How to write a general formula for $-2/9, 3/16, -4/25, 5/36…$? [on hold]Proving that for every real $x$ there exists $y$ with $x+y^2inmathbbQ$Reversing an Arithmetic SequenceFinding a formula for a given series.Quartic Solution on Wikipedia special cases problem $S=0$ how to “change the choice of cubic root”?Sequences: how to prove it is crescent and calculate the limitLimit $(n - a_n)$ of sequence $a_n+1 = sqrtn^2 - a_n$Finding the general termAlmost Alternating sequence general formulaUse Ratio test to find convergence of $sum_k=1^infty frac3x^kk^3$Formula for the sequence 0,3,8,15,24 …
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How to write a general formula for $-2/9, 3/16, -4/25, 5/36…$? [on hold]
Proving that for every real $x$ there exists $y$ with $x+y^2inmathbbQ$Reversing an Arithmetic SequenceFinding a formula for a given series.Quartic Solution on Wikipedia special cases problem $S=0$ how to “change the choice of cubic root”?Sequences: how to prove it is crescent and calculate the limitLimit $(n - a_n)$ of sequence $a_n+1 = sqrtn^2 - a_n$Finding the general termAlmost Alternating sequence general formulaUse Ratio test to find convergence of $sum_k=1^infty frac3x^kk^3$Formula for the sequence 0,3,8,15,24 …
$begingroup$
I'm having a bit of trouble with this sequence:
$-2/9, 3/16, -4/25, 5/36...$
I've gotten: $(n+1)/(n+2)^2$, but I'm not sure how to account for the sign change
sequences-and-series algebra-precalculus
edited yesterday
user21820
39.4k543155
asked yesterday
vmahajan17vmahajan17
218
$endgroup$
put on hold as off-topic by Saad, RRL, user21820, José Carlos Santos, Parcly Taxel yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, RRL, user21820, José Carlos Santos, Parcly Taxel
add a comment |
$begingroup$
I'm having a bit of trouble with this sequence:
$-2/9, 3/16, -4/25, 5/36...$
I've gotten: $(n+1)/(n+2)^2$, but I'm not sure how to account for the sign change
sequences-and-series algebra-precalculus
edited yesterday
user21820
39.4k543155
asked yesterday
vmahajan17vmahajan17
218
$endgroup$
put on hold as off-topic by Saad, RRL, user21820, José Carlos Santos, Parcly Taxel yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, RRL, user21820, José Carlos Santos, Parcly Taxel
3
$begingroup$
How about $(-1)^n$?
$endgroup$
– Pebeto
yesterday
$begingroup$
ah makes sense. thanks!
$endgroup$
– vmahajan17
yesterday
add a comment |
$begingroup$
I'm having a bit of trouble with this sequence:
$-2/9, 3/16, -4/25, 5/36...$
I've gotten: $(n+1)/(n+2)^2$, but I'm not sure how to account for the sign change
sequences-and-series algebra-precalculus
edited yesterday
user21820
39.4k543155
asked yesterday
vmahajan17vmahajan17
218
$endgroup$
I'm having a bit of trouble with this sequence:
$-2/9, 3/16, -4/25, 5/36...$
I've gotten: $(n+1)/(n+2)^2$, but I'm not sure how to account for the sign change
sequences-and-series algebra-precalculus
sequences-and-series algebra-precalculus
edited yesterday
user21820
39.4k543155
asked yesterday
vmahajan17vmahajan17
218
edited yesterday
user21820
39.4k543155
asked yesterday
vmahajan17vmahajan17
218
edited yesterday
user21820
39.4k543155
edited yesterday
user21820
39.4k543155
edited yesterday
user21820
39.4k543155
39.4k543155
asked yesterday
vmahajan17vmahajan17
218
asked yesterday
vmahajan17vmahajan17
218
asked yesterday
vmahajan17vmahajan17
218
218
put on hold as off-topic by Saad, RRL, user21820, José Carlos Santos, Parcly Taxel yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, RRL, user21820, José Carlos Santos, Parcly Taxel
put on hold as off-topic by Saad, RRL, user21820, José Carlos Santos, Parcly Taxel yesterday
This question appears to be off-topic. The users who voted to close gave this specific reason:
- "This question is missing context or other details: Please provide additional context, which ideally explains why the question is relevant to you and our community. Some forms of context include: background and motivation, relevant definitions, source, possible strategies, your current progress, why the question is interesting or important, etc." – Saad, RRL, user21820, José Carlos Santos, Parcly Taxel
3
$begingroup$
How about $(-1)^n$?
