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An Accountant Seeks the Help of a Mathematician


Four prisoners wearing black and white hatsDeduce the numbers (addition + subtraction)Determine $X$ and $Y$: sum, difference and ratioSum, Product and DifferenceFind the identity of the four troll brothers4 Gridded Prime NumbersHow does the hit-man assassinate his target using only two questions?My Friend, 4 kids and gold and silver coinsA Counterfeit $100 Bill among 93 BillsRanking teacher salaries in the Republic of al'Alghaz













6












$begingroup$


The accountant complaints to the mathematician:




“I lent money to five other faculty members and still haven’t been paid back. You are one of them; the other four owe me 12 dollars altogether, but I don’t remember how much each person owes me separately.”



“Are the debts in whole dollars?”



“Yes. I do remember that the four other debts multiplied together equals your debt. Do you remember how much you owe me?”



“Yes, but I still haven’t figured out how much each of the other four owe you.”



“Wait! The statistician is the one who owes the least.”



“That does it. Now I know the amount of each debt.”




What are the debts and how did the mathematician determine them?










share|improve this question









New contributor




user13242352 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$
















    6












    $begingroup$


    The accountant complaints to the mathematician:




    “I lent money to five other faculty members and still haven’t been paid back. You are one of them; the other four owe me 12 dollars altogether, but I don’t remember how much each person owes me separately.”



    “Are the debts in whole dollars?”



    “Yes. I do remember that the four other debts multiplied together equals your debt. Do you remember how much you owe me?”



    “Yes, but I still haven’t figured out how much each of the other four owe you.”



    “Wait! The statistician is the one who owes the least.”



    “That does it. Now I know the amount of each debt.”




    What are the debts and how did the mathematician determine them?










    share|improve this question









    New contributor




    user13242352 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      6












      6








      6





      $begingroup$


      The accountant complaints to the mathematician:




      “I lent money to five other faculty members and still haven’t been paid back. You are one of them; the other four owe me 12 dollars altogether, but I don’t remember how much each person owes me separately.”



      “Are the debts in whole dollars?”



      “Yes. I do remember that the four other debts multiplied together equals your debt. Do you remember how much you owe me?”



      “Yes, but I still haven’t figured out how much each of the other four owe you.”



      “Wait! The statistician is the one who owes the least.”



      “That does it. Now I know the amount of each debt.”




      What are the debts and how did the mathematician determine them?










      share|improve this question









      New contributor




      user13242352 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      The accountant complaints to the mathematician:




      “I lent money to five other faculty members and still haven’t been paid back. You are one of them; the other four owe me 12 dollars altogether, but I don’t remember how much each person owes me separately.”



      “Are the debts in whole dollars?”



      “Yes. I do remember that the four other debts multiplied together equals your debt. Do you remember how much you owe me?”



      “Yes, but I still haven’t figured out how much each of the other four owe you.”



      “Wait! The statistician is the one who owes the least.”



      “That does it. Now I know the amount of each debt.”




      What are the debts and how did the mathematician determine them?







      logical-deduction number-theory






      share|improve this question









      New contributor




      user13242352 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question









      New contributor




      user13242352 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.









      share|improve this question




      share|improve this question








      edited 5 hours ago









      Hugh

      2,26811127




      2,26811127






      New contributor




      user13242352 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      asked 5 hours ago









      user13242352user13242352

      392




      392




      New contributor




      user13242352 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.





      New contributor





      user13242352 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.






      user13242352 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




















          2 Answers
          2






          active

          oldest

          votes


















          10












          $begingroup$

          The mathematician owes




          48 dollars




          and the other faculty members owe




          4, 4, 3 and 1 dollar.




