Is honey really a supersaturated solution? Does heating to un-crystalize redissolve it or melt it?
$begingroup$
In the SciShow video Honey: Bacteria's Worst Enemy after about 00:30
the narrator says:
Honey is only about 17% water. Most, but not all of what remains is sugar. The two main types of sugar in honey are glucose and fructose. Like all sugars, glucose and fructose are sticky — they attract water.
Honey is technically a supersaturated solution, meaning it contains more sugar than would normally dissolve at that temperature. That’s why it eventually gets all crystally in the pantry — over time, sugar comes out of the solution.
In my experience when old honey "gets all crystally in the pantry" I've placed the jar in a hot water bath, and eventually the honey's viscous liquidy consistency is restored.
When I do this, am I redissolving the sugar, or melting it?
I'm asking because even hot, with only 17% water it's hard to imagine it can become an unsaturated solution.
everyday-chemistry solubility melting-point recrystallization viscosity
$endgroup$
add a comment |
$begingroup$
In the SciShow video Honey: Bacteria's Worst Enemy after about 00:30
the narrator says:
Honey is only about 17% water. Most, but not all of what remains is sugar. The two main types of sugar in honey are glucose and fructose. Like all sugars, glucose and fructose are sticky — they attract water.
Honey is technically a supersaturated solution, meaning it contains more sugar than would normally dissolve at that temperature. That’s why it eventually gets all crystally in the pantry — over time, sugar comes out of the solution.
In my experience when old honey "gets all crystally in the pantry" I've placed the jar in a hot water bath, and eventually the honey's viscous liquidy consistency is restored.
When I do this, am I redissolving the sugar, or melting it?
I'm asking because even hot, with only 17% water it's hard to imagine it can become an unsaturated solution.
everyday-chemistry solubility melting-point recrystallization viscosity
$endgroup$
add a comment |
$begingroup$
In the SciShow video Honey: Bacteria's Worst Enemy after about 00:30
the narrator says:
Honey is only about 17% water. Most, but not all of what remains is sugar. The two main types of sugar in honey are glucose and fructose. Like all sugars, glucose and fructose are sticky — they attract water.
Honey is technically a supersaturated solution, meaning it contains more sugar than would normally dissolve at that temperature. That’s why it eventually gets all crystally in the pantry — over time, sugar comes out of the solution.
In my experience when old honey "gets all crystally in the pantry" I've placed the jar in a hot water bath, and eventually the honey's viscous liquidy consistency is restored.
When I do this, am I redissolving the sugar, or melting it?
I'm asking because even hot, with only 17% water it's hard to imagine it can become an unsaturated solution.
everyday-chemistry solubility melting-point recrystallization viscosity
$endgroup$
In the SciShow video Honey: Bacteria's Worst Enemy after about 00:30
the narrator says:
Honey is only about 17% water. Most, but not all of what remains is sugar. The two main types of sugar in honey are glucose and fructose. Like all sugars, glucose and fructose are sticky — they attract water.
Honey is technically a supersaturated solution, meaning it contains more sugar than would normally dissolve at that temperature. That’s why it eventually gets all crystally in the pantry — over time, sugar comes out of the solution.
In my experience when old honey "gets all crystally in the pantry" I've placed the jar in a hot water bath, and eventually the honey's viscous liquidy consistency is restored.
When I do this, am I redissolving the sugar, or melting it?
I'm asking because even hot, with only 17% water it's hard to imagine it can become an unsaturated solution.
everyday-chemistry solubility melting-point recrystallization viscosity
everyday-chemistry solubility melting-point recrystallization viscosity
edited Mar 16 at 8:38
uhoh
asked Mar 16 at 8:09
uhohuhoh
1,746840
1,746840
add a comment |
add a comment |
2 Answers
2
active
oldest
votes
$begingroup$
Honey is indeed a complex mixture containing more than hundred compounds.
