quad l &= 1,2,3,dots, L,\
&text{for} & i &= 0,1,2,dots, N^{l+1},\
&text{for} & j &= 1,2,3,dots, N^{l+1}.
end{alignedat}
]
end{document}
The bottom equality in the left part is suspicious, check it.
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
A combination of a drcases
environment (provided by the mathtools
package and a plain tabular
environment gets the job done:
documentclass{article}
usepackage{mathtools} % for 'drcases' environment
begin{document}
[
begin{drcases}
g^l_{ij} = frac{partial e}{partial w^l_{ij}} = dots\
w^l_{ij} = dots
end{drcases}
qquad
begin{tabular}{@{}l}
for $l=dots$\
for $i=dots$\
for $j=dots$
end{tabular}
]
end{document}
add a comment |
A combination of a drcases
environment (provided by the mathtools
package and a plain tabular
environment gets the job done:
documentclass{article}
usepackage{mathtools} % for 'drcases' environment
begin{document}
[
begin{drcases}
g^l_{ij} = frac{partial e}{partial w^l_{ij}} = dots\
w^l_{ij} = dots
end{drcases}
qquad
begin{tabular}{@{}l}
for $l=dots$\
for $i=dots$\
for $j=dots$
end{tabular}
]
end{document}
add a comment |
A combination of a drcases
environment (provided by the mathtools
package and a plain tabular
environment gets the job done:
documentclass{article}
usepackage{mathtools} % for 'drcases' environment
begin{document}
[
begin{drcases}
g^l_{ij} = frac{partial e}{partial w^l_{ij}} = dots\
w^l_{ij} = dots
end{drcases}
qquad
begin{tabular}{@{}l}
for $l=dots$\
for $i=dots$\
for $j=dots$
end{tabular}
]
end{document}
A combination of a drcases
environment (provided by the mathtools
package and a plain tabular
environment gets the job done:
documentclass{article}
usepackage{mathtools} % for 'drcases' environment
begin{document}
[
begin{drcases}
g^l_{ij} = frac{partial e}{partial w^l_{ij}} = dots\
w^l_{ij} = dots
end{drcases}
qquad
begin{tabular}{@{}l}
for $l=dots$\
for $i=dots$\
for $j=dots$
end{tabular}
]
end{document}
answered 1 hour ago
MicoMico
287k32392781
287k32392781
add a comment |
add a comment |
Similar to Mico's approach but with the equal sign aligned.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{align*}
left.begin{aligned}
g_{ij}^i &=frac{partial e}{partial w_{ij}^I}=A(I_i)delta^{ell+1}_j\
w_{ij}^i &=w_{ij}^ell-r,g_{ij}^ell\
end{aligned}right}qquad
begin{array}{l}
text{for $ell=1,2,3,dots L$,}\
text{for $i=0,1,2,dots N^{ell+1}$,}\
text{for $j=1,2,3,dots N^{ell+1+2}$}
end{array}
end{align*}
end{document}
+1. :-) I think, though, that it's supposed to bew^l
(orw^ell
, if you prefer) rather than eitherw^I
orw^i
...
– Mico
22 mins ago
add a comment |
Similar to Mico's approach but with the equal sign aligned.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{align*}
left.begin{aligned}
g_{ij}^i &=frac{partial e}{partial w_{ij}^I}=A(I_i)delta^{ell+1}_j\
w_{ij}^i &=w_{ij}^ell-r,g_{ij}^ell\
end{aligned}right}qquad
begin{array}{l}
text{for $ell=1,2,3,dots L$,}\
text{for $i=0,1,2,dots N^{ell+1}$,}\
text{for $j=1,2,3,dots N^{ell+1+2}$}
end{array}
end{align*}
end{document}
+1. :-) I think, though, that it's supposed to bew^l
(orw^ell
, if you prefer) rather than eitherw^I
orw^i
...
– Mico
22 mins ago
add a comment |
Similar to Mico's approach but with the equal sign aligned.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{align*}
left.begin{aligned}
g_{ij}^i &=frac{partial e}{partial w_{ij}^I}=A(I_i)delta^{ell+1}_j\
w_{ij}^i &=w_{ij}^ell-r,g_{ij}^ell\
end{aligned}right}qquad
begin{array}{l}
text{for $ell=1,2,3,dots L$,}\
text{for $i=0,1,2,dots N^{ell+1}$,}\
text{for $j=1,2,3,dots N^{ell+1+2}$}
end{array}
end{align*}
end{document}
Similar to Mico's approach but with the equal sign aligned.
documentclass{article}
usepackage{mathtools}
begin{document}
begin{align*}
left.begin{aligned}
g_{ij}^i &=frac{partial e}{partial w_{ij}^I}=A(I_i)delta^{ell+1}_j\
w_{ij}^i &=w_{ij}^ell-r,g_{ij}^ell\
end{aligned}right}qquad
begin{array}{l}
text{for $ell=1,2,3,dots L$,}\
text{for $i=0,1,2,dots N^{ell+1}$,}\
text{for $j=1,2,3,dots N^{ell+1+2}$}
end{array}
end{align*}
end{document}
answered 59 mins ago
marmotmarmot
119k6154288
119k6154288
+1. :-) I think, though, that it's supposed to bew^l
(orw^ell
, if you prefer) rather than eitherw^I
orw^i
...
