Gantt Chart like rectangles with log scalePoets of the 19th centuryIs there a way to output histogram x and y data without using the Histogram chart function?BarChart and Log Scale results in different bar originsIssue with ListDensityPlot when using logarithmic scaleHow to plot BarChart with error bars on logarithmic scale in Mathematica 9?How to plot two y axis? or combine(merge) two plots? Should handle faceted column as wellJumping from one dimension (1D) to two dimensions (2D)Jumping from one dimension (1D) to two dimensions (2D) Part IIWavelet Data Visualization (modus and phase) ListPlotBar chart scale in multi-chart visualisationUpdate: Combining DistributionChart and BoxWhiskerChart

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Gantt Chart like rectangles with log scale


Poets of the 19th centuryIs there a way to output histogram x and y data without using the Histogram chart function?BarChart and Log Scale results in different bar originsIssue with ListDensityPlot when using logarithmic scaleHow to plot BarChart with error bars on logarithmic scale in Mathematica 9?How to plot two y axis? or combine(merge) two plots? Should handle faceted column as wellJumping from one dimension (1D) to two dimensions (2D)Jumping from one dimension (1D) to two dimensions (2D) Part IIWavelet Data Visualization (modus and phase) ListPlotBar chart scale in multi-chart visualisationUpdate: Combining DistributionChart and BoxWhiskerChart













6












$begingroup$


I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    Mar 15 at 19:52















6












$begingroup$


I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    Mar 15 at 19:52













6












6








6





$begingroup$


I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here










share|improve this question











$endgroup$




I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here







plotting charts






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited Mar 15 at 20:17







Mockup Dungeon

















asked Mar 15 at 19:50









Mockup DungeonMockup Dungeon

895613




895613







  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    Mar 15 at 19:52












  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    Mar 15 at 19:52







1




1




$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
Mar 15 at 19:52




$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
Mar 15 at 19:52










3 Answers
3






active

oldest

votes


















10












$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, GeometricMean /@ dates];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



ListLinePlot + ScalingFunctions



ListLinePlot[data, BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]], 
ScalingFunctions -> "Log", "Linear", AspectRatio -> 1/2,
ImageSize -> Large, PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic,
Epilog -> MapIndexed[Text[Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], #, #2[[1]], Center] &, Log[GeometricMean /@ dates]]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[Log@#, # &@50, 100, 200, 500], None]


enter image description here



BarChart



BarChart[Style[#[[1]], Directive[EdgeForm[], White]], 
Labeled[Style[#[[2]], Directive[EdgeForm[], #2]],
Style[#3, White, FontSize -> Scaled[.03]], Center] & @@@
Transpose[dates, ColorData[97] /@ Range[Length@dates], labels],
BarOrigin -> Left, BarSpacing -> 0, .25, ChartLayout -> "Stacked",
ScalingFunctions -> "Log", Axes -> False,
PerformanceGoal -> "Speed", Frame -> True, ImageSize -> Large,
PlotRangePadding -> .5, AspectRatio -> 1/2]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$








  • 3




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    Mar 15 at 21:24











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    Mar 15 at 21:29


















4












$begingroup$

LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]





share|improve this answer











$endgroup$












  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    Mar 15 at 21:18


















1












$begingroup$

A = 10^5; B = 5;
rectangle[start_, length_, number_] :=
RegionPlot[Log10[start] <= x <= Log10[start + length] &&
number <= y <= number + .75, x, 0, Log10[A], y, 0, B,
PlotStyle -> LightBlue, BoundaryStyle -> Blue];
Show[
rectangle[10, 300, 1], rectangle[100, 3000, 2], rectangle[1000, 30000, 3],
FrameTicks -> Transpose@Range[0,5], 10^Range[0,5], Automatic, None, None,
AspectRatio -> 1/2
]


enter image description here






share|improve this answer











$endgroup$












  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    Mar 15 at 21:02










  • $begingroup$
    Added FrameTicks[]. You are right, not a problem.
    $endgroup$
    – mjw
    2 days ago










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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









10












$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, GeometricMean /@ dates];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



