Difference between -| and |- in TikZ
Based on this tutorial, I understand symbols -|
and |-
are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -|
and |-
.
tikz-pgf
add a comment |
Based on this tutorial, I understand symbols -|
and |-
are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -|
and |-
.
tikz-pgf
1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
add a comment |
Based on this tutorial, I understand symbols -|
and |-
are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -|
and |-
.
tikz-pgf
Based on this tutorial, I understand symbols -|
and |-
are used to draw perpendicular lines.
But I wish to understand the difference between the two.
There are the following related questions:
- Insertion of perpendicular symbol at intersection of two perpendicular lines
- How to add perpendicular symbol at desired location
- How to Mark Right Angle in Tikz
But none of them seem to use the approach of -|
and |-
.
tikz-pgf
tikz-pgf
asked yesterday
subham sonisubham soni
4,51983184
4,51983184
1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
add a comment |
1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
1
1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
tex.stackexchange.com/a/401429/121799
– marmot
yesterday
add a comment |
3 Answers
3
active
oldest
votes
Understand it as it looks like:
-|
is "horizontal line → vertical line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) -| (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.
|-
is "vertical line → horizontal line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) |- (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
add a comment |
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
usetikzlibrary{positioning}
begin{document}
begin{tikzpicture}
node[draw] (A) {A};
node[draw, above right =4cm of A] (B) {B};
node[draw] at (A |- B) {$x$ of A, $y$ of B};
node[draw] at (A -| B) {$x$ of B, $y$ of A};
end{tikzpicture}
end{document}
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
22 hours ago
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)
(A-|B)
(TikZ) =(B|A)
(PSTricks)
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
Understand it as it looks like:
-|
is "horizontal line → vertical line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) -| (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.
|-
is "vertical line → horizontal line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) |- (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
add a comment |
Understand it as it looks like:
-|
is "horizontal line → vertical line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) -| (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.
|-
is "vertical line → horizontal line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) |- (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
add a comment |
Understand it as it looks like:
-|
is "horizontal line → vertical line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) -| (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.
|-
is "vertical line → horizontal line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) |- (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
Understand it as it looks like:
-|
is "horizontal line → vertical line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) -| (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) -| (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) -| (a,b)
and(x,y) -- (a,y) -- (a,b)
are the same.
|-
is "vertical line → horizontal line":
documentclass[tikz]{standalone}
begin{document}
begin{tikzpicture}
draw (0,0) coordinate (1) node[below] {$(0,0)$};
draw (2,2) coordinate (2) node[above] {$(2,2)$};
draw (1) |- (2);
% -------------
draw (4,2) coordinate (x) node[above] {$(3,2)$};
draw (6,0) coordinate (y) node[below] {$(5,0)$};
draw (x) |- (y);
end{tikzpicture}
end{document}
Mathematically,
(x,y) |- (a,b)
and(x,y) -- (x,b) -- (a,b)
are the same.
They are clearly very different.
edited 17 hours ago
answered yesterday
JouleVJouleV
7,89222053
7,89222053
add a comment |
add a comment |
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
usetikzlibrary{positioning}
begin{document}
begin{tikzpicture}
node[draw] (A) {A};
node[draw, above right =4cm of A] (B) {B};
node[draw] at (A |- B) {$x$ of A, $y$ of B};
node[draw] at (A -| B) {$x$ of B, $y$ of A};
end{tikzpicture}
end{document}
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
22 hours ago
add a comment |
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
usetikzlibrary{positioning}
begin{document}
begin{tikzpicture}
node[draw] (A) {A};
node[draw, above right =4cm of A] (B) {B};
node[draw] at (A |- B) {$x$ of A, $y$ of B};
node[draw] at (A -| B) {$x$ of B, $y$ of A};
end{tikzpicture}
end{document}
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
22 hours ago
add a comment |
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
usetikzlibrary{positioning}
begin{document}
begin{tikzpicture}
node[draw] (A) {A};
node[draw, above right =4cm of A] (B) {B};
node[draw] at (A |- B) {$x$ of A, $y$ of B};
node[draw] at (A -| B) {$x$ of B, $y$ of A};
end{tikzpicture}
end{document}
I'd like to add to JouleV's answer another use of -|
and |-
.
Given two nodes, A and B:
- if you use
(A |- B)
you have a point with the x coordinate of A and the y coordinate of B - if you use
(A -| B)
you have a point with the x coordinate of B and the y coordinate of A.
documentclass{article}
usepackage{amsmath}
usepackage{tikz}
usetikzlibrary{positioning}
begin{document}
begin{tikzpicture}
node[draw] (A) {A};
node[draw, above right =4cm of A] (B) {B};
node[draw] at (A |- B) {$x$ of A, $y$ of B};
node[draw] at (A -| B) {$x$ of B, $y$ of A};
end{tikzpicture}
end{document}
edited 22 hours ago
answered yesterday
CarLaTeXCarLaTeX
34k551140
34k551140
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
22 hours ago
add a comment |
2
You're welcome! I edited my answer to put x and y within$...$
.
– CarLaTeX
22 hours ago
2
2
You're welcome! I edited my answer to put x and y within
$...$
.– CarLaTeX
22 hours ago
You're welcome! I edited my answer to put x and y within
$...$
.– CarLaTeX
22 hours ago
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)
(A-|B)
(TikZ) =(B|A)
(PSTricks)
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)
(A-|B)
(TikZ) =(B|A)
(PSTricks)
add a comment |
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)
(A-|B)
(TikZ) =(B|A)
(PSTricks)
PSTricks version for @CarLaTeX's explanation:
(A|-B)
(TikZ) =(A|B)
(PSTricks)
(A-|B)
(TikZ) =(B|A)
(PSTricks)
answered yesterday
The Inventor of GodThe Inventor of God
4,99611142
4,99611142
add a comment |
add a comment |
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1
tex.stackexchange.com/a/401429/121799
– marmot
yesterday