– Mico
22 mins ago
add a comment |
+1. :-) I think, though, that it's supposed to bew^l
(orw^ell
, if you prefer) rather than eitherw^I
orw^i
...
– Mico
22 mins ago
+1. :-) I think, though, that it's supposed to be
w^l
(or w^ell
, if you prefer) rather than either w^I
or w^i
...– Mico
22 mins ago
+1. :-) I think, though, that it's supposed to be
w^l
(or w^ell
, if you prefer) rather than either w^I
or w^i
...– Mico
22 mins ago
add a comment |
A combination of aligned
and alignedat
so all equals signs are aligned.
documentclass{article}
usepackage{amsmath}
newcommand{pder}[2]{frac{partial #1}{partial #2}}
begin{document}
[
left.
begin{aligned}
g_{ij}^l &= pder{e}{w_{ij}^l} = mathcal{A}(I_i^l)delta_i^{l+1}
\[2ex]
w_{ij}^l &= w_{ij}^l-rg_{ij}^l
end{aligned}
right}
qquad
begin{alignedat}{2}
&text{for} &quad l &= 1,2,3,dots, L,\
&text{for} & i &= 0,1,2,dots, N^{l+1},\
&text{for} & j &= 1,2,3,dots, N^{l+1}.
end{alignedat}
]
end{document}
The bottom equality in the left part is suspicious, check it.
add a comment |
A combination of aligned
and alignedat
so all equals signs are aligned.
documentclass{article}
usepackage{amsmath}
newcommand{pder}[2]{frac{partial #1}{partial #2}}
begin{document}
[
left.
begin{aligned}
g_{ij}^l &= pder{e}{w_{ij}^l} = mathcal{A}(I_i^l)delta_i^{l+1}
\[2ex]
w_{ij}^l &= w_{ij}^l-rg_{ij}^l
end{aligned}
right}
qquad
begin{alignedat}{2}
&text{for} &quad l &= 1,2,3,dots, L,\
&text{for} & i &= 0,1,2,dots, N^{l+1},\
&text{for} & j &= 1,2,3,dots, N^{l+1}.
end{alignedat}
]
end{document}
The bottom equality in the left part is suspicious, check it.
add a comment |
A combination of aligned
and alignedat
so all equals signs are aligned.
documentclass{article}
usepackage{amsmath}
newcommand{pder}[2]{frac{partial #1}{partial #2}}
begin{document}
[
left.
begin{aligned}
g_{ij}^l &= pder{e}{w_{ij}^l} = mathcal{A}(I_i^l)delta_i^{l+1}
\[2ex]
w_{ij}^l &= w_{ij}^l-rg_{ij}^l
end{aligned}
right}
qquad
begin{alignedat}{2}
&text{for} &quad l &= 1,2,3,dots, L,\
&text{for} & i &= 0,1,2,dots, N^{l+1},\
&text{for} & j &= 1,2,3,dots, N^{l+1}.
end{alignedat}
]
end{document}
The bottom equality in the left part is suspicious, check it.
A combination of aligned
and alignedat
so all equals signs are aligned.
documentclass{article}
usepackage{amsmath}
newcommand{pder}[2]{frac{partial #1}{partial #2}}
begin{document}
[
left.
begin{aligned}
g_{ij}^l &= pder{e}{w_{ij}^l} = mathcal{A}(I_i^l)delta_i^{l+1}
\[2ex]
w_{ij}^l &= w_{ij}^l-rg_{ij}^l
end{aligned}
right}
qquad
begin{alignedat}{2}
&text{for} &quad l &= 1,2,3,dots, L,\
&text{for} & i &= 0,1,2,dots, N^{l+1},\
&text{for} & j &= 1,2,3,dots, N^{l+1}.
end{alignedat}
]
end{document}
The bottom equality in the left part is suspicious, check it.
answered 1 min ago
egregegreg
735k8919343257
735k8919343257
add a comment |
add a comment |
Debotush Dam is a new contributor. Be nice, and check out our Code of Conduct.
Debotush Dam is a new contributor. Be nice, and check out our Code of Conduct.
Debotush Dam is a new contributor. Be nice, and check out our Code of Conduct.
Debotush Dam is a new contributor. Be nice, and check out our Code of Conduct.
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– Mico
1 hour ago