Intersection Puzzle
$begingroup$
I have invented a new puzzle called Intersection. Let's find out what it is!
Intersection
You are given an $ntimes n$ grid with circles and boxes inside arbitrary squares. A circle cannot be in the same grid square as another box; there must always be at least two circles, but at least one box; the circles and/or boxes cannot fill up every square in the grid. Now onto the real rules of the game!
Suppose we let $n=3$ and have the following configuration:
$$begin{array}{|r|c|} hline
& & \ hline
&bigcirc &square \ hline
bigcirc & & \ hline
end{array}$$
The aim of the game in this case is to connect the two circles with lines, but the lines must intersect at the grid square with the box in the middle.
- Lines only start from circles, not boxes or anywhere else;
- When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end (kind of like how Pac-Man can leave the maze from one end and enter it back in from the directly opposite end);
- Lines cannot start from a circle and then connect back to the same circle;
- Lines cannot interfere with each other in regular grid squares, but only on the squares where the boxes are in;
- Lines can only travel in rows and columns, no diagonals;
- Up to four lines can protrude from a given circle in general, but that can vary depending on the position of a circle.
- Lines can only connect to other circles by crossing at least one grid square — if two circles are in grid squares adjacent to each other, a line cannot connect them in between.
- Lines must fill every grid square!
With those rules, here is the solution (though there could be more than one, but that I don't know for sure):
$qquadqquadqquadqquadqquadquad$
How about something else?
$$begin{array}{|r|c|} hline
& &bigcirc \ hline
&bigcirc & \ hline
square & & \ hline
end{array}$$
The solution to this is:
$qquadqquadqquadqquadqquadqquadquad$
(sorry for the bad drawing skill; trust me, I'm better by hand than by software, but that's besides the point)
So, let's bump it up to something a little harder, shall we?
Puzzle
Solve the following intersection grid!
$$begin{array}{|r|c|} hline
bigcirc& & & \ hline
& &bigcirc & \ hline
&square &square & \ hline
& &bigcirc &square \ hline
end{array}$$
The first user to answer with a solution will get the tick; another answer to follow that might also have a solution will get a $+50$ rep bounty; if an answer holds more than one solution, then it will get a $+100$ rep bounty (and if that one comes first, it will instead get the tick).
I hope my puzzle makes sense.
Good luck! :D
P.S. This game is like Flow for those who know that game, except the lines, well, intersect each other.
Edit: Turns out there is a game called Flow Free: Bridges such that lines can intersect each other. Unfortunately, this was unbeknownst to me when I created and posted this puzzle. My apologies.
grid-deduction
edited Apr 4 at 2:20
Deusovi♦
62.6k6215269
asked Apr 3 at 20:57
user477343user477343
3,2101858
$endgroup$
|
show 8 more comments
$begingroup$
I have invented a new puzzle called Intersection. Let's find out what it is!
Intersection
You are given an $ntimes n$ grid with circles and boxes inside arbitrary squares. A circle cannot be in the same grid square as another box; there must always be at least two circles, but at least one box; the circles and/or boxes cannot fill up every square in the grid. Now onto the real rules of the game!
Suppose we let $n=3$ and have the following configuration:
$$begin{array}{|r|c|} hline
& & \ hline
&bigcirc &square \ hline
bigcirc & & \ hline
end{array}$$
The aim of the game in this case is to connect the two circles with lines, but the lines must intersect at the grid square with the box in the middle.
- Lines only start from circles, not boxes or anywhere else;
- When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end (kind of like how Pac-Man can leave the maze from one end and enter it back in from the directly opposite end);
- Lines cannot start from a circle and then connect back to the same circle;
- Lines cannot interfere with each other in regular grid squares, but only on the squares where the boxes are in;
- Lines can only travel in rows and columns, no diagonals;
- Up to four lines can protrude from a given circle in general, but that can vary depending on the position of a circle.
- Lines can only connect to other circles by crossing at least one grid square — if two circles are in grid squares adjacent to each other, a line cannot connect them in between.
- Lines must fill every grid square!
With those rules, here is the solution (though there could be more than one, but that I don't know for sure):
$qquadqquadqquadqquadqquadquad$
How about something else?
$$begin{array}{|r|c|} hline
& &bigcirc \ hline
&bigcirc & \ hline
square & & \ hline
end{array}$$
The solution to this is:
$qquadqquadqquadqquadqquadqquadquad$
(sorry for the bad drawing skill; trust me, I'm better by hand than by software, but that's besides the point)
So, let's bump it up to something a little harder, shall we?
