Mr. Hilbert and the Problem of the Erroneous Equation
32
$begingroup$
Having had just checked into the Grand Hotel, Mr. Hilbert slumped into the hotel room armchair with relief. Finally he could have some peace and quiet and solve the quaint riddle his colleague gave him! He pulled a note out from his breastpocket, and on it was simply scribbled:
Fix this equation by adding three mathematical symbols:
$$2 spacespacespace 2 space = space9$$
NO letters, numbers, or tampering with the equal sign!
Unfortunately, an hour and thousands of incorrect symbols later, Mr. Hilbert remained hopelessly stuck. Can you help Mr. Hilbert?
mathematics calculation-puzzle construction
edited Sep 2 '15 at 2:52
McMagister
6,84812357
asked Sep 2 '15 at 2:25
HackiisanHackiisan
1,538624
$endgroup$
|
show 4 more comments
32
$begingroup$
Having had just checked into the Grand Hotel, Mr. Hilbert slumped into the hotel room armchair with relief. Finally he could have some peace and quiet and solve the quaint riddle his colleague gave him! He pulled a note out from his breastpocket, and on it was simply scribbled:
Fix this equation by adding three mathematical symbols:
$$2 spacespacespace 2 space = space9$$
NO letters, numbers, or tampering with the equal sign!
Unfortunately, an hour and thousands of incorrect symbols later, Mr. Hilbert remained hopelessly stuck. Can you help Mr. Hilbert?
mathematics calculation-puzzle construction
edited Sep 2 '15 at 2:52
McMagister
6,84812357
asked Sep 2 '15 at 2:25
HackiisanHackiisan
1,538624
$endgroup$
22
$begingroup$
How can Mr. Hilbert spend an hour working on a problem in a hotel? Wouldn't he be requested to move to another room once in every few minutes?
$endgroup$
– JiK
Sep 2 '15 at 9:47
18
$begingroup$
@JiK The front desk was busy trying to complete Mr Gödel's check-in.
$endgroup$
– David Tonhofer
Sep 2 '15 at 20:11
$begingroup$
While the Grand Hotel is large, the occupants move slowly =) Summer is also down season for them I suppose?
$endgroup$
– Hackiisan
Sep 3 '15 at 0:34
$begingroup$
Does2 + 2 <= 9qualify as "tampering with the equal sign"? It's still there, just has a < before it.
$endgroup$
– Darrel Hoffman
Sep 3 '15 at 15:40
$begingroup$
You mean $leq$? =)
$endgroup$
– Hackiisan
Sep 3 '15 at 18:35
|
show 4 more comments
32
32
32
8
$begingroup$
Having had just checked into the Grand Hotel, Mr. Hilbert slumped into the hotel room armchair with relief. Finally he could have some peace and quiet and solve the quaint riddle his colleague gave him! He pulled a note out from his breastpocket, and on it was simply scribbled:
Fix this equation by adding three mathematical symbols:
$$2 spacespacespace 2 space = space9$$
NO letters, numbers, or tampering with the equal sign!
Unfortunately, an hour and thousands of incorrect symbols later, Mr. Hilbert remained hopelessly stuck. Can you help Mr. Hilbert?
mathematics calculation-puzzle construction
edited Sep 2 '15 at 2:52
McMagister
6,84812357
asked Sep 2 '15 at 2:25
HackiisanHackiisan
1,538624
$endgroup$
Having had just checked into the Grand Hotel, Mr. Hilbert slumped into the hotel room armchair with relief. Finally he could have some peace and quiet and solve the quaint riddle his colleague gave him! He pulled a note out from his breastpocket, and on it was simply scribbled:
Fix this equation by adding three mathematical symbols:
$$2 spacespacespace 2 space = space9$$
NO letters, numbers, or tampering with the equal sign!
Unfortunately, an hour and thousands of incorrect symbols later, Mr. Hilbert remained hopelessly stuck. Can you help Mr. Hilbert?
mathematics calculation-puzzle construction
mathematics calculation-puzzle construction
edited Sep 2 '15 at 2:52
McMagister
6,84812357
asked Sep 2 '15 at 2:25
HackiisanHackiisan
1,538624
edited Sep 2 '15 at 2:52
McMagister
6,84812357
asked Sep 2 '15 at 2:25
HackiisanHackiisan
1,538624
edited Sep 2 '15 at 2:52
McMagister
6,84812357
edited Sep 2 '15 at 2:52
McMagister
6,84812357
edited Sep 2 '15 at 2:52
McMagister
6,84812357
6,84812357
asked Sep 2 '15 at 2:25
HackiisanHackiisan
1,538624
asked Sep 2 '15 at 2:25
HackiisanHackiisan
1,538624
asked Sep 2 '15 at 2:25
HackiisanHackiisan
1,538624
1,538624
22
$begingroup$
How can Mr. Hilbert spend an hour working on a problem in a hotel? Wouldn't he be requested to move to another room once in every few minutes?
$endgroup$
– JiK
Sep 2 '15 at 9:47
18
$begingroup$
@JiK The front desk was busy trying to complete Mr Gödel's check-in.
$endgroup$
– David Tonhofer
Sep 2 '15 at 20:11
$begingroup$
While the Grand Hotel is large, the occupants move slowly =) Summer is also down season for them I suppose?
$endgroup$
– Hackiisan
Sep 3 '15 at 0:34
$begingroup$
Does2 + 2 <= 9qualify as "tampering with the equal sign"? It's still there, just has a < before it.
$endgroup$
– Darrel Hoffman
Sep 3 '15 at 15:40
$begingroup$
You mean $leq$? =)
$endgroup$
– Hackiisan
Sep 3 '15 at 18:35
|
show 4 more comments
22
$begingroup$
How can Mr. Hilbert spend an hour working on a problem in a hotel? Wouldn't he be requested to move to another room once in every few minutes?
$endgroup$
– JiK
Sep 2 '15 at 9:47
18
$begingroup$
@JiK The front desk was busy trying to complete Mr Gödel's check-in.
$endgroup$
– David Tonhofer
Sep 2 '15 at 20:11
$begingroup$
While the Grand Hotel is large, the occupants move slowly =) Summer is also down season for them I suppose?
$endgroup$
– Hackiisan
Sep 3 '15 at 0:34
$begingroup$
Does2 + 2 <= 9qualify as "tampering with the equal sign"? It's still there, just has a < before it.
$endgroup$
– Darrel Hoffman
Sep 3 '15 at 15:40
$begingroup$
You mean $leq$? =)
$endgroup$
– Hackiisan
Sep 3 '15 at 18:35
22
22
$begingroup$
How can Mr. Hilbert spend an hour working on a problem in a hotel? Wouldn't he be requested to move to another room once in every few minutes?
$endgroup$
– JiK
Sep 2 '15 at 9:47
$begingroup$
How can Mr. Hilbert spend an hour working on a problem in a hotel? Wouldn't he be requested to move to another room once in every few minutes?
$endgroup$
– JiK
Sep 2 '15 at 9:47
18
18
$begingroup$
@JiK The front desk was busy trying to complete Mr Gödel's check-in.
$endgroup$
– David Tonhofer
Sep 2 '15 at 20:11
$begingroup$
@JiK The front desk was busy trying to complete Mr Gödel's check-in.
$endgroup$
– David Tonhofer
Sep 2 '15 at 20:11
$begingroup$
While the Grand Hotel is large, the occupants move slowly =) Summer is also down season for them I suppose?
$endgroup$
– Hackiisan
Sep 3 '15 at 0:34
$begingroup$
While the Grand Hotel is large, the occupants move slowly =) Summer is also down season for them I suppose?
$endgroup$
– Hackiisan
Sep 3 '15 at 0:34
$begingroup$
Does
2 + 2 <= 9 qualify as "tampering with the equal sign"? It's still there, just has a < before it.$endgroup$
– Darrel Hoffman
Sep 3 '15 at 15:40
$begingroup$
Does
2 + 2 <= 9 qualify as "tampering with the equal sign"? It's still there, just has a < before it.$endgroup$
– Darrel Hoffman
Sep 3 '15 at 15:40
$begingroup$
You mean $leq$? =)
$endgroup$
– Hackiisan
Sep 3 '15 at 18:35
$begingroup$
You mean $leq$? =)
$endgroup$
– Hackiisan
Sep 3 '15 at 18:35
|
show 4 more comments
12 Answers
12
active
oldest
votes
34
$begingroup$
I don't know how to do the formatting (thanks McMagister for the edit) but the answer is
$ 2spacedivspace .overline{2} = 9 $
answered Sep 2 '15 at 3:04
FriedSaucePotsFriedSaucePots
61656
$endgroup$
1
$begingroup$
Beautifully solved.