ListLinePlot + ScalingFunctions



ListLinePlot[data, BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]], 
ScalingFunctions -> "Log", "Linear", AspectRatio -> 1/2,
ImageSize -> Large, PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic,
Epilog -> MapIndexed[Text[Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], #, #2[[1]], Center] &, Log[GeometricMean /@ dates]]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[Log@#, # &@50, 100, 200, 500], None]


enter image description here



BarChart



BarChart[Style[#[[1]], Directive[EdgeForm[], White]], 
Labeled[Style[#[[2]], Directive[EdgeForm[], #2]],
Style[#3, White, FontSize -> Scaled[.03]], Center] & @@@
Transpose[dates, ColorData[97] /@ Range[Length@dates], labels],
BarOrigin -> Left, BarSpacing -> 0, .25, ChartLayout -> "Stacked",
ScalingFunctions -> "Log", Axes -> False,
PerformanceGoal -> "Speed", Frame -> True, ImageSize -> Large,
PlotRangePadding -> .5, AspectRatio -> 1/2]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$








  • 3




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    Mar 15 at 21:24











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    Mar 15 at 21:29















10












$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, GeometricMean /@ dates];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



ListLinePlot + ScalingFunctions



ListLinePlot[data, BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]], 
ScalingFunctions -> "Log", "Linear", AspectRatio -> 1/2,
ImageSize -> Large, PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic,
Epilog -> MapIndexed[Text[Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], #, #2[[1]], Center] &, Log[GeometricMean /@ dates]]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[Log@#, # &@50, 100, 200, 500], None]


enter image description here



BarChart



BarChart[Style[#[[1]], Directive[EdgeForm[], White]], 
Labeled[Style[#[[2]], Directive[EdgeForm[], #2]],
Style[#3, White, FontSize -> Scaled[.03]], Center] & @@@
Transpose[dates, ColorData[97] /@ Range[Length@dates], labels],
BarOrigin -> Left, BarSpacing -> 0, .25, ChartLayout -> "Stacked",
ScalingFunctions -> "Log", Axes -> False,
PerformanceGoal -> "Speed", Frame -> True, ImageSize -> Large,
PlotRangePadding -> .5, AspectRatio -> 1/2]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$








  • 3




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    Mar 15 at 21:24











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    Mar 15 at 21:29













10












10








10





$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, GeometricMean /@ dates];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



ListLinePlot + ScalingFunctions



ListLinePlot[data, BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]], 
ScalingFunctions -> "Log", "Linear", AspectRatio -> 1/2,
ImageSize -> Large, PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic,
Epilog -> MapIndexed[Text[Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], #, #2[[1]], Center] &, Log[GeometricMean /@ dates]]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[Log@#, # &@50, 100, 200, 500], None]


enter image description here



BarChart



BarChart[Style[#[[1]], Directive[EdgeForm[], White]], 
Labeled[Style[#[[2]], Directive[EdgeForm[], #2]],
Style[#3, White, FontSize -> Scaled[.03]], Center] & @@@
Transpose[dates, ColorData[97] /@ Range[Length@dates], labels],
BarOrigin -> Left, BarSpacing -> 0, .25, ChartLayout -> "Stacked",
ScalingFunctions -> "Log", Axes -> False,
PerformanceGoal -> "Speed", Frame -> True, ImageSize -> Large,
PlotRangePadding -> .5, AspectRatio -> 1/2]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$



SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, GeometricMean /@ dates];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



ListLinePlot + ScalingFunctions



ListLinePlot[data, BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]], 
ScalingFunctions -> "Log", "Linear", AspectRatio -> 1/2,
ImageSize -> Large, PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic,
Epilog -> MapIndexed[Text[Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], #, #2[[1]], Center] &, Log[GeometricMean /@ dates]]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[Log@#, # &@50, 100, 200, 500], None]


enter image description here



BarChart



BarChart[Style[#[[1]], Directive[EdgeForm[], White]], 
Labeled[Style[#[[2]], Directive[EdgeForm[], #2]],
Style[#3, White, FontSize -> Scaled[.03]], Center] & @@@
Transpose[dates, ColorData[97] /@ Range[Length@dates], labels],
BarOrigin -> Left, BarSpacing -> 0, .25, ChartLayout -> "Stacked",
ScalingFunctions -> "Log", Axes -> False,
PerformanceGoal -> "Speed", Frame -> True, ImageSize -> Large,
PlotRangePadding -> .5, AspectRatio -> 1/2]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century







share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 16 at 12:05

























answered Mar 15 at 21:19









kglrkglr

189k10206424




189k10206424







  • 3




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    Mar 15 at 21:24











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    Mar 15 at 21:29












  • 3




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    Mar 15 at 21:24











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    Mar 15 at 21:29







3




3




$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
$endgroup$
– David G. Stork
Mar 15 at 21:24





$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
$endgroup$
– David G. Stork
Mar 15 at 21:24