Puzzle
Solve the following intersection grid!
$$begin{array}{|r|c|} hline
bigcirc& & & \ hline
& &bigcirc & \ hline
&square &square & \ hline
& &bigcirc &square \ hline
end{array}$$
The first user to answer with a solution will get the tick; another answer to follow that might also have a solution will get a $+50$ rep bounty; if an answer holds more than one solution, then it will get a $+100$ rep bounty (and if that one comes first, it will instead get the tick).
I hope my puzzle makes sense.
Good luck! :D
P.S. This game is like Flow for those who know that game, except the lines, well, intersect each other.
Edit: Turns out there is a game called Flow Free: Bridges such that lines can intersect each other. Unfortunately, this was unbeknownst to me when I created and posted this puzzle. My apologies.
grid-deduction
edited Apr 4 at 2:20
Deusovi♦
62.6k6215269
asked Apr 3 at 20:57
user477343user477343
3,2101858
$endgroup$
1
$begingroup$
Must we fill in every square? Asking this given the "Flow" reference.
$endgroup$
– EKons
Apr 3 at 21:08
1
$begingroup$
This is like the sequel Flow Free: Bridges.
$endgroup$
– noedne
Apr 3 at 21:09
1
$begingroup$
I don't think it's the exact concept, since we have to connect all pairs of circles, not just each pair of same-colored circles (your grid has three such pairs, for example, Flow Free: Bridges needs an even number of circles because of the way it works).
$endgroup$
– EKons
Apr 3 at 21:14
1
$begingroup$
@user477343 You say, "This game is like Flow except the lines intersect each other." In Flow Free: Bridges, there are bridges like your squares where the lines can intersect.
$endgroup$
– noedne
Apr 3 at 21:21
1
$begingroup$
Please don't add irrelevant tags to your questions; tags have "tag wiki" pages where you can see what tags are used for.
$endgroup$
– Deusovi♦
Apr 4 at 2:20
|
show 8 more comments
$begingroup$
I have invented a new puzzle called Intersection. Let's find out what it is!
Intersection
You are given an $ntimes n$ grid with circles and boxes inside arbitrary squares. A circle cannot be in the same grid square as another box; there must always be at least two circles, but at least one box; the circles and/or boxes cannot fill up every square in the grid. Now onto the real rules of the game!
Suppose we let $n=3$ and have the following configuration:
$$begin{array}{|r|c|} hline
& & \ hline
&bigcirc &square \ hline
bigcirc & & \ hline
end{array}$$
The aim of the game in this case is to connect the two circles with lines, but the lines must intersect at the grid square with the box in the middle.
- Lines only start from circles, not boxes or anywhere else;
- When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end (kind of like how Pac-Man can leave the maze from one end and enter it back in from the directly opposite end);
- Lines cannot start from a circle and then connect back to the same circle;
- Lines cannot interfere with each other in regular grid squares, but only on the squares where the boxes are in;
- Lines can only travel in rows and columns, no diagonals;
- Up to four lines can protrude from a given circle in general, but that can vary depending on the position of a circle.
- Lines can only connect to other circles by crossing at least one grid square — if two circles are in grid squares adjacent to each other, a line cannot connect them in between.
- Lines must fill every grid square!
With those rules, here is the solution (though there could be more than one, but that I don't know for sure):
$qquadqquadqquadqquadqquadquad$
How about something else?
$$begin{array}{|r|c|} hline
& &bigcirc \ hline
&bigcirc & \ hline
square & & \ hline
end{array}$$
The solution to this is:
$qquadqquadqquadqquadqquadqquadquad$
(sorry for the bad drawing skill; trust me, I'm better by hand than by software, but that's besides the point)
So, let's bump it up to something a little harder, shall we?
Puzzle
Solve the following intersection grid!
$$begin{array}{|r|c|} hline
bigcirc& & & \ hline
& &bigcirc & \ hline
&square &square & \ hline
& &bigcirc &square \ hline
end{array}$$
The first user to answer with a solution will get the tick; another answer to follow that might also have a solution will get a $+50$ rep bounty; if an answer holds more than one solution, then it will get a $+100$ rep bounty (and if that one comes first, it will instead get the tick).
I hope my puzzle makes sense.
Good luck! :D
P.S. This game is like Flow for those who know that game, except the lines, well, intersect each other.