$endgroup$
– alexmc
Sep 2 '15 at 3:09
28
$begingroup$
That feel when grade school repeated decimal notation is more foreign to me than the gamma function...
$endgroup$
– McMagister
Sep 2 '15 at 3:12
$begingroup$
Well done, much faster than Mr. Hilbert! I had hidden a hint in the story text to be revealed later, but clearly it is unnecessary now =)
$endgroup$
– Hackiisan
Sep 2 '15 at 3:15
$begingroup$
The hint is not so much hidden as I was thinking about it just by reading the title of the question. There is not that many reasons why would one name the usually unnamed (or non-existent) protagonist after a mathematician, besides giving a hint :)
$endgroup$
– zovits
Sep 2 '15 at 9:07
2
$begingroup$
For the uninitiated what does the overbar notation mean? I thought that meant complex conjugate?
$endgroup$
– curious_cat
Sep 2 '15 at 12:21
|
show 2 more comments
24
+100
$begingroup$
$$ 2 div 2 = .overline{9} $$
Simply rearranging the symbols used in the intended solution.
answered Sep 2 '15 at 7:11
GOTO 0GOTO 0
9,85054089
$endgroup$
5
$begingroup$
Nice! Mr. Hilbert agrees this could be a valid solution as well.
$endgroup$
– Hackiisan
Sep 2 '15 at 7:19
add a comment |
17
$begingroup$
Probably fails the no letter criterion.
$-2+2={d over dx} 9$
Or using Lagrange notation as a workaround (thanks to McMagister) we can also write
$-2+2= 9'$
answered Sep 2 '15 at 2:56
RohcanaRohcana
3,4701447
$endgroup$
3
$begingroup$
Use lagrange notation as a work-around?
$endgroup$
– McMagister
Sep 2 '15 at 3:01
4
$begingroup$
Yes. While technically you can use a "prime" symbol for differentiation, the intended answer is not a simple "cheat". Otherwise, most of similar type questions can be solved by the trivial $a' + b' = c' + d'$
$endgroup$
– Hackiisan
Sep 2 '15 at 3:01
add a comment |
14
$begingroup$
I came up with this:
$lceil2sqrt{2}rceil = sqrt{9}$
answered Sep 2 '15 at 16:55
HellionHellion
1,931819
$endgroup$
1
$begingroup$
implicit multiplcation - getting that fourth operation without a fourth math symbol - love it!
$endgroup$
– corsiKa
Sep 3 '15 at 2:00
3
$begingroup$
...And then losing two math symbols on one math operation (ceil), ending up with one symbol too many...
$endgroup$
– namey
Sep 3 '15 at 21:04
add a comment |
7
$begingroup$
My answer:
$$Gamma(2) + 2 = sqrt9$$
answered Sep 2 '15 at 2:41
McMagisterMcMagister
6,84812357
$endgroup$
2
$begingroup$
Very good attempt, but unfortunately Mr. Hilbert would consider the use of the gamma function as "using letters".
$endgroup$
– Hackiisan
Sep 2 '15 at 2:51
4
$begingroup$
Do the brackets count as "mathematical symbols"?
$endgroup$
– alexmc
Sep 2 '15 at 2:53
1
$begingroup$
@alexmc Yes, they do.
$endgroup$
– Hackiisan
Sep 2 '15 at 2:58
add a comment |
5
$begingroup$
Assuming that perfect formatting is not required:
$ neg (2 space 2 = 9) $
That is:
not (twenty-two equals nine)
If we count a pair of parentheses as a single unit, then:
$ neg (2 + 2 = 9) $
answered Sep 2 '15 at 18:09
YpnypnYpnypn
284111
$endgroup$
2
$begingroup$
A solution in the similar vein: $2+2=9tobot$
$endgroup$
– Taemyr
Sep 2 '15 at 19:29
add a comment |
5
$begingroup$
While the accepted answer was also the first one I thought of, there's also a nice solution with subfactorials:
$$2;!2 = !sqrt{9}$$
answered Jan 10 '16 at 21:57
Peter TaylorPeter Taylor
3,9761330
$endgroup$
$begingroup$
What does a factorial sign in front of a number mean in math?
$endgroup$
– user1717828
Jan 10 '16 at 22:26
$begingroup$
@user1717828, see the linked Mathworld page.
$endgroup$
– Peter Taylor
Jan 10 '16 at 22:47
$begingroup$
Didn't see that on mobile. My bad.
$endgroup$
– user1717828
Jan 10 '16 at 23:40
2
$begingroup$
Fascinating. Also $2+!2 = sqrt{9}$.
$endgroup$
– GOTO 0
Jan 12 '16 at 13:29
add a comment |
4
$begingroup$
What about :
$2div2=#{9}$
In case I got the symbols wrong, what I am trying to say is:
two divided by two equals the cardinality of the set of numbers that just contains the number nine
edited Sep 2 '15 at 4:39
GentlePurpleRain♦
17.1k569137
answered Sep 2 '15 at 4:31
KevinKevin
1,634419
$endgroup$
$begingroup$
Nice! While I can't say this is wrong (similar to Anachor's answer), it goes against the spirit of this puzzle by ignoring the value of the number. Otherwise, many other trivial answers exist, such as $(#(2)+2)! = 9$ or $#(2) + 2 = sqrt{9}$. I would have edited the question to reflect this, but the correct solution has already appeared =P
$endgroup$
– Hackiisan
Sep 2 '15 at 7:15
$begingroup$
This solution also uses 4 symbols - not the allowed 3.
$endgroup$
– Eborbob
Sep 2 '15 at 12:50
$begingroup$
@Eborbob Parentheses and brackets are always used a unit and I would consider them to be one symbol. Based on his comments on other answers, Hackiisan seems to agree with me.
$endgroup$
– Kevin
Sep 2 '15 at 13:00
$begingroup$
@Kevin Fair enough, I'll remember that for future use!
$endgroup$
– Eborbob
Sep 2 '15 at 13:04
3
$begingroup$
@Hackiisan $#(2)+2=sqrt{9}$ isn't trivial, and doesn't ignore the value of any number but the first. One could argue the 'accepted' answer ignores the value of one of the numbers, because any two equal numbers will result in an acceptable result.
$endgroup$
– corsiKa
Sep 2 '15 at 16:42
|
show 3 more comments
4
$begingroup$
How about this?
$lfloorsqrt{2}rfloor + 2 = sqrt{9}$
Oops, that is 4 symbols. Thanks @corsiKa.
This one uses three symbols:
$2 - 2 = lfloor9%rfloor$
answered Sep 2 '15 at 14:24
user2023861user2023861
76249
$endgroup$
2
$begingroup$
That's four - floor, sqrt, plus, sqrt
$endgroup$
– corsiKa
Sep 2 '15 at 16:37
add a comment |
2
$begingroup$
How about
$2'cdot 2' = 9$, where $(,cdot,)'$ denotes the successor function.
answered Sep 3 '15 at 12:51
ClaudiusClaudius
1211
$endgroup$
$begingroup$
By that logic, I can always define (⋅)′ to always return 3, irrespective of what is inside. (⋅)′ is not standard notation for the successor function, which means you will have to add letters after these 3 operators to explain what you mean.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:08
$begingroup$
I'm pretty sure that $(,cdot,)'$ is a standard notation for the successor function. At least this is the notation I learned when I was in school. And it is not far fetched to recognise it as such.
$endgroup$
– Claudius
Sep 3 '15 at 13:11
$begingroup$
Can you provide any links to text where such a notation is used? (Hopefully one that isn't too obscure)
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:16
$begingroup$
see this question on math.stackexchange: math.stackexchange.com/questions/643374/… There is a reference to Kleene’s Mathematical Logic that uses this notation.
$endgroup$
– Claudius
Sep 3 '15 at 13:28
$begingroup$
I stand corrected. Although this is not as common as you expect, indicated by the accepted answer in the above question pointing out that S(n) is a more common notation.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:31
add a comment |
2
$begingroup$
If we can assume these digits are measured we get:
2 + √2 = √9 (true to one significant figure)
answered Jan 8 '16 at 7:27
Paul EvansPaul Evans
8,50821946
$endgroup$
add a comment |
2
$begingroup$
With 2 mathematical operations:
$ 2-2={9} $
edited yesterday
PiIsNot3
2,005329
answered yesterday
Artem LuginArtem Lugin
536
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
3
$begingroup$
{} is the fractional part of a number. Clarifying because a set is used in another answer
$endgroup$
– Artem Lugin
yesterday
add a comment |
protected by Aza Sep 3 '15 at 18:46
Thank you for your interest in this question.
Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).
Would you like to answer one of these unanswered questions instead?
12 Answers
12
active
oldest
votes
12 Answers
12
active
oldest
votes
active
oldest
votes
active
oldest
votes
34
$begingroup$
I don't know how to do the formatting (thanks McMagister for the edit) but the answer is
$ 2spacedivspace .overline{2} = 9 $
answered Sep 2 '15 at 3:04
FriedSaucePotsFriedSaucePots
61656
$endgroup$
1
$begingroup$
Beautifully solved.
$endgroup$
– alexmc
Sep 2 '15 at 3:09
28
$begingroup$
That feel when grade school repeated decimal notation is more foreign to me than the gamma function...
$endgroup$
– McMagister
Sep 2 '15 at 3:12
$begingroup$
Well done, much faster than Mr. Hilbert! I had hidden a hint in the story text to be revealed later, but clearly it is unnecessary now =)
$endgroup$
– Hackiisan
Sep 2 '15 at 3:15
$begingroup$
The hint is not so much hidden as I was thinking about it just by reading the title of the question. There is not that many reasons why would one name the usually unnamed (or non-existent) protagonist after a mathematician, besides giving a hint :)
$endgroup$
– zovits
Sep 2 '15 at 9:07
2
$begingroup$
For the uninitiated what does the overbar notation mean? I thought that meant complex conjugate?
$endgroup$
– curious_cat
Sep 2 '15 at 12:21
|
show 2 more comments
34
$begingroup$
I don't know how to do the formatting (thanks McMagister for the edit) but the answer is
$ 2spacedivspace .overline{2} = 9 $
answered Sep 2 '15 at 3:04
FriedSaucePotsFriedSaucePots
61656
$endgroup$
1
$begingroup$
Beautifully solved.
$endgroup$
– alexmc
Sep 2 '15 at 3:09
28
$begingroup$
That feel when grade school repeated decimal notation is more foreign to me than the gamma function...
$endgroup$
– McMagister
Sep 2 '15 at 3:12
$begingroup$
Well done, much faster than Mr. Hilbert! I had hidden a hint in the story text to be revealed later, but clearly it is unnecessary now =)
$endgroup$
– Hackiisan
Sep 2 '15 at 3:15
$begingroup$
The hint is not so much hidden as I was thinking about it just by reading the title of the question. There is not that many reasons why would one name the usually unnamed (or non-existent) protagonist after a mathematician, besides giving a hint :)
$endgroup$
– zovits
Sep 2 '15 at 9:07
2
$begingroup$
For the uninitiated what does the overbar notation mean? I thought that meant complex conjugate?
$endgroup$
– curious_cat
Sep 2 '15 at 12:21
|
show 2 more comments
34
34
34
$begingroup$
I don't know how to do the formatting (thanks McMagister for the edit) but the answer is
$ 2spacedivspace .overline{2} = 9 $
answered Sep 2 '15 at 3:04
FriedSaucePotsFriedSaucePots
61656
$endgroup$
I don't know how to do the formatting (thanks McMagister for the edit) but the answer is
$ 2spacedivspace .overline{2} = 9 $
answered Sep 2 '15 at 3:04
FriedSaucePotsFriedSaucePots
61656
edited Sep 2 '15 at 3:12
answered Sep 2 '15 at 3:04
FriedSaucePotsFriedSaucePots
61656
answered Sep 2 '15 at 3:04
FriedSaucePotsFriedSaucePots
61656
answered Sep 2 '15 at 3:04
FriedSaucePotsFriedSaucePots
61656
61656
1
$begingroup$
Beautifully solved.
$endgroup$
– alexmc
Sep 2 '15 at 3:09
28
$begingroup$
That feel when grade school repeated decimal notation is more foreign to me than the gamma function...
$endgroup$
– McMagister
Sep 2 '15 at 3:12
$begingroup$
Well done, much faster than Mr. Hilbert! I had hidden a hint in the story text to be revealed later, but clearly it is unnecessary now =)
$endgroup$
– Hackiisan
Sep 2 '15 at 3:15
$begingroup$
The hint is not so much hidden as I was thinking about it just by reading the title of the question. There is not that many reasons why would one name the usually unnamed (or non-existent) protagonist after a mathematician, besides giving a hint :)
$endgroup$
– zovits
Sep 2 '15 at 9:07
2
$begingroup$
For the uninitiated what does the overbar notation mean? I thought that meant complex conjugate?
$endgroup$
– curious_cat
Sep 2 '15 at 12:21
|
show 2 more comments
1
$begingroup$
Beautifully solved.
$endgroup$
– alexmc
Sep 2 '15 at 3:09
28
$begingroup$
That feel when grade school repeated decimal notation is more foreign to me than the gamma function...
$endgroup$
– McMagister
Sep 2 '15 at 3:12
$begingroup$
Well done, much faster than Mr. Hilbert! I had hidden a hint in the story text to be revealed later, but clearly it is unnecessary now =)
$endgroup$
– Hackiisan
Sep 2 '15 at 3:15
$begingroup$
The hint is not so much hidden as I was thinking about it just by reading the title of the question. There is not that many reasons why would one name the usually unnamed (or non-existent) protagonist after a mathematician, besides giving a hint :)
$endgroup$
– zovits
Sep 2 '15 at 9:07
2
$begingroup$
For the uninitiated what does the overbar notation mean? I thought that meant complex conjugate?
$endgroup$
– curious_cat
Sep 2 '15 at 12:21
1
1
$begingroup$
Beautifully solved.
$endgroup$
– alexmc
Sep 2 '15 at 3:09
$begingroup$
Beautifully solved.
$endgroup$
– alexmc
Sep 2 '15 at 3:09
28
28
$begingroup$
That feel when grade school repeated decimal notation is more foreign to me than the gamma function...
$endgroup$
– McMagister
Sep 2 '15 at 3:12
$begingroup$
That feel when grade school repeated decimal notation is more foreign to me than the gamma function...
$endgroup$
– McMagister
Sep 2 '15 at 3:12
$begingroup$
Well done, much faster than Mr. Hilbert! I had hidden a hint in the story text to be revealed later, but clearly it is unnecessary now =)
$endgroup$
– Hackiisan
Sep 2 '15 at 3:15
$begingroup$
Well done, much faster than Mr. Hilbert! I had hidden a hint in the story text to be revealed later, but clearly it is unnecessary now =)
$endgroup$
– Hackiisan
Sep 2 '15 at 3:15
$begingroup$
The hint is not so much hidden as I was thinking about it just by reading the title of the question. There is not that many reasons why would one name the usually unnamed (or non-existent) protagonist after a mathematician, besides giving a hint :)
$endgroup$
– zovits
Sep 2 '15 at 9:07
$begingroup$
The hint is not so much hidden as I was thinking about it just by reading the title of the question. There is not that many reasons why would one name the usually unnamed (or non-existent) protagonist after a mathematician, besides giving a hint :)
$endgroup$
– zovits
Sep 2 '15 at 9:07
2
2
$begingroup$
For the uninitiated what does the overbar notation mean? I thought that meant complex conjugate?
$endgroup$
– curious_cat
Sep 2 '15 at 12:21
$begingroup$
For the uninitiated what does the overbar notation mean? I thought that meant complex conjugate?
$endgroup$
– curious_cat
Sep 2 '15 at 12:21
|
show 2 more comments
24
+100
$begingroup$
$$ 2 div 2 = .overline{9} $$
Simply rearranging the symbols used in the intended solution.
answered Sep 2 '15 at 7:11
GOTO 0GOTO 0
9,85054089
$endgroup$
5
$begingroup$
Nice! Mr. Hilbert agrees this could be a valid solution as well.
$endgroup$
– Hackiisan
Sep 2 '15 at 7:19
add a comment |
24
+100
$begingroup$
$$ 2 div 2 = .overline{9} $$
Simply rearranging the symbols used in the intended solution.
answered Sep 2 '15 at 7:11
GOTO 0GOTO 0
9,85054089
$endgroup$
5
$begingroup$
Nice! Mr. Hilbert agrees this could be a valid solution as well.