As for Wikipedia and depending on the point of view it is
a supersatured liquid solution
a viscous supercooled liquid (in the sense that it can get so viscous as to appear solid, without affecting its status of being a supersatured solution, and undergoes glass transition).
https://en.wikipedia.org/wiki/Honey#Physical_and_chemical_properties
The facts that you describe in the question are less surprising if we consider that:
with respect to sugars crystallization, of which at least there are two different ones, glucose and fructose, the rest of the non-sugar components must be considered to be impurities
impurities, even in traces, often hamper the crystallisation of a compound, even in simple mixture of a single compound and the above traces. This is common after organic synthesis, in which often a viscous "oil" is attained that might crystallize only upon prolonged storage or a careful removal of the disturbing trace compound(s)
finally and most important, the solubility of sugars in water is very high, and very sensitive to temperature. For instance, at room temperature glucose is already soluble in the reason of 90 g per 100 ml of water, that means a saturated solution already contains about fifty percent weight per weight of sugar
A table is here (I didn't cross check the values):
http://www.mpcfaculty.net/mark_bishop/supersaturated.htm
All this, viscosity included, makes the attainment of a supersatured solution particularly easy, as in the kitchen in the case of sucrose:
https://sciencing.com/make-supersaturated-solution-sugar-6199355.html
As such, heating crystallized honey does indeed dissolve the sugar, and a supersaturated solution is attained upon subsequent cooling.
$endgroup$
1
$begingroup$
In the circumstances the other answer is more than valid. What is peculiar is the easy to maintain the super-saturation regime (ie the resistance to crystallisation). @uhoh
$endgroup$
– Alchimista
Mar 16 at 14:49
$begingroup$
You might add the high viscosity to the list. Just about everything is slow in honey.
$endgroup$
– Karl
Mar 17 at 10:38
$begingroup$
@Karl I thought the •supercooled entry did the job. Shall I put it more in connection with slow crystallisation?
$endgroup$
– Alchimista
Mar 17 at 11:04
$begingroup$
I think so. Supercooled water is still very much like water, and the viscosity of sugar solutions does not rise differently above the solubility limit.
$endgroup$
– Karl
Mar 17 at 12:36
$begingroup$
@Karl yes but water isn't that viscous and does not show glass transition. Anyway I have emphasised the viscosity aspect further. Thx.
$endgroup$
– Alchimista
Mar 19 at 8:13
add a comment |
$begingroup$
Melting and dissolving are all the same when you look at mixtures close to saturation.
You can say water lowers the melting point of the sugar, or that the solubility of sugar increases with temperature. Different description, same fact.
What makes this seem different from e.g. a salt water solution is that the molten (i.e. non-crystalline) sugar is fully miscible with water, which is only possible because the m.p. of sugar is not so far above the Bp. of water. If you go to high pressures (like in earth's mantle), the situation between (supercritical) water and rock is probably very similar.
$endgroup$
$begingroup$
Is this a general principle in chemistry (for supersaturated solutions), or does it mostly apply to saturated solutions of sugar?
$endgroup$
– uhoh
Mar 16 at 9:36
4
$begingroup$
I would call it a non-principle. ;-) If you think about a saltwater solution, you would clearly use the word "solubility". There's a large miscibility gap. Molten sugar and water however are completely miscible, the Bp of one and Mp of the other are closeby.
$endgroup$
– Karl
Mar 16 at 9:55
add a comment |
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2 Answers
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active
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2 Answers
2
active
oldest
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active
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$begingroup$
Honey is indeed a complex mixture containing more than hundred compounds.
As for Wikipedia and depending on the point of view it is
a supersatured liquid solution
a viscous supercooled liquid (in the sense that it can get so viscous as to appear solid, without affecting its status of being a supersatured solution, and undergoes glass transition).