Edit: Turns out there is a game called Flow Free: Bridges such that lines can intersect each other. Unfortunately, this was unbeknownst to me when I created and posted this puzzle. My apologies.
grid-deduction
edited Apr 4 at 2:20
Deusovi♦
62.6k6215269
asked Apr 3 at 20:57
user477343user477343
3,2101858
$endgroup$
I have invented a new puzzle called Intersection. Let's find out what it is!
Intersection
You are given an $ntimes n$ grid with circles and boxes inside arbitrary squares. A circle cannot be in the same grid square as another box; there must always be at least two circles, but at least one box; the circles and/or boxes cannot fill up every square in the grid. Now onto the real rules of the game!
Suppose we let $n=3$ and have the following configuration:
$$begin{array}{|r|c|} hline
& & \ hline
&bigcirc &square \ hline
bigcirc & & \ hline
end{array}$$
The aim of the game in this case is to connect the two circles with lines, but the lines must intersect at the grid square with the box in the middle.
- Lines only start from circles, not boxes or anywhere else;
- When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end (kind of like how Pac-Man can leave the maze from one end and enter it back in from the directly opposite end);
- Lines cannot start from a circle and then connect back to the same circle;
- Lines cannot interfere with each other in regular grid squares, but only on the squares where the boxes are in;
- Lines can only travel in rows and columns, no diagonals;
- Up to four lines can protrude from a given circle in general, but that can vary depending on the position of a circle.
- Lines can only connect to other circles by crossing at least one grid square — if two circles are in grid squares adjacent to each other, a line cannot connect them in between.
- Lines must fill every grid square!
With those rules, here is the solution (though there could be more than one, but that I don't know for sure):
$qquadqquadqquadqquadqquadquad$
How about something else?
$$begin{array}{|r|c|} hline
& &bigcirc \ hline
&bigcirc & \ hline
square & & \ hline
end{array}$$
The solution to this is:
$qquadqquadqquadqquadqquadqquadquad$
(sorry for the bad drawing skill; trust me, I'm better by hand than by software, but that's besides the point)
So, let's bump it up to something a little harder, shall we?
Puzzle
Solve the following intersection grid!
$$begin{array}{|r|c|} hline
bigcirc& & & \ hline
& &bigcirc & \ hline
&square &square & \ hline
& &bigcirc &square \ hline
end{array}$$
The first user to answer with a solution will get the tick; another answer to follow that might also have a solution will get a $+50$ rep bounty; if an answer holds more than one solution, then it will get a $+100$ rep bounty (and if that one comes first, it will instead get the tick).
I hope my puzzle makes sense.
Good luck! :D
P.S. This game is like Flow for those who know that game, except the lines, well, intersect each other.
Edit: Turns out there is a game called Flow Free: Bridges such that lines can intersect each other. Unfortunately, this was unbeknownst to me when I created and posted this puzzle. My apologies.
grid-deduction
grid-deduction
edited Apr 4 at 2:20
Deusovi♦
62.6k6215269
asked Apr 3 at 20:57
user477343user477343
3,2101858
edited Apr 4 at 2:20
Deusovi♦
62.6k6215269
asked Apr 3 at 20:57
user477343user477343
3,2101858
edited Apr 4 at 2:20
Deusovi♦
62.6k6215269
edited Apr 4 at 2:20
Deusovi♦
62.6k6215269
edited Apr 4 at 2:20
Deusovi♦
62.6k6215269
62.6k6215269
asked Apr 3 at 20:57
user477343user477343
3,2101858
asked Apr 3 at 20:57
user477343user477343
3,2101858
asked Apr 3 at 20:57
user477343user477343
3,2101858
3,2101858
1
$begingroup$
Must we fill in every square? Asking this given the "Flow" reference.
$endgroup$
– EKons
Apr 3 at 21:08
1
$begingroup$
This is like the sequel Flow Free: Bridges.
$endgroup$
– noedne
Apr 3 at 21:09
1
$begingroup$
I don't think it's the exact concept, since we have to connect all pairs of circles, not just each pair of same-colored circles (your grid has three such pairs, for example, Flow Free: Bridges needs an even number of circles because of the way it works).
$endgroup$
– EKons
Apr 3 at 21:14
1
$begingroup$
@user477343 You say, "This game is like Flow except the lines intersect each other." In Flow Free: Bridges, there are bridges like your squares where the lines can intersect.
$endgroup$
– noedne
Apr 3 at 21:21
1
$begingroup$
Please don't add irrelevant tags to your questions; tags have "tag wiki" pages where you can see what tags are used for.