$endgroup$
– Hackiisan
Sep 2 '15 at 7:19
add a comment |
24
+100
24
+100
24
+100
$begingroup$
$$ 2 div 2 = .overline{9} $$
Simply rearranging the symbols used in the intended solution.
answered Sep 2 '15 at 7:11
GOTO 0GOTO 0
9,85054089
$endgroup$
$$ 2 div 2 = .overline{9} $$
Simply rearranging the symbols used in the intended solution.
answered Sep 2 '15 at 7:11
GOTO 0GOTO 0
9,85054089
answered Sep 2 '15 at 7:11
GOTO 0GOTO 0
9,85054089
answered Sep 2 '15 at 7:11
GOTO 0GOTO 0
9,85054089
answered Sep 2 '15 at 7:11
GOTO 0GOTO 0
9,85054089
9,85054089
5
$begingroup$
Nice! Mr. Hilbert agrees this could be a valid solution as well.
$endgroup$
– Hackiisan
Sep 2 '15 at 7:19
add a comment |
5
$begingroup$
Nice! Mr. Hilbert agrees this could be a valid solution as well.
$endgroup$
– Hackiisan
Sep 2 '15 at 7:19
5
5
$begingroup$
Nice! Mr. Hilbert agrees this could be a valid solution as well.
$endgroup$
– Hackiisan
Sep 2 '15 at 7:19
$begingroup$
Nice! Mr. Hilbert agrees this could be a valid solution as well.
$endgroup$
– Hackiisan
Sep 2 '15 at 7:19
add a comment |
17
$begingroup$
Probably fails the no letter criterion.
$-2+2={d over dx} 9$
Or using Lagrange notation as a workaround (thanks to McMagister) we can also write
$-2+2= 9'$
answered Sep 2 '15 at 2:56
RohcanaRohcana
3,4701447
$endgroup$
3
$begingroup$
Use lagrange notation as a work-around?
$endgroup$
– McMagister
Sep 2 '15 at 3:01
4
$begingroup$
Yes. While technically you can use a "prime" symbol for differentiation, the intended answer is not a simple "cheat". Otherwise, most of similar type questions can be solved by the trivial $a' + b' = c' + d'$
$endgroup$
– Hackiisan
Sep 2 '15 at 3:01
add a comment |
17
$begingroup$
Probably fails the no letter criterion.
$-2+2={d over dx} 9$
Or using Lagrange notation as a workaround (thanks to McMagister) we can also write
$-2+2= 9'$
answered Sep 2 '15 at 2:56
RohcanaRohcana
3,4701447
$endgroup$
3
$begingroup$
Use lagrange notation as a work-around?
$endgroup$
– McMagister
Sep 2 '15 at 3:01
4
$begingroup$
Yes. While technically you can use a "prime" symbol for differentiation, the intended answer is not a simple "cheat". Otherwise, most of similar type questions can be solved by the trivial $a' + b' = c' + d'$
$endgroup$
– Hackiisan
Sep 2 '15 at 3:01
add a comment |
17
17
17
$begingroup$
Probably fails the no letter criterion.
$-2+2={d over dx} 9$
Or using Lagrange notation as a workaround (thanks to McMagister) we can also write
$-2+2= 9'$
answered Sep 2 '15 at 2:56
RohcanaRohcana
3,4701447
$endgroup$
Probably fails the no letter criterion.
$-2+2={d over dx} 9$
Or using Lagrange notation as a workaround (thanks to McMagister) we can also write
$-2+2= 9'$
answered Sep 2 '15 at 2:56
RohcanaRohcana
3,4701447
edited Sep 2 '15 at 3:13
answered Sep 2 '15 at 2:56
RohcanaRohcana
3,4701447
answered Sep 2 '15 at 2:56
RohcanaRohcana
3,4701447
answered Sep 2 '15 at 2:56
RohcanaRohcana
3,4701447
3,4701447
3
$begingroup$
Use lagrange notation as a work-around?
$endgroup$
– McMagister
Sep 2 '15 at 3:01
4
$begingroup$
Yes. While technically you can use a "prime" symbol for differentiation, the intended answer is not a simple "cheat". Otherwise, most of similar type questions can be solved by the trivial $a' + b' = c' + d'$
$endgroup$
– Hackiisan
Sep 2 '15 at 3:01
add a comment |
3
$begingroup$
Use lagrange notation as a work-around?
$endgroup$
– McMagister
Sep 2 '15 at 3:01
4
$begingroup$
Yes. While technically you can use a "prime" symbol for differentiation, the intended answer is not a simple "cheat". Otherwise, most of similar type questions can be solved by the trivial $a' + b' = c' + d'$
$endgroup$
– Hackiisan
Sep 2 '15 at 3:01
3
3
$begingroup$
Use lagrange notation as a work-around?
$endgroup$
– McMagister
Sep 2 '15 at 3:01
$begingroup$
Use lagrange notation as a work-around?
$endgroup$
– McMagister
Sep 2 '15 at 3:01
4
4
$begingroup$
Yes. While technically you can use a "prime" symbol for differentiation, the intended answer is not a simple "cheat". Otherwise, most of similar type questions can be solved by the trivial $a' + b' = c' + d'$
$endgroup$
– Hackiisan
Sep 2 '15 at 3:01
$begingroup$
Yes. While technically you can use a "prime" symbol for differentiation, the intended answer is not a simple "cheat". Otherwise, most of similar type questions can be solved by the trivial $a' + b' = c' + d'$
$endgroup$
– Hackiisan
Sep 2 '15 at 3:01
add a comment |
14
$begingroup$
I came up with this:
$lceil2sqrt{2}rceil = sqrt{9}$
answered Sep 2 '15 at 16:55
HellionHellion
1,931819
$endgroup$
1
$begingroup$
implicit multiplcation - getting that fourth operation without a fourth math symbol - love it!
$endgroup$
– corsiKa
Sep 3 '15 at 2:00
3
$begingroup$
...And then losing two math symbols on one math operation (ceil), ending up with one symbol too many...
$endgroup$
– namey
Sep 3 '15 at 21:04
add a comment |
14
$begingroup$
I came up with this:
$lceil2sqrt{2}rceil = sqrt{9}$
answered Sep 2 '15 at 16:55
HellionHellion
1,931819
$endgroup$
1
$begingroup$
implicit multiplcation - getting that fourth operation without a fourth math symbol - love it!
$endgroup$
– corsiKa
Sep 3 '15 at 2:00
3
$begingroup$
...And then losing two math symbols on one math operation (ceil), ending up with one symbol too many...
$endgroup$
– namey
Sep 3 '15 at 21:04
add a comment |
14
14
14
$begingroup$
I came up with this:
$lceil2sqrt{2}rceil = sqrt{9}$
answered Sep 2 '15 at 16:55
HellionHellion
1,931819
$endgroup$
I came up with this:
$lceil2sqrt{2}rceil = sqrt{9}$
answered Sep 2 '15 at 16:55
HellionHellion
1,931819
answered Sep 2 '15 at 16:55
HellionHellion
1,931819
answered Sep 2 '15 at 16:55
HellionHellion
1,931819
answered Sep 2 '15 at 16:55
HellionHellion
1,931819
1,931819
1
$begingroup$
implicit multiplcation - getting that fourth operation without a fourth math symbol - love it!
$endgroup$
– corsiKa
Sep 3 '15 at 2:00
3
$begingroup$
...And then losing two math symbols on one math operation (ceil), ending up with one symbol too many...
$endgroup$
– namey
Sep 3 '15 at 21:04
add a comment |
1
$begingroup$
implicit multiplcation - getting that fourth operation without a fourth math symbol - love it!
$endgroup$
– corsiKa
Sep 3 '15 at 2:00
3
$begingroup$
...And then losing two math symbols on one math operation (ceil), ending up with one symbol too many...
$endgroup$
– namey
Sep 3 '15 at 21:04
1
1
$begingroup$
implicit multiplcation - getting that fourth operation without a fourth math symbol - love it!
$endgroup$
– corsiKa
Sep 3 '15 at 2:00
$begingroup$
implicit multiplcation - getting that fourth operation without a fourth math symbol - love it!
$endgroup$
– corsiKa
Sep 3 '15 at 2:00
3
3
$begingroup$
...And then losing two math symbols on one math operation (ceil), ending up with one symbol too many...
$endgroup$
– namey
Sep 3 '15 at 21:04
$begingroup$
...And then losing two math symbols on one math operation (ceil), ending up with one symbol too many...
$endgroup$
– namey
Sep 3 '15 at 21:04
add a comment |
7
$begingroup$
My answer:
$$Gamma(2) + 2 = sqrt9$$
answered Sep 2 '15 at 2:41
McMagisterMcMagister
6,84812357
$endgroup$
2
$begingroup$
Very good attempt, but unfortunately Mr. Hilbert would consider the use of the gamma function as "using letters".