https://en.wikipedia.org/wiki/Honey#Physical_and_chemical_properties
The facts that you describe in the question are less surprising if we consider that:
with respect to sugars crystallization, of which at least there are two different ones, glucose and fructose, the rest of the non-sugar components must be considered to be impurities
impurities, even in traces, often hamper the crystallisation of a compound, even in simple mixture of a single compound and the above traces. This is common after organic synthesis, in which often a viscous "oil" is attained that might crystallize only upon prolonged storage or a careful removal of the disturbing trace compound(s)
finally and most important, the solubility of sugars in water is very high, and very sensitive to temperature. For instance, at room temperature glucose is already soluble in the reason of 90 g per 100 ml of water, that means a saturated solution already contains about fifty percent weight per weight of sugar
A table is here (I didn't cross check the values):
http://www.mpcfaculty.net/mark_bishop/supersaturated.htm
All this, viscosity included, makes the attainment of a supersatured solution particularly easy, as in the kitchen in the case of sucrose:
https://sciencing.com/make-supersaturated-solution-sugar-6199355.html
As such, heating crystallized honey does indeed dissolve the sugar, and a supersaturated solution is attained upon subsequent cooling.
$endgroup$
1
$begingroup$
In the circumstances the other answer is more than valid. What is peculiar is the easy to maintain the super-saturation regime (ie the resistance to crystallisation). @uhoh
$endgroup$
– Alchimista
Mar 16 at 14:49
$begingroup$
You might add the high viscosity to the list. Just about everything is slow in honey.
$endgroup$
– Karl
Mar 17 at 10:38
$begingroup$
@Karl I thought the •supercooled entry did the job. Shall I put it more in connection with slow crystallisation?
$endgroup$
– Alchimista
Mar 17 at 11:04
$begingroup$
I think so. Supercooled water is still very much like water, and the viscosity of sugar solutions does not rise differently above the solubility limit.
$endgroup$
– Karl
Mar 17 at 12:36
$begingroup$
@Karl yes but water isn't that viscous and does not show glass transition. Anyway I have emphasised the viscosity aspect further. Thx.
$endgroup$
– Alchimista
Mar 19 at 8:13
add a comment |
$begingroup$
Honey is indeed a complex mixture containing more than hundred compounds.
As for Wikipedia and depending on the point of view it is
a supersatured liquid solution
a viscous supercooled liquid (in the sense that it can get so viscous as to appear solid, without affecting its status of being a supersatured solution, and undergoes glass transition).
https://en.wikipedia.org/wiki/Honey#Physical_and_chemical_properties
The facts that you describe in the question are less surprising if we consider that:
with respect to sugars crystallization, of which at least there are two different ones, glucose and fructose, the rest of the non-sugar components must be considered to be impurities
impurities, even in traces, often hamper the crystallisation of a compound, even in simple mixture of a single compound and the above traces. This is common after organic synthesis, in which often a viscous "oil" is attained that might crystallize only upon prolonged storage or a careful removal of the disturbing trace compound(s)
finally and most important, the solubility of sugars in water is very high, and very sensitive to temperature. For instance, at room temperature glucose is already soluble in the reason of 90 g per 100 ml of water, that means a saturated solution already contains about fifty percent weight per weight of sugar
A table is here (I didn't cross check the values):
http://www.mpcfaculty.net/mark_bishop/supersaturated.htm
All this, viscosity included, makes the attainment of a supersatured solution particularly easy, as in the kitchen in the case of sucrose:
https://sciencing.com/make-supersaturated-solution-sugar-6199355.html
As such, heating crystallized honey does indeed dissolve the sugar, and a supersaturated solution is attained upon subsequent cooling.
$endgroup$
1
$begingroup$
In the circumstances the other answer is more than valid. What is peculiar is the easy to maintain the super-saturation regime (ie the resistance to crystallisation). @uhoh
$endgroup$
– Alchimista
Mar 16 at 14:49
$begingroup$
You might add the high viscosity to the list. Just about everything is slow in honey.
$endgroup$
– Karl
Mar 17 at 10:38
$begingroup$
@Karl I thought the •supercooled entry did the job. Shall I put it more in connection with slow crystallisation?
$endgroup$
– Alchimista
Mar 17 at 11:04
$begingroup$
I think so. Supercooled water is still very much like water, and the viscosity of sugar solutions does not rise differently above the solubility limit.
$endgroup$
– Karl
Mar 17 at 12:36
$begingroup$
@Karl yes but water isn't that viscous and does not show glass transition. Anyway I have emphasised the viscosity aspect further. Thx.