$endgroup$
– Deusovi♦
Apr 4 at 2:20
|
show 8 more comments
1
$begingroup$
Must we fill in every square? Asking this given the "Flow" reference.
$endgroup$
– EKons
Apr 3 at 21:08
1
$begingroup$
This is like the sequel Flow Free: Bridges.
$endgroup$
– noedne
Apr 3 at 21:09
1
$begingroup$
I don't think it's the exact concept, since we have to connect all pairs of circles, not just each pair of same-colored circles (your grid has three such pairs, for example, Flow Free: Bridges needs an even number of circles because of the way it works).
$endgroup$
– EKons
Apr 3 at 21:14
1
$begingroup$
@user477343 You say, "This game is like Flow except the lines intersect each other." In Flow Free: Bridges, there are bridges like your squares where the lines can intersect.
$endgroup$
– noedne
Apr 3 at 21:21
1
$begingroup$
Please don't add irrelevant tags to your questions; tags have "tag wiki" pages where you can see what tags are used for.
$endgroup$
– Deusovi♦
Apr 4 at 2:20
1
1
$begingroup$
Must we fill in every square? Asking this given the "Flow" reference.
$endgroup$
– EKons
Apr 3 at 21:08
$begingroup$
Must we fill in every square? Asking this given the "Flow" reference.
$endgroup$
– EKons
Apr 3 at 21:08
1
1
$begingroup$
This is like the sequel Flow Free: Bridges.
$endgroup$
– noedne
Apr 3 at 21:09
$begingroup$
This is like the sequel Flow Free: Bridges.
$endgroup$
– noedne
Apr 3 at 21:09
1
1
$begingroup$
I don't think it's the exact concept, since we have to connect all pairs of circles, not just each pair of same-colored circles (your grid has three such pairs, for example, Flow Free: Bridges needs an even number of circles because of the way it works).
$endgroup$
– EKons
Apr 3 at 21:14
$begingroup$
I don't think it's the exact concept, since we have to connect all pairs of circles, not just each pair of same-colored circles (your grid has three such pairs, for example, Flow Free: Bridges needs an even number of circles because of the way it works).
$endgroup$
– EKons
Apr 3 at 21:14
1
1
$begingroup$
@user477343 You say, "This game is like Flow except the lines intersect each other." In Flow Free: Bridges, there are bridges like your squares where the lines can intersect.
$endgroup$
– noedne
Apr 3 at 21:21
$begingroup$
@user477343 You say, "This game is like Flow except the lines intersect each other." In Flow Free: Bridges, there are bridges like your squares where the lines can intersect.
$endgroup$
– noedne
Apr 3 at 21:21
1
1
$begingroup$
Please don't add irrelevant tags to your questions; tags have "tag wiki" pages where you can see what tags are used for.
$endgroup$
– Deusovi♦
Apr 4 at 2:20
$begingroup$
Please don't add irrelevant tags to your questions; tags have "tag wiki" pages where you can see what tags are used for.
$endgroup$
– Deusovi♦
Apr 4 at 2:20
|
show 8 more comments
3 Answers
3
active
oldest
votes
$begingroup$
answered Apr 3 at 21:20
noednenoedne
8,69512365
$endgroup$
$begingroup$
Yes, this was the solution I had! Good job! $(+1)$ I will give you the tick in $24$ hours from now! :D
$endgroup$
– user477343
Apr 4 at 1:47
add a comment |
$begingroup$
I think I've got an alternative solution to noedne
Here are two more solutions if we include the rule that at least two lines must protrude from a circle
answered Apr 3 at 22:43
hexominohexomino
46.1k4140219
$endgroup$
1
$begingroup$
Hmm, if I say that at least two lines must protrude from a circle, then this narrows down multiple solutions, which would exclude your answer and make @noedne's answer correct. I'll make sure to include that rule if I show this puzzle to some of my friends not on this site; but for now, I accept this as an alternative solution and will give you a $+50$ rep bounty (though I will have to wait two days form now). Well done! :P $(+1)$
$endgroup$
– user477343
Apr 4 at 1:44
1
$begingroup$
@user477343 Adding some restrictions is probably a good idea. I like the idea in this puzzle and it would be cool to see how much it can develop. I've added what I think are two more solutions based on the new restriction.