$endgroup$
– Hackiisan
Sep 2 '15 at 2:51
4
$begingroup$
Do the brackets count as "mathematical symbols"?
$endgroup$
– alexmc
Sep 2 '15 at 2:53
1
$begingroup$
@alexmc Yes, they do.
$endgroup$
– Hackiisan
Sep 2 '15 at 2:58
add a comment |
7
$begingroup$
My answer:
$$Gamma(2) + 2 = sqrt9$$
answered Sep 2 '15 at 2:41
McMagisterMcMagister
6,84812357
$endgroup$
2
$begingroup$
Very good attempt, but unfortunately Mr. Hilbert would consider the use of the gamma function as "using letters".
$endgroup$
– Hackiisan
Sep 2 '15 at 2:51
4
$begingroup$
Do the brackets count as "mathematical symbols"?
$endgroup$
– alexmc
Sep 2 '15 at 2:53
1
$begingroup$
@alexmc Yes, they do.
$endgroup$
– Hackiisan
Sep 2 '15 at 2:58
add a comment |
7
7
7
$begingroup$
My answer:
$$Gamma(2) + 2 = sqrt9$$
answered Sep 2 '15 at 2:41
McMagisterMcMagister
6,84812357
$endgroup$
My answer:
$$Gamma(2) + 2 = sqrt9$$
answered Sep 2 '15 at 2:41
McMagisterMcMagister
6,84812357
edited Sep 2 '15 at 2:48
answered Sep 2 '15 at 2:41
McMagisterMcMagister
6,84812357
answered Sep 2 '15 at 2:41
McMagisterMcMagister
6,84812357
answered Sep 2 '15 at 2:41
McMagisterMcMagister
6,84812357
6,84812357
2
$begingroup$
Very good attempt, but unfortunately Mr. Hilbert would consider the use of the gamma function as "using letters".
$endgroup$
– Hackiisan
Sep 2 '15 at 2:51
4
$begingroup$
Do the brackets count as "mathematical symbols"?
$endgroup$
– alexmc
Sep 2 '15 at 2:53
1
$begingroup$
@alexmc Yes, they do.
$endgroup$
– Hackiisan
Sep 2 '15 at 2:58
add a comment |
2
$begingroup$
Very good attempt, but unfortunately Mr. Hilbert would consider the use of the gamma function as "using letters".
$endgroup$
– Hackiisan
Sep 2 '15 at 2:51
4
$begingroup$
Do the brackets count as "mathematical symbols"?
$endgroup$
– alexmc
Sep 2 '15 at 2:53
1
$begingroup$
@alexmc Yes, they do.
$endgroup$
– Hackiisan
Sep 2 '15 at 2:58
2
2
$begingroup$
Very good attempt, but unfortunately Mr. Hilbert would consider the use of the gamma function as "using letters".
$endgroup$
– Hackiisan
Sep 2 '15 at 2:51
$begingroup$
Very good attempt, but unfortunately Mr. Hilbert would consider the use of the gamma function as "using letters".
$endgroup$
– Hackiisan
Sep 2 '15 at 2:51
4
4
$begingroup$
Do the brackets count as "mathematical symbols"?
$endgroup$
– alexmc
Sep 2 '15 at 2:53
$begingroup$
Do the brackets count as "mathematical symbols"?
$endgroup$
– alexmc
Sep 2 '15 at 2:53
1
1
$begingroup$
@alexmc Yes, they do.
$endgroup$
– Hackiisan
Sep 2 '15 at 2:58
$begingroup$
@alexmc Yes, they do.
$endgroup$
– Hackiisan
Sep 2 '15 at 2:58
add a comment |
5
$begingroup$
Assuming that perfect formatting is not required:
$ neg (2 space 2 = 9) $
That is:
not (twenty-two equals nine)
If we count a pair of parentheses as a single unit, then:
$ neg (2 + 2 = 9) $
answered Sep 2 '15 at 18:09
YpnypnYpnypn
284111
$endgroup$
2
$begingroup$
A solution in the similar vein: $2+2=9tobot$
$endgroup$
– Taemyr
Sep 2 '15 at 19:29
add a comment |
5
$begingroup$
Assuming that perfect formatting is not required:
$ neg (2 space 2 = 9) $
That is:
not (twenty-two equals nine)
If we count a pair of parentheses as a single unit, then:
$ neg (2 + 2 = 9) $
answered Sep 2 '15 at 18:09
YpnypnYpnypn
284111
$endgroup$
2
$begingroup$
A solution in the similar vein: $2+2=9tobot$
$endgroup$
– Taemyr
Sep 2 '15 at 19:29
add a comment |
5
5
5
$begingroup$
Assuming that perfect formatting is not required:
$ neg (2 space 2 = 9) $
That is:
not (twenty-two equals nine)
If we count a pair of parentheses as a single unit, then:
$ neg (2 + 2 = 9) $
answered Sep 2 '15 at 18:09
YpnypnYpnypn
284111
$endgroup$
Assuming that perfect formatting is not required:
$ neg (2 space 2 = 9) $
That is:
not (twenty-two equals nine)
If we count a pair of parentheses as a single unit, then:
$ neg (2 + 2 = 9) $
answered Sep 2 '15 at 18:09
YpnypnYpnypn
284111
answered Sep 2 '15 at 18:09
YpnypnYpnypn
284111
answered Sep 2 '15 at 18:09
YpnypnYpnypn
284111
answered Sep 2 '15 at 18:09
YpnypnYpnypn
284111
284111
2
$begingroup$
A solution in the similar vein: $2+2=9tobot$
$endgroup$
– Taemyr
Sep 2 '15 at 19:29
add a comment |
2
$begingroup$
A solution in the similar vein: $2+2=9tobot$
$endgroup$
– Taemyr
Sep 2 '15 at 19:29
2
2
$begingroup$
A solution in the similar vein: $2+2=9tobot$
$endgroup$
– Taemyr
Sep 2 '15 at 19:29
$begingroup$
A solution in the similar vein: $2+2=9tobot$
$endgroup$
– Taemyr
Sep 2 '15 at 19:29
add a comment |
5
$begingroup$
While the accepted answer was also the first one I thought of, there's also a nice solution with subfactorials:
$$2;!2 = !sqrt{9}$$
answered Jan 10 '16 at 21:57
Peter TaylorPeter Taylor
3,9761330
$endgroup$
$begingroup$
What does a factorial sign in front of a number mean in math?
$endgroup$
– user1717828
Jan 10 '16 at 22:26
$begingroup$
@user1717828, see the linked Mathworld page.
$endgroup$
– Peter Taylor
Jan 10 '16 at 22:47
$begingroup$
Didn't see that on mobile. My bad.
$endgroup$
– user1717828
Jan 10 '16 at 23:40
2
$begingroup$
Fascinating. Also $2+!2 = sqrt{9}$.
$endgroup$
– GOTO 0
Jan 12 '16 at 13:29
add a comment |
5
$begingroup$
While the accepted answer was also the first one I thought of, there's also a nice solution with subfactorials:
$$2;!2 = !sqrt{9}$$
answered Jan 10 '16 at 21:57
Peter TaylorPeter Taylor
3,9761330
$endgroup$
$begingroup$
What does a factorial sign in front of a number mean in math?
$endgroup$
– user1717828
Jan 10 '16 at 22:26
$begingroup$
@user1717828, see the linked Mathworld page.
$endgroup$
– Peter Taylor
Jan 10 '16 at 22:47
$begingroup$
Didn't see that on mobile. My bad.
$endgroup$
– user1717828
Jan 10 '16 at 23:40
2
$begingroup$
Fascinating. Also $2+!2 = sqrt{9}$.
$endgroup$
– GOTO 0
Jan 12 '16 at 13:29
add a comment |
5
5
5
$begingroup$
While the accepted answer was also the first one I thought of, there's also a nice solution with subfactorials:
$$2;!2 = !sqrt{9}$$
answered Jan 10 '16 at 21:57
Peter TaylorPeter Taylor
3,9761330
$endgroup$
While the accepted answer was also the first one I thought of, there's also a nice solution with subfactorials:
$$2;!2 = !sqrt{9}$$
answered Jan 10 '16 at 21:57
Peter TaylorPeter Taylor
3,9761330
answered Jan 10 '16 at 21:57
Peter TaylorPeter Taylor
3,9761330
answered Jan 10 '16 at 21:57
Peter TaylorPeter Taylor
3,9761330
answered Jan 10 '16 at 21:57
Peter TaylorPeter Taylor
3,9761330
3,9761330
$begingroup$
What does a factorial sign in front of a number mean in math?
$endgroup$
– user1717828
Jan 10 '16 at 22:26
$begingroup$
@user1717828, see the linked Mathworld page.
$endgroup$
– Peter Taylor
Jan 10 '16 at 22:47
$begingroup$
Didn't see that on mobile. My bad.
$endgroup$
– user1717828
Jan 10 '16 at 23:40
2
$begingroup$
Fascinating. Also $2+!2 = sqrt{9}$.
$endgroup$
– GOTO 0
Jan 12 '16 at 13:29
add a comment |
$begingroup$
What does a factorial sign in front of a number mean in math?
$endgroup$
– user1717828
Jan 10 '16 at 22:26
$begingroup$
@user1717828, see the linked Mathworld page.
$endgroup$
– Peter Taylor
Jan 10 '16 at 22:47
$begingroup$
Didn't see that on mobile. My bad.
$endgroup$
– user1717828
Jan 10 '16 at 23:40
2
$begingroup$
Fascinating. Also $2+!2 = sqrt{9}$.
$endgroup$
– GOTO 0
Jan 12 '16 at 13:29
$begingroup$
What does a factorial sign in front of a number mean in math?
$endgroup$
– user1717828
Jan 10 '16 at 22:26
$begingroup$
What does a factorial sign in front of a number mean in math?
$endgroup$
– user1717828
Jan 10 '16 at 22:26
$begingroup$
@user1717828, see the linked Mathworld page.
$endgroup$
– Peter Taylor
Jan 10 '16 at 22:47
$begingroup$
@user1717828, see the linked Mathworld page.
$endgroup$
– Peter Taylor
Jan 10 '16 at 22:47
$begingroup$
Didn't see that on mobile. My bad.
$endgroup$
– user1717828
Jan 10 '16 at 23:40
$begingroup$
Didn't see that on mobile. My bad.
$endgroup$
– user1717828
Jan 10 '16 at 23:40
2
2
$begingroup$
Fascinating. Also $2+!2 = sqrt{9}$.
$endgroup$
– GOTO 0
Jan 12 '16 at 13:29
$begingroup$
Fascinating. Also $2+!2 = sqrt{9}$.
$endgroup$
– GOTO 0
Jan 12 '16 at 13:29
add a comment |
4
$begingroup$
What about :
$2div2=#{9}$
In case I got the symbols wrong, what I am trying to say is:
two divided by two equals the cardinality of the set of numbers that just contains the number nine
edited Sep 2 '15 at 4:39
GentlePurpleRain♦
17.1k569137
answered Sep 2 '15 at 4:31
KevinKevin
1,634419
$endgroup$
$begingroup$
Nice! While I can't say this is wrong (similar to Anachor's answer), it goes against the spirit of this puzzle by ignoring the value of the number. Otherwise, many other trivial answers exist, such as $(#(2)+2)! = 9$ or $#(2) + 2 = sqrt{9}$. I would have edited the question to reflect this, but the correct solution has already appeared =P
$endgroup$
– Hackiisan
Sep 2 '15 at 7:15
$begingroup$
This solution also uses 4 symbols - not the allowed 3.
$endgroup$
– Eborbob
Sep 2 '15 at 12:50
$begingroup$
@Eborbob Parentheses and brackets are always used a unit and I would consider them to be one symbol. Based on his comments on other answers, Hackiisan seems to agree with me.
$endgroup$
– Kevin
Sep 2 '15 at 13:00
$begingroup$
@Kevin Fair enough, I'll remember that for future use!
$endgroup$
– Eborbob
Sep 2 '15 at 13:04
3
$begingroup$
@Hackiisan $#(2)+2=sqrt{9}$ isn't trivial, and doesn't ignore the value of any number but the first. One could argue the 'accepted' answer ignores the value of one of the numbers, because any two equal numbers will result in an acceptable result.
$endgroup$
– corsiKa
Sep 2 '15 at 16:42
|
show 3 more comments
4
$begingroup$
What about :
$2div2=#{9}$
In case I got the symbols wrong, what I am trying to say is:
two divided by two equals the cardinality of the set of numbers that just contains the number nine
edited Sep 2 '15 at 4:39
GentlePurpleRain♦
17.1k569137
answered Sep 2 '15 at 4:31
KevinKevin
1,634419
$endgroup$
$begingroup$
Nice! While I can't say this is wrong (similar to Anachor's answer), it goes against the spirit of this puzzle by ignoring the value of the number. Otherwise, many other trivial answers exist, such as $(#(2)+2)! = 9$ or $#(2) + 2 = sqrt{9}$. I would have edited the question to reflect this, but the correct solution has already appeared =P
$endgroup$
– Hackiisan
Sep 2 '15 at 7:15
$begingroup$
This solution also uses 4 symbols - not the allowed 3.
$endgroup$
– Eborbob
Sep 2 '15 at 12:50
$begingroup$
@Eborbob Parentheses and brackets are always used a unit and I would consider them to be one symbol. Based on his comments on other answers, Hackiisan seems to agree with me.
$endgroup$
– Kevin
Sep 2 '15 at 13:00
$begingroup$
@Kevin Fair enough, I'll remember that for future use!
$endgroup$
– Eborbob
Sep 2 '15 at 13:04
3
$begingroup$
@Hackiisan $#(2)+2=sqrt{9}$ isn't trivial, and doesn't ignore the value of any number but the first. One could argue the 'accepted' answer ignores the value of one of the numbers, because any two equal numbers will result in an acceptable result.
$endgroup$
– corsiKa
Sep 2 '15 at 16:42
|
show 3 more comments
4
4
4
$begingroup$
What about :
$2div2=#{9}$
In case I got the symbols wrong, what I am trying to say is:
two divided by two equals the cardinality of the set of numbers that just contains the number nine
edited Sep 2 '15 at 4:39
GentlePurpleRain♦
17.1k569137
answered Sep 2 '15 at 4:31
KevinKevin
1,634419
$endgroup$
What about :
$2div2=#{9}$
In case I got the symbols wrong, what I am trying to say is:
two divided by two equals the cardinality of the set of numbers that just contains the number nine
edited Sep 2 '15 at 4:39
GentlePurpleRain♦
17.1k569137
answered Sep 2 '15 at 4:31
KevinKevin
1,634419
edited Sep 2 '15 at 4:39
GentlePurpleRain♦
17.1k569137
edited Sep 2 '15 at 4:39
GentlePurpleRain♦
17.1k569137
edited Sep 2 '15 at 4:39
GentlePurpleRain♦
17.1k569137
17.1k569137
answered Sep 2 '15 at 4:31
KevinKevin
1,634419
answered Sep 2 '15 at 4:31
KevinKevin
1,634419
answered Sep 2 '15 at 4:31
KevinKevin
1,634419
1,634419
$begingroup$
Nice! While I can't say this is wrong (similar to Anachor's answer), it goes against the spirit of this puzzle by ignoring the value of the number. Otherwise, many other trivial answers exist, such as $(#(2)+2)! = 9$ or $#(2) + 2 = sqrt{9}$. I would have edited the question to reflect this, but the correct solution has already appeared =P
$endgroup$
– Hackiisan
Sep 2 '15 at 7:15
$begingroup$
This solution also uses 4 symbols - not the allowed 3.
$endgroup$
– Eborbob
Sep 2 '15 at 12:50
$begingroup$
@Eborbob Parentheses and brackets are always used a unit and I would consider them to be one symbol. Based on his comments on other answers, Hackiisan seems to agree with me.
$endgroup$
– Kevin
Sep 2 '15 at 13:00
$begingroup$
@Kevin Fair enough, I'll remember that for future use!
$endgroup$
– Eborbob
Sep 2 '15 at 13:04
3
$begingroup$
@Hackiisan $#(2)+2=sqrt{9}$ isn't trivial, and doesn't ignore the value of any number but the first. One could argue the 'accepted' answer ignores the value of one of the numbers, because any two equal numbers will result in an acceptable result.
$endgroup$
– corsiKa
Sep 2 '15 at 16:42
|
show 3 more comments
$begingroup$
Nice! While I can't say this is wrong (similar to Anachor's answer), it goes against the spirit of this puzzle by ignoring the value of the number. Otherwise, many other trivial answers exist, such as $(#(2)+2)! = 9$ or $#(2) + 2 = sqrt{9}$. I would have edited the question to reflect this, but the correct solution has already appeared =P
$endgroup$
– Hackiisan
Sep 2 '15 at 7:15
$begingroup$
This solution also uses 4 symbols - not the allowed 3.