$endgroup$
– Alchimista
Mar 19 at 8:13
add a comment |
$begingroup$
Honey is indeed a complex mixture containing more than hundred compounds.
As for Wikipedia and depending on the point of view it is
a supersatured liquid solution
a viscous supercooled liquid (in the sense that it can get so viscous as to appear solid, without affecting its status of being a supersatured solution, and undergoes glass transition).
https://en.wikipedia.org/wiki/Honey#Physical_and_chemical_properties
The facts that you describe in the question are less surprising if we consider that:
with respect to sugars crystallization, of which at least there are two different ones, glucose and fructose, the rest of the non-sugar components must be considered to be impurities
impurities, even in traces, often hamper the crystallisation of a compound, even in simple mixture of a single compound and the above traces. This is common after organic synthesis, in which often a viscous "oil" is attained that might crystallize only upon prolonged storage or a careful removal of the disturbing trace compound(s)
finally and most important, the solubility of sugars in water is very high, and very sensitive to temperature. For instance, at room temperature glucose is already soluble in the reason of 90 g per 100 ml of water, that means a saturated solution already contains about fifty percent weight per weight of sugar
A table is here (I didn't cross check the values):
http://www.mpcfaculty.net/mark_bishop/supersaturated.htm
All this, viscosity included, makes the attainment of a supersatured solution particularly easy, as in the kitchen in the case of sucrose:
https://sciencing.com/make-supersaturated-solution-sugar-6199355.html
As such, heating crystallized honey does indeed dissolve the sugar, and a supersaturated solution is attained upon subsequent cooling.
$endgroup$
Honey is indeed a complex mixture containing more than hundred compounds.
As for Wikipedia and depending on the point of view it is
a supersatured liquid solution
a viscous supercooled liquid (in the sense that it can get so viscous as to appear solid, without affecting its status of being a supersatured solution, and undergoes glass transition).
https://en.wikipedia.org/wiki/Honey#Physical_and_chemical_properties
The facts that you describe in the question are less surprising if we consider that:
with respect to sugars crystallization, of which at least there are two different ones, glucose and fructose, the rest of the non-sugar components must be considered to be impurities
impurities, even in traces, often hamper the crystallisation of a compound, even in simple mixture of a single compound and the above traces. This is common after organic synthesis, in which often a viscous "oil" is attained that might crystallize only upon prolonged storage or a careful removal of the disturbing trace compound(s)
finally and most important, the solubility of sugars in water is very high, and very sensitive to temperature. For instance, at room temperature glucose is already soluble in the reason of 90 g per 100 ml of water, that means a saturated solution already contains about fifty percent weight per weight of sugar
A table is here (I didn't cross check the values):
http://www.mpcfaculty.net/mark_bishop/supersaturated.htm
All this, viscosity included, makes the attainment of a supersatured solution particularly easy, as in the kitchen in the case of sucrose:
https://sciencing.com/make-supersaturated-solution-sugar-6199355.html
As such, heating crystallized honey does indeed dissolve the sugar, and a supersaturated solution is attained upon subsequent cooling.
edited Mar 18 at 8:37
answered Mar 16 at 9:55
AlchimistaAlchimista
1,878310
1,878310
1
$begingroup$
In the circumstances the other answer is more than valid. What is peculiar is the easy to maintain the super-saturation regime (ie the resistance to crystallisation). @uhoh
$endgroup$
– Alchimista
Mar 16 at 14:49
$begingroup$
You might add the high viscosity to the list. Just about everything is slow in honey.
$endgroup$
– Karl
Mar 17 at 10:38
$begingroup$
@Karl I thought the •supercooled entry did the job. Shall I put it more in connection with slow crystallisation?
$endgroup$
– Alchimista
Mar 17 at 11:04
$begingroup$
I think so. Supercooled water is still very much like water, and the viscosity of sugar solutions does not rise differently above the solubility limit.
$endgroup$
– Karl
Mar 17 at 12:36
$begingroup$
@Karl yes but water isn't that viscous and does not show glass transition. Anyway I have emphasised the viscosity aspect further. Thx.