          Explanation:




          We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




          Table:




          9 + 1 + 1 + 1 = 12 --> 9
          8 + 2 + 1 + 1 = 12 --> 16
          7 + 3 + 1 + 1 = 12 --> 21
          7 + 2 + 2 + 1 = 12 --> 28
          6 + 4 + 1 + 1 = 12 --> 24
          6 + 3 + 2 + 1 = 12 --> 36
          6 + 2 + 2 + 2 = 12 --> 48
          5 + 5 + 1 + 1 = 12 --> 25
          5 + 4 + 2 + 1 = 12 --> 40
          5 + 3 + 3 + 1 = 12 --> 45
          5 + 3 + 2 + 2 = 12 --> 60
          4 + 4 + 3 + 1 = 12 --> 48
          4 + 4 + 2 + 2 = 12 --> 64
          4 + 3 + 3 + 2 = 12 --> 72
          3 + 3 + 3 + 3 = 12 --> 81

          Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.







          share|improve this answer











          $endgroup$








          • 1




            $begingroup$
            Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
            $endgroup$
            – Kevin
            4 hours ago


















          5












          $begingroup$

          The mathematician owes




          $48




          Because




          nothing is said that the individual debts are unique, only that the lowest one must be.

          So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


          1,2,2,7 → $28

          1,2,3,6 → $36

          1,2,4,5 → $40

          1,3,3,5 → $45

          1,3,4,4 → $48




          Now the mathematician says at first that




          the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


          The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

          The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

          The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

          The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.







          share|improve this answer









          $endgroup$












            Your Answer





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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            10












            $begingroup$

            The mathematician owes




            48 dollars




            and the other faculty members owe




            4, 4, 3 and 1 dollar.




            Explanation:




            We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




            Table:




            9 + 1 + 1 + 1 = 12 --> 9
            8 + 2 + 1 + 1 = 12 --> 16
            7 + 3 + 1 + 1 = 12 --> 21
            7 + 2 + 2 + 1 = 12 --> 28
            6 + 4 + 1 + 1 = 12 --> 24
            6 + 3 + 2 + 1 = 12 --> 36
            6 + 2 + 2 + 2 = 12 --> 48
            5 + 5 + 1 + 1 = 12 --> 25
            5 + 4 + 2 + 1 = 12 --> 40
            5 + 3 + 3 + 1 = 12 --> 45
            5 + 3 + 2 + 2 = 12 --> 60
            4 + 4 + 3 + 1 = 12 --> 48
            4 + 4 + 2 + 2 = 12 --> 64
            4 + 3 + 3 + 2 = 12 --> 72
            3 + 3 + 3 + 3 = 12 --> 81

            Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.







            share|improve this answer











            $endgroup$








            • 1




              $begingroup$
              Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
              $endgroup$
              – Kevin
              4 hours ago















            10












            $begingroup$

            The mathematician owes




            48 dollars




            and the other faculty members owe




            4, 4, 3 and 1 dollar.




            Explanation:




            We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




            Table:




            9 + 1 + 1 + 1 = 12 --> 9
            8 + 2 + 1 + 1 = 12 --> 16
            7 + 3 + 1 + 1 = 12 --> 21
            7 + 2 + 2 + 1 = 12 --> 28
            6 + 4 + 1 + 1 = 12 --> 24
            6 + 3 + 2 + 1 = 12 --> 36
            6 + 2 + 2 + 2 = 12 --> 48
            5 + 5 + 1 + 1 = 12 --> 25
            5 + 4 + 2 + 1 = 12 --> 40
            5 + 3 + 3 + 1 = 12 --> 45
            5 + 3 + 2 + 2 = 12 --> 60
            4 + 4 + 3 + 1 = 12 --> 48
            4 + 4 + 2 + 2 = 12 --> 64
            4 + 3 + 3 + 2 = 12 --> 72
            3 + 3 + 3 + 3 = 12 --> 81

            Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.







            share|improve this answer











            $endgroup$








            • 1




              $begingroup$
              Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
              $endgroup$
              – Kevin
              4 hours ago













            10












            10








            10





            $begingroup$

            The mathematician owes




            48 dollars




            and the other faculty members owe




            4, 4, 3 and 1 dollar.