$endgroup$
– Eborbob
Sep 2 '15 at 12:50
$begingroup$
@Eborbob Parentheses and brackets are always used a unit and I would consider them to be one symbol. Based on his comments on other answers, Hackiisan seems to agree with me.
$endgroup$
– Kevin
Sep 2 '15 at 13:00
$begingroup$
@Kevin Fair enough, I'll remember that for future use!
$endgroup$
– Eborbob
Sep 2 '15 at 13:04
3
$begingroup$
@Hackiisan $#(2)+2=sqrt{9}$ isn't trivial, and doesn't ignore the value of any number but the first. One could argue the 'accepted' answer ignores the value of one of the numbers, because any two equal numbers will result in an acceptable result.
$endgroup$
– corsiKa
Sep 2 '15 at 16:42
$begingroup$
Nice! While I can't say this is wrong (similar to Anachor's answer), it goes against the spirit of this puzzle by ignoring the value of the number. Otherwise, many other trivial answers exist, such as $(#(2)+2)! = 9$ or $#(2) + 2 = sqrt{9}$. I would have edited the question to reflect this, but the correct solution has already appeared =P
$endgroup$
– Hackiisan
Sep 2 '15 at 7:15
$begingroup$
Nice! While I can't say this is wrong (similar to Anachor's answer), it goes against the spirit of this puzzle by ignoring the value of the number. Otherwise, many other trivial answers exist, such as $(#(2)+2)! = 9$ or $#(2) + 2 = sqrt{9}$. I would have edited the question to reflect this, but the correct solution has already appeared =P
$endgroup$
– Hackiisan
Sep 2 '15 at 7:15
$begingroup$
This solution also uses 4 symbols - not the allowed 3.
$endgroup$
– Eborbob
Sep 2 '15 at 12:50
$begingroup$
This solution also uses 4 symbols - not the allowed 3.
$endgroup$
– Eborbob
Sep 2 '15 at 12:50
$begingroup$
@Eborbob Parentheses and brackets are always used a unit and I would consider them to be one symbol. Based on his comments on other answers, Hackiisan seems to agree with me.
$endgroup$
– Kevin
Sep 2 '15 at 13:00
$begingroup$
@Eborbob Parentheses and brackets are always used a unit and I would consider them to be one symbol. Based on his comments on other answers, Hackiisan seems to agree with me.
$endgroup$
– Kevin
Sep 2 '15 at 13:00
$begingroup$
@Kevin Fair enough, I'll remember that for future use!
$endgroup$
– Eborbob
Sep 2 '15 at 13:04
$begingroup$
@Kevin Fair enough, I'll remember that for future use!
$endgroup$
– Eborbob
Sep 2 '15 at 13:04
3
3
$begingroup$
@Hackiisan $#(2)+2=sqrt{9}$ isn't trivial, and doesn't ignore the value of any number but the first. One could argue the 'accepted' answer ignores the value of one of the numbers, because any two equal numbers will result in an acceptable result.
$endgroup$
– corsiKa
Sep 2 '15 at 16:42
$begingroup$
@Hackiisan $#(2)+2=sqrt{9}$ isn't trivial, and doesn't ignore the value of any number but the first. One could argue the 'accepted' answer ignores the value of one of the numbers, because any two equal numbers will result in an acceptable result.
$endgroup$
– corsiKa
Sep 2 '15 at 16:42
|
show 3 more comments
4
$begingroup$
How about this?
$lfloorsqrt{2}rfloor + 2 = sqrt{9}$
Oops, that is 4 symbols. Thanks @corsiKa.
This one uses three symbols:
$2 - 2 = lfloor9%rfloor$
answered Sep 2 '15 at 14:24
user2023861user2023861
76249
$endgroup$
2
$begingroup$
That's four - floor, sqrt, plus, sqrt
$endgroup$
– corsiKa
Sep 2 '15 at 16:37
add a comment |
4
$begingroup$
How about this?
$lfloorsqrt{2}rfloor + 2 = sqrt{9}$
Oops, that is 4 symbols. Thanks @corsiKa.
This one uses three symbols:
$2 - 2 = lfloor9%rfloor$
answered Sep 2 '15 at 14:24
user2023861user2023861
76249
$endgroup$
2
$begingroup$
That's four - floor, sqrt, plus, sqrt
$endgroup$
– corsiKa
Sep 2 '15 at 16:37
add a comment |
4
4
4
$begingroup$
How about this?
$lfloorsqrt{2}rfloor + 2 = sqrt{9}$
Oops, that is 4 symbols. Thanks @corsiKa.
This one uses three symbols:
$2 - 2 = lfloor9%rfloor$
answered Sep 2 '15 at 14:24
user2023861user2023861
76249
$endgroup$
How about this?
$lfloorsqrt{2}rfloor + 2 = sqrt{9}$
Oops, that is 4 symbols. Thanks @corsiKa.
This one uses three symbols:
$2 - 2 = lfloor9%rfloor$
answered Sep 2 '15 at 14:24
user2023861user2023861
76249
edited Sep 2 '15 at 17:24
answered Sep 2 '15 at 14:24
user2023861user2023861
76249
answered Sep 2 '15 at 14:24
user2023861user2023861
76249
answered Sep 2 '15 at 14:24
user2023861user2023861
76249
76249
2
$begingroup$
That's four - floor, sqrt, plus, sqrt
$endgroup$
– corsiKa
Sep 2 '15 at 16:37
add a comment |
2
$begingroup$
That's four - floor, sqrt, plus, sqrt
$endgroup$
– corsiKa
Sep 2 '15 at 16:37
2
2
$begingroup$
That's four - floor, sqrt, plus, sqrt
$endgroup$
– corsiKa
Sep 2 '15 at 16:37
$begingroup$
That's four - floor, sqrt, plus, sqrt
$endgroup$
– corsiKa
Sep 2 '15 at 16:37
add a comment |
2
$begingroup$
How about
$2'cdot 2' = 9$, where $(,cdot,)'$ denotes the successor function.
answered Sep 3 '15 at 12:51
ClaudiusClaudius
1211
$endgroup$
$begingroup$
By that logic, I can always define (⋅)′ to always return 3, irrespective of what is inside. (⋅)′ is not standard notation for the successor function, which means you will have to add letters after these 3 operators to explain what you mean.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:08
$begingroup$
I'm pretty sure that $(,cdot,)'$ is a standard notation for the successor function. At least this is the notation I learned when I was in school. And it is not far fetched to recognise it as such.
$endgroup$
– Claudius
Sep 3 '15 at 13:11
$begingroup$
Can you provide any links to text where such a notation is used? (Hopefully one that isn't too obscure)
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:16
$begingroup$
see this question on math.stackexchange: math.stackexchange.com/questions/643374/… There is a reference to Kleene’s Mathematical Logic that uses this notation.
$endgroup$
– Claudius
Sep 3 '15 at 13:28
$begingroup$
I stand corrected. Although this is not as common as you expect, indicated by the accepted answer in the above question pointing out that S(n) is a more common notation.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:31
add a comment |
2
$begingroup$
How about
$2'cdot 2' = 9$, where $(,cdot,)'$ denotes the successor function.
answered Sep 3 '15 at 12:51
ClaudiusClaudius
1211
$endgroup$
$begingroup$
By that logic, I can always define (⋅)′ to always return 3, irrespective of what is inside. (⋅)′ is not standard notation for the successor function, which means you will have to add letters after these 3 operators to explain what you mean.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:08
$begingroup$
I'm pretty sure that $(,cdot,)'$ is a standard notation for the successor function. At least this is the notation I learned when I was in school. And it is not far fetched to recognise it as such.
$endgroup$
– Claudius
Sep 3 '15 at 13:11
$begingroup$
Can you provide any links to text where such a notation is used? (Hopefully one that isn't too obscure)
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:16
$begingroup$
see this question on math.stackexchange: math.stackexchange.com/questions/643374/… There is a reference to Kleene’s Mathematical Logic that uses this notation.
$endgroup$
– Claudius
Sep 3 '15 at 13:28
$begingroup$
I stand corrected. Although this is not as common as you expect, indicated by the accepted answer in the above question pointing out that S(n) is a more common notation.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:31
add a comment |
2
2
2
$begingroup$
How about
$2'cdot 2' = 9$, where $(,cdot,)'$ denotes the successor function.
answered Sep 3 '15 at 12:51
ClaudiusClaudius
1211
$endgroup$
How about
$2'cdot 2' = 9$, where $(,cdot,)'$ denotes the successor function.
answered Sep 3 '15 at 12:51
ClaudiusClaudius
1211
answered Sep 3 '15 at 12:51
ClaudiusClaudius
1211
answered Sep 3 '15 at 12:51
ClaudiusClaudius
1211
answered Sep 3 '15 at 12:51
ClaudiusClaudius
1211
1211
$begingroup$
By that logic, I can always define (⋅)′ to always return 3, irrespective of what is inside. (⋅)′ is not standard notation for the successor function, which means you will have to add letters after these 3 operators to explain what you mean.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:08
$begingroup$
I'm pretty sure that $(,cdot,)'$ is a standard notation for the successor function. At least this is the notation I learned when I was in school. And it is not far fetched to recognise it as such.
$endgroup$
– Claudius
Sep 3 '15 at 13:11
$begingroup$
Can you provide any links to text where such a notation is used? (Hopefully one that isn't too obscure)
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:16
$begingroup$
see this question on math.stackexchange: math.stackexchange.com/questions/643374/… There is a reference to Kleene’s Mathematical Logic that uses this notation.
$endgroup$
– Claudius
Sep 3 '15 at 13:28
$begingroup$
I stand corrected. Although this is not as common as you expect, indicated by the accepted answer in the above question pointing out that S(n) is a more common notation.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:31
add a comment |
$begingroup$
By that logic, I can always define (⋅)′ to always return 3, irrespective of what is inside. (⋅)′ is not standard notation for the successor function, which means you will have to add letters after these 3 operators to explain what you mean.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:08
$begingroup$
I'm pretty sure that $(,cdot,)'$ is a standard notation for the successor function. At least this is the notation I learned when I was in school. And it is not far fetched to recognise it as such.
$endgroup$
– Claudius
Sep 3 '15 at 13:11
$begingroup$
Can you provide any links to text where such a notation is used? (Hopefully one that isn't too obscure)
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:16
$begingroup$
see this question on math.stackexchange: math.stackexchange.com/questions/643374/… There is a reference to Kleene’s Mathematical Logic that uses this notation.
$endgroup$
– Claudius
Sep 3 '15 at 13:28
$begingroup$
I stand corrected. Although this is not as common as you expect, indicated by the accepted answer in the above question pointing out that S(n) is a more common notation.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:31
$begingroup$
By that logic, I can always define (⋅)′ to always return 3, irrespective of what is inside. (⋅)′ is not standard notation for the successor function, which means you will have to add letters after these 3 operators to explain what you mean.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:08
$begingroup$
By that logic, I can always define (⋅)′ to always return 3, irrespective of what is inside. (⋅)′ is not standard notation for the successor function, which means you will have to add letters after these 3 operators to explain what you mean.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:08
$begingroup$
I'm pretty sure that $(,cdot,)'$ is a standard notation for the successor function. At least this is the notation I learned when I was in school. And it is not far fetched to recognise it as such.
$endgroup$
– Claudius
Sep 3 '15 at 13:11
$begingroup$
I'm pretty sure that $(,cdot,)'$ is a standard notation for the successor function. At least this is the notation I learned when I was in school. And it is not far fetched to recognise it as such.
$endgroup$
– Claudius
Sep 3 '15 at 13:11
$begingroup$
Can you provide any links to text where such a notation is used? (Hopefully one that isn't too obscure)
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:16
$begingroup$
Can you provide any links to text where such a notation is used? (Hopefully one that isn't too obscure)
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:16
$begingroup$
see this question on math.stackexchange: math.stackexchange.com/questions/643374/… There is a reference to Kleene’s Mathematical Logic that uses this notation.
$endgroup$
– Claudius
Sep 3 '15 at 13:28
$begingroup$
see this question on math.stackexchange: math.stackexchange.com/questions/643374/… There is a reference to Kleene’s Mathematical Logic that uses this notation.
$endgroup$
– Claudius
Sep 3 '15 at 13:28
$begingroup$
I stand corrected. Although this is not as common as you expect, indicated by the accepted answer in the above question pointing out that S(n) is a more common notation.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:31
$begingroup$
I stand corrected. Although this is not as common as you expect, indicated by the accepted answer in the above question pointing out that S(n) is a more common notation.
$endgroup$
– CodeNewbie
Sep 3 '15 at 13:31
add a comment |
2
$begingroup$
If we can assume these digits are measured we get:
2 + √2 = √9 (true to one significant figure)
answered Jan 8 '16 at 7:27
Paul EvansPaul Evans
8,50821946
$endgroup$
add a comment |
2
$begingroup$
If we can assume these digits are measured we get:
2 + √2 = √9 (true to one significant figure)
answered Jan 8 '16 at 7:27
Paul EvansPaul Evans
8,50821946
$endgroup$
add a comment |
2
2
2
$begingroup$
If we can assume these digits are measured we get:
2 + √2 = √9 (true to one significant figure)
answered Jan 8 '16 at 7:27
Paul EvansPaul Evans
8,50821946
$endgroup$
If we can assume these digits are measured we get:
2 + √2 = √9 (true to one significant figure)
answered Jan 8 '16 at 7:27
Paul EvansPaul Evans
8,50821946
answered Jan 8 '16 at 7:27
Paul EvansPaul Evans
8,50821946
answered Jan 8 '16 at 7:27
Paul EvansPaul Evans
8,50821946
answered Jan 8 '16 at 7:27
Paul EvansPaul Evans
8,50821946
8,50821946
add a comment |
add a comment |
2
$begingroup$
With 2 mathematical operations:
$ 2-2={9} $
edited yesterday
PiIsNot3
2,005329
answered yesterday
Artem LuginArtem Lugin
536
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
3
$begingroup$
{} is the fractional part of a number. Clarifying because a set is used in another answer
$endgroup$
– Artem Lugin
yesterday
add a comment |
2
$begingroup$
With 2 mathematical operations:
$ 2-2={9} $
edited yesterday
PiIsNot3
2,005329
answered yesterday
Artem LuginArtem Lugin
536
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
3
$begingroup$
{} is the fractional part of a number. Clarifying because a set is used in another answer
$endgroup$
– Artem Lugin
yesterday
add a comment |
2
2
2
$begingroup$
With 2 mathematical operations:
$ 2-2={9} $
edited yesterday
PiIsNot3
2,005329
answered yesterday
Artem LuginArtem Lugin
536
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
With 2 mathematical operations:
$ 2-2={9} $
edited yesterday
PiIsNot3
2,005329
answered yesterday
Artem LuginArtem Lugin
536
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited yesterday
PiIsNot3
2,005329
edited yesterday
PiIsNot3
2,005329
edited yesterday
PiIsNot3
2,005329
2,005329
answered yesterday
Artem LuginArtem Lugin
536
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered yesterday
Artem LuginArtem Lugin
536
answered yesterday
Artem LuginArtem Lugin
536
536
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Artem Lugin is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
3
$begingroup$
{} is the fractional part of a number. Clarifying because a set is used in another answer
$endgroup$
– Artem Lugin
yesterday
add a comment |
3
$begingroup$
{} is the fractional part of a number. Clarifying because a set is used in another answer
$endgroup$
– Artem Lugin
yesterday
3
3
$begingroup$
{} is the fractional part of a number. Clarifying because a set is used in another answer
$endgroup$
– Artem Lugin
yesterday
$begingroup$
{} is the fractional part of a number. Clarifying because a set is used in another answer
$endgroup$
– Artem Lugin
yesterday
add a comment |
protected by Aza Sep 3 '15 at 18:46
Thank you for your interest in this question.
Because it has attracted low-quality or spam answers that had to be removed, posting an answer now requires 10 reputation on this site (the association bonus does not count).
Would you like to answer one of these unanswered questions instead?
22
$begingroup$
How can Mr. Hilbert spend an hour working on a problem in a hotel? Wouldn't he be requested to move to another room once in every few minutes?
$endgroup$
– JiK
Sep 2 '15 at 9:47
18
$begingroup$
@JiK The front desk was busy trying to complete Mr Gödel's check-in.
$endgroup$
– David Tonhofer
Sep 2 '15 at 20:11
$begingroup$
While the Grand Hotel is large, the occupants move slowly =) Summer is also down season for them I suppose?
$endgroup$
– Hackiisan
Sep 3 '15 at 0:34
$begingroup$
Does
2 + 2 <= 9qualify as "tampering with the equal sign"? It's still there, just has a < before it.$endgroup$
– Darrel Hoffman
Sep 3 '15 at 15:40
$begingroup$
You mean $leq$? =)
$endgroup$
– Hackiisan
Sep 3 '15 at 18:35