$endgroup$
– hexomino
Apr 4 at 9:04
$begingroup$
Congratulations! $boxed{color{blue}{+50}}$
$endgroup$
– user477343
16 hours ago
add a comment |
$begingroup$
It's not too different to the above, but I think this counts as
Another solution:
And here is one that is different
Another solution:
answered Apr 4 at 14:35
Elements in SpaceElements in Space
32816
$endgroup$
1
$begingroup$
As far as I can tell, rule 2 seems to forbid a line from wrapping around the grid if there is a circle in the next cell. So, for example, I think the line going up to the bottom circle is disallowed.
$endgroup$
– hexomino
2 days ago
$begingroup$
@hexomino indeed!
$endgroup$
– user477343
2 days ago
$begingroup$
Your answer is unfortunately not a solution because of Rule 2, as previously mentioned by @hexomino: When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end. Sorry about that!
$endgroup$
– user477343
2 days ago
$begingroup$
Oh, right. That is a weird rule. Whoops.
$endgroup$
– Elements in Space
2 days ago
$begingroup$
Such rules are added to increase the difficulty of the puzzle. Rule 2 in particular, however, was also included because lines can only connect via full squares. If we include this rule and then have two circles on opposite ends of the same row/column that we wish to connect, this wish would violate that rule. Not allowing such a position as opposed to changing the rule is more complicated, however (in my opinion). (+1) for your effort, nevertheless! :)
$endgroup$
– user477343
2 days ago
add a comment |
Your Answer
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
answered Apr 3 at 21:20
noednenoedne
8,69512365
$endgroup$
$begingroup$
Yes, this was the solution I had! Good job! $(+1)$ I will give you the tick in $24$ hours from now! :D
$endgroup$
– user477343
Apr 4 at 1:47
add a comment |
$begingroup$
answered Apr 3 at 21:20
noednenoedne
8,69512365
$endgroup$
$begingroup$
Yes, this was the solution I had! Good job! $(+1)$ I will give you the tick in $24$ hours from now! :D
$endgroup$
– user477343
Apr 4 at 1:47
add a comment |
$begingroup$
answered Apr 3 at 21:20
noednenoedne
8,69512365
$endgroup$
answered Apr 3 at 21:20
noednenoedne
8,69512365
answered Apr 3 at 21:20
noednenoedne
8,69512365
answered Apr 3 at 21:20
noednenoedne
8,69512365
answered Apr 3 at 21:20
noednenoedne
8,69512365
8,69512365
$begingroup$
Yes, this was the solution I had! Good job! $(+1)$ I will give you the tick in $24$ hours from now! :D
$endgroup$
– user477343
Apr 4 at 1:47
add a comment |
$begingroup$
Yes, this was the solution I had! Good job! $(+1)$ I will give you the tick in $24$ hours from now! :D
$endgroup$
– user477343
Apr 4 at 1:47
$begingroup$
Yes, this was the solution I had! Good job! $(+1)$ I will give you the tick in $24$ hours from now! :D
$endgroup$
– user477343
Apr 4 at 1:47
$begingroup$
Yes, this was the solution I had! Good job! $(+1)$ I will give you the tick in $24$ hours from now! :D
$endgroup$
– user477343
Apr 4 at 1:47
add a comment |
$begingroup$
I think I've got an alternative solution to noedne
Here are two more solutions if we include the rule that at least two lines must protrude from a circle
answered Apr 3 at 22:43
hexominohexomino
46.1k4140219
$endgroup$
1
$begingroup$
Hmm, if I say that at least two lines must protrude from a circle, then this narrows down multiple solutions, which would exclude your answer and make @noedne's answer correct. I'll make sure to include that rule if I show this puzzle to some of my friends not on this site; but for now, I accept this as an alternative solution and will give you a $+50$ rep bounty (though I will have to wait two days form now). Well done! :P $(+1)$
$endgroup$
– user477343
Apr 4 at 1:44
1
$begingroup$
@user477343 Adding some restrictions is probably a good idea. I like the idea in this puzzle and it would be cool to see how much it can develop. I've added what I think are two more solutions based on the new restriction.