            Explanation:




            We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




            Table:




            9 + 1 + 1 + 1 = 12 --> 9
            8 + 2 + 1 + 1 = 12 --> 16
            7 + 3 + 1 + 1 = 12 --> 21
            7 + 2 + 2 + 1 = 12 --> 28
            6 + 4 + 1 + 1 = 12 --> 24
            6 + 3 + 2 + 1 = 12 --> 36
            6 + 2 + 2 + 2 = 12 --> 48
            5 + 5 + 1 + 1 = 12 --> 25
            5 + 4 + 2 + 1 = 12 --> 40
            5 + 3 + 3 + 1 = 12 --> 45
            5 + 3 + 2 + 2 = 12 --> 60
            4 + 4 + 3 + 1 = 12 --> 48
            4 + 4 + 2 + 2 = 12 --> 64
            4 + 3 + 3 + 2 = 12 --> 72
            3 + 3 + 3 + 3 = 12 --> 81

            Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.







            share|improve this answer











            $endgroup$



            The mathematician owes




            48 dollars




            and the other faculty members owe




            4, 4, 3 and 1 dollar.




            Explanation:




            We know the total debt of the other four faculty members is 12, so we're looking for partitions of 12 in four parts. Let's list them and compute the product (which would be the mathematician's debt):




            Table:




            9 + 1 + 1 + 1 = 12 --> 9
            8 + 2 + 1 + 1 = 12 --> 16
            7 + 3 + 1 + 1 = 12 --> 21
            7 + 2 + 2 + 1 = 12 --> 28
            6 + 4 + 1 + 1 = 12 --> 24
            6 + 3 + 2 + 1 = 12 --> 36
            6 + 2 + 2 + 2 = 12 --> 48
            5 + 5 + 1 + 1 = 12 --> 25
            5 + 4 + 2 + 1 = 12 --> 40
            5 + 3 + 3 + 1 = 12 --> 45
            5 + 3 + 2 + 2 = 12 --> 60
            4 + 4 + 3 + 1 = 12 --> 48
            4 + 4 + 2 + 2 = 12 --> 64
            4 + 3 + 3 + 2 = 12 --> 72
            3 + 3 + 3 + 3 = 12 --> 81

            Now, the mathematician knows his own debt, so if he's unsure of the distribution of the others, there must be multiple partitions of 12 in four parts with a product equal to his debt. That's only the case for 48, which can be split as $6 times 2 times 2 times 2$ and $4 times 4 times 3 times 1$. Since there is a single least number among those (corresponding to the statistician's debt), it must be the second option.








            share|improve this answer














            share|improve this answer



            share|improve this answer








            edited 1 hour ago









            Yakk

            1706




            1706










            answered 5 hours ago









            GlorfindelGlorfindel

            14k45085




            14k45085







            • 1




              $begingroup$
              Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
              $endgroup$
              – Kevin
              4 hours ago












            • 1




              $begingroup$
              Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
              $endgroup$
              – Kevin
              4 hours ago







            1




            1




            $begingroup$
            Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
            $endgroup$
            – Kevin
            4 hours ago




            $begingroup$
            Your explanation reminds me of the famous Clue scene: youtube.com/watch?v=O5ROhf5Soqs
            $endgroup$
            – Kevin
            4 hours ago











            5












            $begingroup$

            The mathematician owes




            $48




            Because




            nothing is said that the individual debts are unique, only that the lowest one must be.

            So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


            1,2,2,7 → $28

            1,2,3,6 → $36

            1,2,4,5 → $40

            1,3,3,5 → $45

            1,3,4,4 → $48




            Now the mathematician says at first that




            the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


            The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

            The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

            The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

            The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.







            share|improve this answer









            $endgroup$

















              5












              $begingroup$

              The mathematician owes




              $48




              Because




              nothing is said that the individual debts are unique, only that the lowest one must be.

              So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


              1,2,2,7 → $28

              1,2,3,6 → $36

              1,2,4,5 → $40

              1,3,3,5 → $45

              1,3,4,4 → $48




              Now the mathematician says at first that




              the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


              The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

              The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

              The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

              The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.







              share|improve this answer









              $endgroup$















                5












                5








                5





                $begingroup$

                The mathematician owes




                $48




                Because




                nothing is said that the individual debts are unique, only that the lowest one must be.

                So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


                1,2,2,7 → $28

                1,2,3,6 → $36

                1,2,4,5 → $40

                1,3,3,5 → $45

                1,3,4,4 → $48




                Now the mathematician says at first that




                the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


                The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

                The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

                The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

                The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.







                share|improve this answer









                $endgroup$



                The mathematician owes




                $48




                Because




                nothing is said that the individual debts are unique, only that the lowest one must be.

                So any of the following distributions of debts by the four remaining are possible, and thus the following possibilities for what the mathematician owes:


                1,2,2,7 → $28

                1,2,3,6 → $36

                1,2,4,5 → $40

                1,3,3,5 → $45

                1,3,4,4 → $48




                Now the mathematician says at first that




                the other totals are not known to them until the accountant mentions that the statistician owes the least, thus requiring there to be a distinct "least". Prior to that discovery, ...


                The mathematician can't owe $45 because there is only one way to sum to 12 and multiply to 45.

                The mathematician can't owe $36 because there is only one way to sum to 12 and multiply to 36.

                The mathematician can't owe $28 because there is only one way to sum to 12 and multiply to 28.

                The mathematician could owe $48 because 2,2,2,6 is another valid solution that sums to 12 and multiplies to 48, but is ruled out when the discovery is made.








                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 5 hours ago









                RubioRubio

                29.7k566182




                29.7k566182




















                    user13242352 is a new contributor. Be nice, and check out our Code of Conduct.









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                    Старые Смолеговицы Содержание История | География | Демография | Достопримечательности | Примечания | НавигацияHGЯOLHGЯOL41 206 832 01641 606 406 141Административно-территориальное деление Ленинградской области«Переписная оброчная книга Водской пятины 1500 года», С. 793«Карта Ингерманландии: Ивангорода, Яма, Копорья, Нотеборга», по материалам 1676 г.«Генеральная карта провинции Ингерманландии» Э. Белинга и А. Андерсина, 1704 г., составлена по материалам 1678 г.«Географический чертёж над Ижорскою землей со своими городами» Адриана Шонбека 1705 г.Новая и достоверная всей Ингерманландии ланткарта. Грав. А. Ростовцев. СПб., 1727 г.Топографическая карта Санкт-Петербургской губернии. 5-и верстка. Шуберт. 1834 г.Описание Санкт-Петербургской губернии по уездам и станамСпецкарта западной части России Ф. Ф. Шуберта. 1844 г.Алфавитный список селений по уездам и станам С.-Петербургской губернииСписки населённых мест Российской Империи, составленные и издаваемые центральным статистическим комитетом министерства внутренних дел. XXXVII. Санкт-Петербургская губерния. По состоянию на 1862 год. СПб. 1864. С. 203Материалы по статистике народного хозяйства в С.-Петербургской губернии. Вып. IX. Частновладельческое хозяйство в Ямбургском уезде. СПб, 1888, С. 146, С. 2, 7, 54Положение о гербе муниципального образования Курское сельское поселениеСправочник истории административно-территориального деления Ленинградской области.Топографическая карта Ленинградской области, квадрат О-35-23-В (Хотыницы), 1930 г.АрхивированоАдминистративно-территориальное деление Ленинградской области. — Л., 1933, С. 27, 198АрхивированоАдминистративно-экономический справочник по Ленинградской области. — Л., 1936, с. 219АрхивированоАдминистративно-территориальное деление Ленинградской области. — Л., 1966, с. 175АрхивированоАдминистративно-территориальное деление Ленинградской области. — Лениздат, 1973, С. 180АрхивированоАдминистративно-территориальное деление Ленинградской области. — Лениздат, 1990, ISBN 5-289-00612-5, С. 38АрхивированоАдминистративно-территориальное деление Ленинградской области. — СПб., 2007, с. 60АрхивированоКоряков Юрий База данных «Этно-языковой состав населённых пунктов России». Ленинградская область.Административно-территориальное деление Ленинградской области. — СПб, 1997, ISBN 5-86153-055-6, С. 41АрхивированоКультовый комплекс Старые Смолеговицы // Электронная энциклопедия ЭрмитажаПроблемы выявления, изучения и сохранения культовых комплексов с каменными крестами: по материалам работ 2016-2017 гг. в Ленинградской области