$endgroup$
– Pebeto
yesterday
$begingroup$
ah makes sense. thanks!
$endgroup$
– vmahajan17
yesterday
add a comment |
3
$begingroup$
How about $(-1)^n$?
$endgroup$
– Pebeto
yesterday
$begingroup$
ah makes sense. thanks!
$endgroup$
– vmahajan17
yesterday
3
3
$begingroup$
How about $(-1)^n$?
$endgroup$
– Pebeto
yesterday
$begingroup$
How about $(-1)^n$?
$endgroup$
– Pebeto
yesterday
$begingroup$
ah makes sense. thanks!
$endgroup$
– vmahajan17
yesterday
$begingroup$
ah makes sense. thanks!
$endgroup$
– vmahajan17
yesterday
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Answer is $$(-1)^nfracn+1(n+2)^2$$
answered yesterday
Sujit BhattacharyyaSujit Bhattacharyya
1,533519
$endgroup$
add a comment |
$begingroup$
Here is the way:
$$
a_n=(-1)^nfracn+1(n+2)^2
$$
answered yesterday
Holding ArthurHolding Arthur
1,271417
$endgroup$
add a comment |
$begingroup$
$$T_n=(-1)^nfracn+1(n+2^2)$$
answered yesterday
saket kumarsaket kumar
198113
$endgroup$
add a comment |
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Answer is $$(-1)^nfracn+1(n+2)^2$$
answered yesterday
Sujit BhattacharyyaSujit Bhattacharyya
1,533519
$endgroup$
add a comment |
$begingroup$
Answer is $$(-1)^nfracn+1(n+2)^2$$
answered yesterday
Sujit BhattacharyyaSujit Bhattacharyya
1,533519
$endgroup$
add a comment |
$begingroup$
Answer is $$(-1)^nfracn+1(n+2)^2$$
answered yesterday
Sujit BhattacharyyaSujit Bhattacharyya
1,533519
$endgroup$
Answer is $$(-1)^nfracn+1(n+2)^2$$
answered yesterday
Sujit BhattacharyyaSujit Bhattacharyya
1,533519
answered yesterday
Sujit BhattacharyyaSujit Bhattacharyya
1,533519
answered yesterday
Sujit BhattacharyyaSujit Bhattacharyya
1,533519
answered yesterday
Sujit BhattacharyyaSujit Bhattacharyya
1,533519
1,533519
add a comment |
add a comment |
$begingroup$
Here is the way:
$$
a_n=(-1)^nfracn+1(n+2)^2
$$
answered yesterday
Holding ArthurHolding Arthur
1,271417
$endgroup$
add a comment |
$begingroup$
Here is the way:
$$
a_n=(-1)^nfracn+1(n+2)^2
$$
answered yesterday
Holding ArthurHolding Arthur
1,271417
$endgroup$
add a comment |
$begingroup$
Here is the way:
$$
a_n=(-1)^nfracn+1(n+2)^2
$$
answered yesterday
Holding ArthurHolding Arthur
1,271417
$endgroup$
Here is the way:
$$
a_n=(-1)^nfracn+1(n+2)^2
$$
answered yesterday
Holding ArthurHolding Arthur
1,271417
answered yesterday
Holding ArthurHolding Arthur
1,271417
answered yesterday
Holding ArthurHolding Arthur
1,271417
answered yesterday
Holding ArthurHolding Arthur
1,271417
1,271417
add a comment |
add a comment |
$begingroup$
$$T_n=(-1)^nfracn+1(n+2^2)$$
answered yesterday
saket kumarsaket kumar
198113
$endgroup$
add a comment |
$begingroup$
$$T_n=(-1)^nfracn+1(n+2^2)$$
answered yesterday
saket kumarsaket kumar
198113
$endgroup$
add a comment |
$begingroup$
$$T_n=(-1)^nfracn+1(n+2^2)$$
answered yesterday
saket kumarsaket kumar
198113
$endgroup$
$$T_n=(-1)^nfracn+1(n+2^2)$$
answered yesterday
saket kumarsaket kumar
198113
answered yesterday
saket kumarsaket kumar
198113
answered yesterday
saket kumarsaket kumar
198113
answered yesterday
saket kumarsaket kumar
198113
198113
add a comment |
add a comment |
flX89om4
3
$begingroup$
How about $(-1)^n$?
$endgroup$
– Pebeto
yesterday
$begingroup$
ah makes sense. thanks!
$endgroup$
– vmahajan17
yesterday