$endgroup$
– hexomino
Apr 4 at 9:04
$begingroup$
Congratulations! $boxed{color{blue}{+50}}$
$endgroup$
– user477343
16 hours ago
add a comment |
$begingroup$
I think I've got an alternative solution to noedne
Here are two more solutions if we include the rule that at least two lines must protrude from a circle
answered Apr 3 at 22:43
hexominohexomino
46.1k4140219
$endgroup$
1
$begingroup$
Hmm, if I say that at least two lines must protrude from a circle, then this narrows down multiple solutions, which would exclude your answer and make @noedne's answer correct. I'll make sure to include that rule if I show this puzzle to some of my friends not on this site; but for now, I accept this as an alternative solution and will give you a $+50$ rep bounty (though I will have to wait two days form now). Well done! :P $(+1)$
$endgroup$
– user477343
Apr 4 at 1:44
1
$begingroup$
@user477343 Adding some restrictions is probably a good idea. I like the idea in this puzzle and it would be cool to see how much it can develop. I've added what I think are two more solutions based on the new restriction.
$endgroup$
– hexomino
Apr 4 at 9:04
$begingroup$
Congratulations! $boxed{color{blue}{+50}}$
$endgroup$
– user477343
16 hours ago
add a comment |
$begingroup$
I think I've got an alternative solution to noedne
Here are two more solutions if we include the rule that at least two lines must protrude from a circle
answered Apr 3 at 22:43
hexominohexomino
46.1k4140219
$endgroup$
I think I've got an alternative solution to noedne
Here are two more solutions if we include the rule that at least two lines must protrude from a circle
answered Apr 3 at 22:43
hexominohexomino
46.1k4140219
edited Apr 4 at 9:03
answered Apr 3 at 22:43
hexominohexomino
46.1k4140219
answered Apr 3 at 22:43
hexominohexomino
46.1k4140219
answered Apr 3 at 22:43
hexominohexomino
46.1k4140219
46.1k4140219
1
$begingroup$
Hmm, if I say that at least two lines must protrude from a circle, then this narrows down multiple solutions, which would exclude your answer and make @noedne's answer correct. I'll make sure to include that rule if I show this puzzle to some of my friends not on this site; but for now, I accept this as an alternative solution and will give you a $+50$ rep bounty (though I will have to wait two days form now). Well done! :P $(+1)$
$endgroup$
– user477343
Apr 4 at 1:44
1
$begingroup$
@user477343 Adding some restrictions is probably a good idea. I like the idea in this puzzle and it would be cool to see how much it can develop. I've added what I think are two more solutions based on the new restriction.
$endgroup$
– hexomino
Apr 4 at 9:04
$begingroup$
Congratulations! $boxed{color{blue}{+50}}$
$endgroup$
– user477343
16 hours ago
add a comment |
1
$begingroup$
Hmm, if I say that at least two lines must protrude from a circle, then this narrows down multiple solutions, which would exclude your answer and make @noedne's answer correct. I'll make sure to include that rule if I show this puzzle to some of my friends not on this site; but for now, I accept this as an alternative solution and will give you a $+50$ rep bounty (though I will have to wait two days form now). Well done! :P $(+1)$
$endgroup$
– user477343
Apr 4 at 1:44
1
$begingroup$
@user477343 Adding some restrictions is probably a good idea. I like the idea in this puzzle and it would be cool to see how much it can develop. I've added what I think are two more solutions based on the new restriction.
$endgroup$
– hexomino
Apr 4 at 9:04
$begingroup$
Congratulations! $boxed{color{blue}{+50}}$
$endgroup$
– user477343
16 hours ago
1
1
$begingroup$
Hmm, if I say that at least two lines must protrude from a circle, then this narrows down multiple solutions, which would exclude your answer and make @noedne's answer correct. I'll make sure to include that rule if I show this puzzle to some of my friends not on this site; but for now, I accept this as an alternative solution and will give you a $+50$ rep bounty (though I will have to wait two days form now). Well done! :P $(+1)$
$endgroup$
– user477343
Apr 4 at 1:44
$begingroup$
Hmm, if I say that at least two lines must protrude from a circle, then this narrows down multiple solutions, which would exclude your answer and make @noedne's answer correct. I'll make sure to include that rule if I show this puzzle to some of my friends not on this site; but for now, I accept this as an alternative solution and will give you a $+50$ rep bounty (though I will have to wait two days form now). Well done! :P $(+1)$
$endgroup$
– user477343
Apr 4 at 1:44
1
1
$begingroup$
@user477343 Adding some restrictions is probably a good idea. I like the idea in this puzzle and it would be cool to see how much it can develop. I've added what I think are two more solutions based on the new restriction.
$endgroup$
– hexomino
Apr 4 at 9:04
$begingroup$
@user477343 Adding some restrictions is probably a good idea. I like the idea in this puzzle and it would be cool to see how much it can develop. I've added what I think are two more solutions based on the new restriction.
