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When is composition of meromorphic functions meromorphic



The Next CEO of Stack OverflowExplicit Representations of Meromorphic Functions as Quotients of Entire FunctionsMeromorphic functions on the unit diskCan all meromorphic functions be described by analytic parametrizations?Tilings and meromorphic functionsMeromorphic functions of several variablesfind all meromorphic functions s.t. |f|=1 where |z|=1Can a meromorphic function have removable singularities?Meromorphic functions on $hatmathbbC$ are rational functionsTerminology for a set of meromorphic functions with controlled poles and ordersWhy is the derevative of meromorphic function is meromorphic?










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When I compose a meromorphic and a holomorphic function, I get a meromorphic function. Are there other cases when a composition of two meromorphic functions is meromorphic? For example, if I compose a holomorphic and a meromorphic function? Or does it hold that the composition is meromorphic in general?










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$endgroup$
















    6












    $begingroup$


    When I compose a meromorphic and a holomorphic function, I get a meromorphic function. Are there other cases when a composition of two meromorphic functions is meromorphic? For example, if I compose a holomorphic and a meromorphic function? Or does it hold that the composition is meromorphic in general?










    share|cite|improve this question









    $endgroup$














      6












      6








      6





      $begingroup$


      When I compose a meromorphic and a holomorphic function, I get a meromorphic function. Are there other cases when a composition of two meromorphic functions is meromorphic? For example, if I compose a holomorphic and a meromorphic function? Or does it hold that the composition is meromorphic in general?










      share|cite|improve this question









      $endgroup$




      When I compose a meromorphic and a holomorphic function, I get a meromorphic function. Are there other cases when a composition of two meromorphic functions is meromorphic? For example, if I compose a holomorphic and a meromorphic function? Or does it hold that the composition is meromorphic in general?







      complex-analysis function-and-relation-composition holomorphic-functions meromorphic-functions






      share|cite|improve this question













      share|cite|improve this question











      share|cite|improve this question




      share|cite|improve this question










      asked Mar 19 at 9:13









      user2316602user2316602

      707




      707




















          2 Answers
          2






          active

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          9












          $begingroup$

          Assume that $f$ and $g$ are meromorphic in $Bbb C$, and that the composition $h = f circ g$ is also meromorphic in $Bbb C$.



          If $f$ is not a rational function then it has an essential singularity at $z= infty$. If in addition, $g$ has a pole at $z_0$, then the Casorati-Weierstraß theorem shows that $lim_zto z_0 f(g(z))$ does not exist in the extended complex plane. So this can not happen.



          Therefore $f circ g$ is meromorphic in $Bbb C$ if and only if




          • $f$ is a rational function, or


          • $g$ is holomorphic in $Bbb C$.





          share|cite|improve this answer









          $endgroup$




















            4












            $begingroup$

            The composition of holomorphic functions is holomorphic. As a special case, a holomorphic function followed by a meromorphic function is meromorphic.



            I say 'special case' because we can think of a meromorphic function as a holomorphic function $mathbb C to P^1(mathbb C)$.



            The converse is often false. In fact, when:




            • $f$ is entire and there is a value which it reaches infinitely often


            • $g$ is meromorphic with at least one pole

            then $f circ g$ is not meromorphic unless $f$ is constant. Indeed, $f circ g$ reaches a value infinitely often in any neighborhood of the pole of $g$, which can only be if $f circ g$ is constant.



            Examples: $f = sin z$, $g = frac1z$, or $f = e^z$, $g = frac1z$, ...






            share|cite|improve this answer











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              9












              $begingroup$

              Assume that $f$ and $g$ are meromorphic in $Bbb C$, and that the composition $h = f circ g$ is also meromorphic in $Bbb C$.



              If $f$ is not a rational function then it has an essential singularity at $z= infty$. If in addition, $g$ has a pole at $z_0$, then the Casorati-Weierstraß theorem shows that $lim_zto z_0 f(g(z))$ does not exist in the extended complex plane. So this can not happen.



              Therefore $f circ g$ is meromorphic in $Bbb C$ if and only if




              • $f$ is a rational function, or


              • $g$ is holomorphic in $Bbb C$.





              share|cite|improve this answer









              $endgroup$

















                9












                $begingroup$

                Assume that $f$ and $g$ are meromorphic in $Bbb C$, and that the composition $h = f circ g$ is also meromorphic in $Bbb C$.



                If $f$ is not a rational function then it has an essential singularity at $z= infty$. If in addition, $g$ has a pole at $z_0$, then the Casorati-Weierstraß theorem shows that $lim_zto z_0 f(g(z))$ does not exist in the extended complex plane. So this can not happen.



                Therefore $f circ g$ is meromorphic in $Bbb C$ if and only if




                • $f$ is a rational function, or


                • $g$ is holomorphic in $Bbb C$.





                share|cite|improve this answer









                $endgroup$















                  9












                  9








                  9





                  $begingroup$

                  Assume that $f$ and $g$ are meromorphic in $Bbb C$, and that the composition $h = f circ g$ is also meromorphic in $Bbb C$.



                  If $f$ is not a rational function then it has an essential singularity at $z= infty$. If in addition, $g$ has a pole at $z_0$, then the Casorati-Weierstraß theorem shows that $lim_zto z_0 f(g(z))$ does not exist in the extended complex plane. So this can not happen.



                  Therefore $f circ g$ is meromorphic in $Bbb C$ if and only if




                  • $f$ is a rational function, or


                  • $g$ is holomorphic in $Bbb C$.





                  share|cite|improve this answer









                  $endgroup$



                  Assume that $f$ and $g$ are meromorphic in $Bbb C$, and that the composition $h = f circ g$ is also meromorphic in $Bbb C$.



                  If $f$ is not a rational function then it has an essential singularity at $z= infty$. If in addition, $g$ has a pole at $z_0$, then the Casorati-Weierstraß theorem shows that $lim_zto z_0 f(g(z))$ does not exist in the extended complex plane. So this can not happen.



                  Therefore $f circ g$ is meromorphic in $Bbb C$ if and only if




                  • $f$ is a rational function, or


                  • $g$ is holomorphic in $Bbb C$.






                  share|cite|improve this answer












                  share|cite|improve this answer



                  share|cite|improve this answer










                  answered Mar 19 at 9:45









                  Martin RMartin R

                  30.6k33558




                  30.6k33558





















                      4












                      $begingroup$

                      The composition of holomorphic functions is holomorphic. As a special case, a holomorphic function followed by a meromorphic function is meromorphic.



                      I say 'special case' because we can think of a meromorphic function as a holomorphic function $mathbb C to P^1(mathbb C)$.



                      The converse is often false. In fact, when:




                      • $f$ is entire and there is a value which it reaches infinitely often


                      • $g$ is meromorphic with at least one pole

                      then $f circ g$ is not meromorphic unless $f$ is constant. Indeed, $f circ g$ reaches a value infinitely often in any neighborhood of the pole of $g$, which can only be if $f circ g$ is constant.



                      Examples: $f = sin z$, $g = frac1z$, or $f = e^z$, $g = frac1z$, ...






                      share|cite|improve this answer











                      $endgroup$

















                        4












                        $begingroup$

                        The composition of holomorphic functions is holomorphic. As a special case, a holomorphic function followed by a meromorphic function is meromorphic.



                        I say 'special case' because we can think of a meromorphic function as a holomorphic function $mathbb C to P^1(mathbb C)$.



                        The converse is often false. In fact, when:




                        • $f$ is entire and there is a value which it reaches infinitely often


                        • $g$ is meromorphic with at least one pole

                        then $f circ g$ is not meromorphic unless $f$ is constant. Indeed, $f circ g$ reaches a value infinitely often in any neighborhood of the pole of $g$, which can only be if $f circ g$ is constant.



                        Examples: $f = sin z$, $g = frac1z$, or $f = e^z$, $g = frac1z$, ...






                        share|cite|improve this answer











                        $endgroup$















                          4












                          4








                          4





                          $begingroup$

                          The composition of holomorphic functions is holomorphic. As a special case, a holomorphic function followed by a meromorphic function is meromorphic.



                          I say 'special case' because we can think of a meromorphic function as a holomorphic function $mathbb C to P^1(mathbb C)$.



                          The converse is often false. In fact, when:




                          • $f$ is entire and there is a value which it reaches infinitely often


                          • $g$ is meromorphic with at least one pole

                          then $f circ g$ is not meromorphic unless $f$ is constant. Indeed, $f circ g$ reaches a value infinitely often in any neighborhood of the pole of $g$, which can only be if $f circ g$ is constant.



                          Examples: $f = sin z$, $g = frac1z$, or $f = e^z$, $g = frac1z$, ...






                          share|cite|improve this answer











                          $endgroup$



                          The composition of holomorphic functions is holomorphic. As a special case, a holomorphic function followed by a meromorphic function is meromorphic.



                          I say 'special case' because we can think of a meromorphic function as a holomorphic function $mathbb C to P^1(mathbb C)$.



                          The converse is often false. In fact, when:




                          • $f$ is entire and there is a value which it reaches infinitely often


                          • $g$ is meromorphic with at least one pole

                          then $f circ g$ is not meromorphic unless $f$ is constant. Indeed, $f circ g$ reaches a value infinitely often in any neighborhood of the pole of $g$, which can only be if $f circ g$ is constant.



                          Examples: $f = sin z$, $g = frac1z$, or $f = e^z$, $g = frac1z$, ...







                          share|cite|improve this answer














                          share|cite|improve this answer



                          share|cite|improve this answer








                          edited Mar 19 at 9:32

























                          answered Mar 19 at 9:23









                          rabotarabota

                          14.4k32784




                          14.4k32784



























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