$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
Mar 15 at 21:29




$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
Mar 15 at 21:29











4












$begingroup$

LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]





share|improve this answer











$endgroup$












  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    Mar 15 at 21:18















4












$begingroup$

LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]





share|improve this answer











$endgroup$












  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    Mar 15 at 21:18













4












4








4





$begingroup$

LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]





share|improve this answer











$endgroup$



LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]






share|improve this answer














share|improve this answer



share|improve this answer








edited Mar 15 at 21:06

























answered Mar 15 at 20:47









David G. StorkDavid G. Stork

24.7k22153




24.7k22153











  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    Mar 15 at 21:18
















  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    Mar 15 at 21:18















$begingroup$
This is nice, was wondering how to use Rectangle[]. Thank you!
$endgroup$
– mjw
Mar 15 at 21:18




$begingroup$
This is nice, was wondering how to use Rectangle[]. Thank you!
$endgroup$
– mjw
Mar 15 at 21:18











1












$begingroup$

A = 10^5; B = 5;
rectangle[start_, length_, number_] :=
RegionPlot[Log10[start] <= x <= Log10[start + length] &&
number <= y <= number + .75, x, 0, Log10[A], y, 0, B,
PlotStyle -> LightBlue, BoundaryStyle -> Blue];
Show[
rectangle[10, 300, 1], rectangle[100, 3000, 2], rectangle[1000, 30000, 3],
FrameTicks -> Transpose@Range[0,5], 10^Range[0,5], Automatic, None, None,
AspectRatio -> 1/2
]


enter image description here






share|improve this answer











$endgroup$












  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    Mar 15 at 21:02










  • $begingroup$
    Added FrameTicks[]. You are right, not a problem.
    $endgroup$
    – mjw
    2 days ago















1












$begingroup$

A = 10^5; B = 5;
rectangle[start_, length_, number_] :=
RegionPlot[Log10[start] <= x <= Log10[start + length] &&
number <= y <= number + .75, x, 0, Log10[A], y, 0, B,
PlotStyle -> LightBlue, BoundaryStyle -> Blue];
Show[
rectangle[10, 300, 1], rectangle[100, 3000, 2], rectangle[1000, 30000, 3],
FrameTicks -> Transpose@Range[0,5], 10^Range[0,5], Automatic, None, None,
AspectRatio -> 1/2
]


enter image description here






share|improve this answer











$endgroup$












  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    Mar 15 at 21:02










  • $begingroup$
    Added FrameTicks[]. You are right, not a problem.
    $endgroup$
    – mjw
    2 days ago













1












1








1





$begingroup$

A = 10^5; B = 5;
rectangle[start_, length_, number_] :=
RegionPlot[Log10[start] <= x <= Log10[start + length] &&
number <= y <= number + .75, x, 0, Log10[A], y, 0, B,
PlotStyle -> LightBlue, BoundaryStyle -> Blue];
Show[
rectangle[10, 300, 1], rectangle[100, 3000, 2], rectangle[1000, 30000, 3],
FrameTicks -> Transpose@Range[0,5], 10^Range[0,5], Automatic, None, None,
AspectRatio -> 1/2
]


enter image description here






share|improve this answer











$endgroup$



A = 10^5; B = 5;
rectangle[start_, length_, number_] :=
RegionPlot[Log10[start] <= x <= Log10[start + length] &&
number <= y <= number + .75, x, 0, Log10[A], y, 0, B,
PlotStyle -> LightBlue, BoundaryStyle -> Blue];
Show[
rectangle[10, 300, 1], rectangle[100, 3000, 2], rectangle[1000, 30000, 3],
FrameTicks -> Transpose@Range[0,5], 10^Range[0,5], Automatic, None, None,
AspectRatio -> 1/2
]


enter image description here







share|improve this answer














share|improve this answer



share|improve this answer








edited 2 days ago

























answered Mar 15 at 20:36









mjwmjw

8659




8659











  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    Mar 15 at 21:02










  • $begingroup$
    Added FrameTicks[]. You are right, not a problem.
    $endgroup$
    – mjw
    2 days ago
















  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    Mar 15 at 21:02










  • $begingroup$
    Added FrameTicks[]. You are right, not a problem.
    $endgroup$
    – mjw
    2 days ago















$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
Mar 15 at 21:02




$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
Mar 15 at 21:02












$begingroup$
Added FrameTicks[]. You are right, not a problem.
$endgroup$
– mjw
2 days ago




$begingroup$
Added FrameTicks[]. You are right, not a problem.
$endgroup$
– mjw
2 days ago

















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