$endgroup$
– hexomino
Apr 4 at 9:04
$begingroup$
Congratulations! $boxed{color{blue}{+50}}$
$endgroup$
– user477343
16 hours ago
$begingroup$
Congratulations! $boxed{color{blue}{+50}}$
$endgroup$
– user477343
16 hours ago
add a comment |
$begingroup$
It's not too different to the above, but I think this counts as
Another solution:
And here is one that is different
Another solution:
answered Apr 4 at 14:35
Elements in SpaceElements in Space
32816
$endgroup$
1
$begingroup$
As far as I can tell, rule 2 seems to forbid a line from wrapping around the grid if there is a circle in the next cell. So, for example, I think the line going up to the bottom circle is disallowed.
$endgroup$
– hexomino
2 days ago
$begingroup$
@hexomino indeed!
$endgroup$
– user477343
2 days ago
$begingroup$
Your answer is unfortunately not a solution because of Rule 2, as previously mentioned by @hexomino: When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end. Sorry about that!
$endgroup$
– user477343
2 days ago
$begingroup$
Oh, right. That is a weird rule. Whoops.
$endgroup$
– Elements in Space
2 days ago
$begingroup$
Such rules are added to increase the difficulty of the puzzle. Rule 2 in particular, however, was also included because lines can only connect via full squares. If we include this rule and then have two circles on opposite ends of the same row/column that we wish to connect, this wish would violate that rule. Not allowing such a position as opposed to changing the rule is more complicated, however (in my opinion). (+1) for your effort, nevertheless! :)
$endgroup$
– user477343
2 days ago
add a comment |
$begingroup$
It's not too different to the above, but I think this counts as
Another solution:
And here is one that is different
Another solution:
answered Apr 4 at 14:35
Elements in SpaceElements in Space
32816
$endgroup$
1
$begingroup$
As far as I can tell, rule 2 seems to forbid a line from wrapping around the grid if there is a circle in the next cell. So, for example, I think the line going up to the bottom circle is disallowed.
$endgroup$
– hexomino
2 days ago
$begingroup$
@hexomino indeed!
$endgroup$
– user477343
2 days ago
$begingroup$
Your answer is unfortunately not a solution because of Rule 2, as previously mentioned by @hexomino: When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end. Sorry about that!
$endgroup$
– user477343
2 days ago
$begingroup$
Oh, right. That is a weird rule. Whoops.
$endgroup$
– Elements in Space
2 days ago
$begingroup$
Such rules are added to increase the difficulty of the puzzle. Rule 2 in particular, however, was also included because lines can only connect via full squares. If we include this rule and then have two circles on opposite ends of the same row/column that we wish to connect, this wish would violate that rule. Not allowing such a position as opposed to changing the rule is more complicated, however (in my opinion). (+1) for your effort, nevertheless! :)
$endgroup$
– user477343
2 days ago
add a comment |
$begingroup$
It's not too different to the above, but I think this counts as
Another solution:
And here is one that is different
Another solution:
answered Apr 4 at 14:35
Elements in SpaceElements in Space
32816
$endgroup$
It's not too different to the above, but I think this counts as
Another solution:
And here is one that is different
Another solution:
answered Apr 4 at 14:35
Elements in SpaceElements in Space
32816
edited Apr 4 at 14:56
answered Apr 4 at 14:35
Elements in SpaceElements in Space
32816
answered Apr 4 at 14:35
Elements in SpaceElements in Space
32816
answered Apr 4 at 14:35
Elements in SpaceElements in Space
32816
32816
1
$begingroup$
As far as I can tell, rule 2 seems to forbid a line from wrapping around the grid if there is a circle in the next cell. So, for example, I think the line going up to the bottom circle is disallowed.
$endgroup$
– hexomino
2 days ago
$begingroup$
@hexomino indeed!
$endgroup$
– user477343
2 days ago
$begingroup$
Your answer is unfortunately not a solution because of Rule 2, as previously mentioned by @hexomino: When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end. Sorry about that!
$endgroup$
– user477343
2 days ago
$begingroup$
Oh, right. That is a weird rule. Whoops.
$endgroup$
– Elements in Space
2 days ago
$begingroup$
Such rules are added to increase the difficulty of the puzzle. Rule 2 in particular, however, was also included because lines can only connect via full squares. If we include this rule and then have two circles on opposite ends of the same row/column that we wish to connect, this wish would violate that rule. Not allowing such a position as opposed to changing the rule is more complicated, however (in my opinion). (+1) for your effort, nevertheless! :)
$endgroup$
– user477343
2 days ago
add a comment |
1
$begingroup$
As far as I can tell, rule 2 seems to forbid a line from wrapping around the grid if there is a circle in the next cell. So, for example, I think the line going up to the bottom circle is disallowed.
$endgroup$
– hexomino
2 days ago
$begingroup$
@hexomino indeed!
$endgroup$
– user477343
2 days ago
$begingroup$
Your answer is unfortunately not a solution because of Rule 2, as previously mentioned by @hexomino: When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end. Sorry about that!
$endgroup$
– user477343
2 days ago
$begingroup$
Oh, right. That is a weird rule. Whoops.
$endgroup$
– Elements in Space
2 days ago
$begingroup$
Such rules are added to increase the difficulty of the puzzle. Rule 2 in particular, however, was also included because lines can only connect via full squares. If we include this rule and then have two circles on opposite ends of the same row/column that we wish to connect, this wish would violate that rule. Not allowing such a position as opposed to changing the rule is more complicated, however (in my opinion). (+1) for your effort, nevertheless! :)
$endgroup$
– user477343
2 days ago
1
1
$begingroup$
As far as I can tell, rule 2 seems to forbid a line from wrapping around the grid if there is a circle in the next cell. So, for example, I think the line going up to the bottom circle is disallowed.
$endgroup$
– hexomino
2 days ago
$begingroup$
As far as I can tell, rule 2 seems to forbid a line from wrapping around the grid if there is a circle in the next cell. So, for example, I think the line going up to the bottom circle is disallowed.
$endgroup$
– hexomino
2 days ago
$begingroup$
@hexomino indeed!
$endgroup$
– user477343
2 days ago
$begingroup$
@hexomino indeed!
$endgroup$
– user477343
2 days ago
$begingroup$
Your answer is unfortunately not a solution because of Rule 2, as previously mentioned by @hexomino: When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end. Sorry about that!
$endgroup$
– user477343
2 days ago
$begingroup$
Your answer is unfortunately not a solution because of Rule 2, as previously mentioned by @hexomino: When a line reaches an outer edge of the grid from a particular grid square, the line can be continued from the grid square on the directly opposite end of the same row/column, unless a line or circle is in the grid square on that very opposite end. Sorry about that!
$endgroup$
– user477343
2 days ago
$begingroup$
Oh, right. That is a weird rule. Whoops.
$endgroup$
– Elements in Space
2 days ago
$begingroup$
Oh, right. That is a weird rule. Whoops.
$endgroup$
– Elements in Space
2 days ago
$begingroup$
Such rules are added to increase the difficulty of the puzzle. Rule 2 in particular, however, was also included because lines can only connect via full squares. If we include this rule and then have two circles on opposite ends of the same row/column that we wish to connect, this wish would violate that rule. Not allowing such a position as opposed to changing the rule is more complicated, however (in my opinion). (+1) for your effort, nevertheless! :)
$endgroup$
– user477343
2 days ago
$begingroup$
Such rules are added to increase the difficulty of the puzzle. Rule 2 in particular, however, was also included because lines can only connect via full squares. If we include this rule and then have two circles on opposite ends of the same row/column that we wish to connect, this wish would violate that rule. Not allowing such a position as opposed to changing the rule is more complicated, however (in my opinion). (+1) for your effort, nevertheless! :)
$endgroup$
– user477343
2 days ago
add a comment |
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1
$begingroup$
Must we fill in every square? Asking this given the "Flow" reference.
$endgroup$
– EKons
Apr 3 at 21:08
1
$begingroup$
This is like the sequel Flow Free: Bridges.
$endgroup$
– noedne
Apr 3 at 21:09
1
$begingroup$
I don't think it's the exact concept, since we have to connect all pairs of circles, not just each pair of same-colored circles (your grid has three such pairs, for example, Flow Free: Bridges needs an even number of circles because of the way it works).
$endgroup$
– EKons
Apr 3 at 21:14
1
$begingroup$
@user477343 You say, "This game is like Flow except the lines intersect each other." In Flow Free: Bridges, there are bridges like your squares where the lines can intersect.
$endgroup$
– noedne
Apr 3 at 21:21
1
$begingroup$
Please don't add irrelevant tags to your questions; tags have "tag wiki" pages where you can see what tags are used for.
$endgroup$
– Deusovi♦
Apr 4 at 2:20