$endgroup$
– Alchimista
Mar 19 at 8:13
add a comment |
1
$begingroup$
In the circumstances the other answer is more than valid. What is peculiar is the easy to maintain the super-saturation regime (ie the resistance to crystallisation). @uhoh
$endgroup$
– Alchimista
Mar 16 at 14:49
$begingroup$
You might add the high viscosity to the list. Just about everything is slow in honey.
$endgroup$
– Karl
Mar 17 at 10:38
$begingroup$
@Karl I thought the •supercooled entry did the job. Shall I put it more in connection with slow crystallisation?
$endgroup$
– Alchimista
Mar 17 at 11:04
$begingroup$
I think so. Supercooled water is still very much like water, and the viscosity of sugar solutions does not rise differently above the solubility limit.
$endgroup$
– Karl
Mar 17 at 12:36
$begingroup$
@Karl yes but water isn't that viscous and does not show glass transition. Anyway I have emphasised the viscosity aspect further. Thx.
$endgroup$
– Alchimista
Mar 19 at 8:13
1
1
$begingroup$
In the circumstances the other answer is more than valid. What is peculiar is the easy to maintain the super-saturation regime (ie the resistance to crystallisation). @uhoh
$endgroup$
– Alchimista
Mar 16 at 14:49
$begingroup$
In the circumstances the other answer is more than valid. What is peculiar is the easy to maintain the super-saturation regime (ie the resistance to crystallisation). @uhoh
$endgroup$
– Alchimista
Mar 16 at 14:49
$begingroup$
You might add the high viscosity to the list. Just about everything is slow in honey.
$endgroup$
– Karl
Mar 17 at 10:38
$begingroup$
You might add the high viscosity to the list. Just about everything is slow in honey.
$endgroup$
– Karl
Mar 17 at 10:38
$begingroup$
@Karl I thought the •supercooled entry did the job. Shall I put it more in connection with slow crystallisation?
$endgroup$
– Alchimista
Mar 17 at 11:04
$begingroup$
@Karl I thought the •supercooled entry did the job. Shall I put it more in connection with slow crystallisation?
$endgroup$
– Alchimista
Mar 17 at 11:04
$begingroup$
I think so. Supercooled water is still very much like water, and the viscosity of sugar solutions does not rise differently above the solubility limit.
$endgroup$
– Karl
Mar 17 at 12:36
$begingroup$
I think so. Supercooled water is still very much like water, and the viscosity of sugar solutions does not rise differently above the solubility limit.
$endgroup$
– Karl
Mar 17 at 12:36
$begingroup$
@Karl yes but water isn't that viscous and does not show glass transition. Anyway I have emphasised the viscosity aspect further. Thx.
$endgroup$
– Alchimista
Mar 19 at 8:13
$begingroup$
@Karl yes but water isn't that viscous and does not show glass transition. Anyway I have emphasised the viscosity aspect further. Thx.
$endgroup$
– Alchimista
Mar 19 at 8:13
add a comment |
$begingroup$
Melting and dissolving are all the same when you look at mixtures close to saturation.
You can say water lowers the melting point of the sugar, or that the solubility of sugar increases with temperature. Different description, same fact.
What makes this seem different from e.g. a salt water solution is that the molten (i.e. non-crystalline) sugar is fully miscible with water, which is only possible because the m.p. of sugar is not so far above the Bp. of water. If you go to high pressures (like in earth's mantle), the situation between (supercritical) water and rock is probably very similar.
$endgroup$
$begingroup$
Is this a general principle in chemistry (for supersaturated solutions), or does it mostly apply to saturated solutions of sugar?
$endgroup$
– uhoh
Mar 16 at 9:36
4
$begingroup$
I would call it a non-principle. ;-) If you think about a saltwater solution, you would clearly use the word "solubility". There's a large miscibility gap. Molten sugar and water however are completely miscible, the Bp of one and Mp of the other are closeby.
$endgroup$
– Karl
Mar 16 at 9:55
add a comment |
$begingroup$
Melting and dissolving are all the same when you look at mixtures close to saturation.
You can say water lowers the melting point of the sugar, or that the solubility of sugar increases with temperature. Different description, same fact.
What makes this seem different from e.g. a salt water solution is that the molten (i.e. non-crystalline) sugar is fully miscible with water, which is only possible because the m.p. of sugar is not so far above the Bp. of water. If you go to high pressures (like in earth's mantle), the situation between (supercritical) water and rock is probably very similar.
$endgroup$
$begingroup$
Is this a general principle in chemistry (for supersaturated solutions), or does it mostly apply to saturated solutions of sugar?
$endgroup$
– uhoh
Mar 16 at 9:36
4
$begingroup$
I would call it a non-principle. ;-) If you think about a saltwater solution, you would clearly use the word "solubility". There's a large miscibility gap. Molten sugar and water however are completely miscible, the Bp of one and Mp of the other are closeby.
$endgroup$
– Karl
Mar 16 at 9:55
add a comment |
$begingroup$
Melting and dissolving are all the same when you look at mixtures close to saturation.
You can say water lowers the melting point of the sugar, or that the solubility of sugar increases with temperature. Different description, same fact.
What makes this seem different from e.g. a salt water solution is that the molten (i.e. non-crystalline) sugar is fully miscible with water, which is only possible because the m.p. of sugar is not so far above the Bp. of water. If you go to high pressures (like in earth's mantle), the situation between (supercritical) water and rock is probably very similar.
$endgroup$
Melting and dissolving are all the same when you look at mixtures close to saturation.
You can say water lowers the melting point of the sugar, or that the solubility of sugar increases with temperature. Different description, same fact.
What makes this seem different from e.g. a salt water solution is that the molten (i.e. non-crystalline) sugar is fully miscible with water, which is only possible because the m.p. of sugar is not so far above the Bp. of water. If you go to high pressures (like in earth's mantle), the situation between (supercritical) water and rock is probably very similar.
edited Mar 17 at 10:25
answered Mar 16 at 9:15
KarlKarl
6,1971433
6,1971433
$begingroup$
Is this a general principle in chemistry (for supersaturated solutions), or does it mostly apply to saturated solutions of sugar?
$endgroup$
– uhoh
Mar 16 at 9:36
4
$begingroup$
I would call it a non-principle. ;-) If you think about a saltwater solution, you would clearly use the word "solubility". There's a large miscibility gap. Molten sugar and water however are completely miscible, the Bp of one and Mp of the other are closeby.
$endgroup$
– Karl
Mar 16 at 9:55
add a comment |
$begingroup$
Is this a general principle in chemistry (for supersaturated solutions), or does it mostly apply to saturated solutions of sugar?
$endgroup$
– uhoh
Mar 16 at 9:36
4
$begingroup$
I would call it a non-principle. ;-) If you think about a saltwater solution, you would clearly use the word "solubility". There's a large miscibility gap. Molten sugar and water however are completely miscible, the Bp of one and Mp of the other are closeby.
$endgroup$
– Karl
Mar 16 at 9:55
$begingroup$
Is this a general principle in chemistry (for supersaturated solutions), or does it mostly apply to saturated solutions of sugar?
$endgroup$
– uhoh
Mar 16 at 9:36
$begingroup$
Is this a general principle in chemistry (for supersaturated solutions), or does it mostly apply to saturated solutions of sugar?
$endgroup$
– uhoh
Mar 16 at 9:36
4
4
$begingroup$
I would call it a non-principle. ;-) If you think about a saltwater solution, you would clearly use the word "solubility". There's a large miscibility gap. Molten sugar and water however are completely miscible, the Bp of one and Mp of the other are closeby.
$endgroup$
– Karl
Mar 16 at 9:55
$begingroup$
I would call it a non-principle. ;-) If you think about a saltwater solution, you would clearly use the word "solubility". There's a large miscibility gap. Molten sugar and water however are completely miscible, the Bp of one and Mp of the other are closeby.
$endgroup$
– Karl
Mar 16 at 9:55
add a comment |
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StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
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Sign up using Email and Password
Post as a guest
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Sign up or log in
StackExchange.ready(function () {
StackExchange.helpers.onClickDraftSave('#login-link');
});
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown