Sum letters are not two different
$begingroup$
The following letters all have something in common which may not be obvious at a first glance:
A B D H P
No other letters share this attribute.
Hint
There are no misspellings or typos in the title of this question. Maybe a clue though.
More hints may follow if the question is not answered.
Some great answers so far all of which I have upvoted but none of which are exactly what I am looking for.
Hint 2
The number
0and the character(also have the same property. I only said no other letters share it ;-)
Hint 3
As correctly identified by @RedBaron the ASCII table is key here. There is a good reason why "sum" is mentioned in the title and there are two reasons why "two" is mentioned.
logical-deduction pattern
asked 2 days ago
ElPedroElPedro
303210
$endgroup$
add a comment |
$begingroup$
The following letters all have something in common which may not be obvious at a first glance:
A B D H P
No other letters share this attribute.
Hint
There are no misspellings or typos in the title of this question. Maybe a clue though.
More hints may follow if the question is not answered.
Some great answers so far all of which I have upvoted but none of which are exactly what I am looking for.
Hint 2
The number
0and the character(also have the same property. I only said no other letters share it ;-)
Hint 3
As correctly identified by @RedBaron the ASCII table is key here. There is a good reason why "sum" is mentioned in the title and there are two reasons why "two" is mentioned.
logical-deduction pattern
asked 2 days ago
ElPedroElPedro
303210
$endgroup$
5
$begingroup$
Are you sure B shouldn't be included too?
$endgroup$
– Deusovi♦
2 days ago
$begingroup$
@Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
Does a!also share this property?
$endgroup$
– Eagle
2 days ago
$begingroup$
@Akari Yes it does. I have not listed them all.
$endgroup$
– ElPedro
2 days ago
add a comment |
$begingroup$
The following letters all have something in common which may not be obvious at a first glance:
A B D H P
No other letters share this attribute.
Hint
There are no misspellings or typos in the title of this question. Maybe a clue though.
More hints may follow if the question is not answered.
Some great answers so far all of which I have upvoted but none of which are exactly what I am looking for.
Hint 2
The number
0and the character(also have the same property. I only said no other letters share it ;-)
Hint 3
As correctly identified by @RedBaron the ASCII table is key here. There is a good reason why "sum" is mentioned in the title and there are two reasons why "two" is mentioned.
logical-deduction pattern
asked 2 days ago
ElPedroElPedro
303210
$endgroup$
The following letters all have something in common which may not be obvious at a first glance:
A B D H P
No other letters share this attribute.
Hint
There are no misspellings or typos in the title of this question. Maybe a clue though.
More hints may follow if the question is not answered.
Some great answers so far all of which I have upvoted but none of which are exactly what I am looking for.
Hint 2
The number
0and the character(also have the same property. I only said no other letters share it ;-)
Hint 3
As correctly identified by @RedBaron the ASCII table is key here. There is a good reason why "sum" is mentioned in the title and there are two reasons why "two" is mentioned.
logical-deduction pattern
logical-deduction pattern
asked 2 days ago
ElPedroElPedro
303210
asked 2 days ago
ElPedroElPedro
303210
edited 2 days ago
ElPedro
asked 2 days ago
ElPedroElPedro
303210
asked 2 days ago
ElPedroElPedro
303210
asked 2 days ago
ElPedroElPedro
303210
303210
5
$begingroup$
Are you sure B shouldn't be included too?
$endgroup$
– Deusovi♦
2 days ago
$begingroup$
@Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
Does a!also share this property?
$endgroup$
– Eagle
2 days ago
$begingroup$
@Akari Yes it does. I have not listed them all.
$endgroup$
– ElPedro
2 days ago
add a comment |
5
$begingroup$
Are you sure B shouldn't be included too?
$endgroup$
– Deusovi♦
2 days ago
$begingroup$
@Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
Does a!also share this property?
$endgroup$
– Eagle
2 days ago
$begingroup$
@Akari Yes it does. I have not listed them all.
$endgroup$
– ElPedro
2 days ago
5
5
$begingroup$
Are you sure B shouldn't be included too?
$endgroup$
– Deusovi♦
2 days ago
$begingroup$
Are you sure B shouldn't be included too?
$endgroup$
– Deusovi♦
2 days ago
$begingroup$
@Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
$endgroup$
– ElPedro
2 days ago
$begingroup$
@Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
$endgroup$
– ElPedro
2 days ago
1
1
$begingroup$
Does a
! also share this property?$endgroup$
– Eagle
2 days ago
$begingroup$
Does a
! also share this property?$endgroup$
– Eagle
2 days ago
$begingroup$
@Akari Yes it does. I have not listed them all.
$endgroup$
– ElPedro
2 days ago
$begingroup$
@Akari Yes it does. I have not listed them all.
$endgroup$
– ElPedro
2 days ago
add a comment |
5 Answers
5
active
oldest
votes
$begingroup$
The property seems to be related to:
Binary equivalents of the symbols/alphabets etc.
Explanation:
Binary equivalents for the following can be written as:
A -- 01000001
B -- 01000010
D -- 01000100
H -- 01001000
P -- 01010000
0 -- 00110000
( -- 00101000
So the property is,
The sum of digits in the binary equivalents is two
Or
The binary equivalents of all these have two
1s and six0s.
Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property
The title (Thanks to @trolley813):
Two might refer to the sum of the digits, which is indeed two!
Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]
Old (and wrong) answer
The property is:
The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.
And,
There is no other alphabet with the index
1+2+4+8+16+1 = 32
answered 2 days ago
EagleEagle
720226
$endgroup$
1
$begingroup$
You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
@Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
$endgroup$
– trolley813
yesterday
1
$begingroup$
Thanks a lot @trolley813 ! I've edited it
$endgroup$
– Eagle
yesterday
$begingroup$
@trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
$endgroup$
– ElPedro
yesterday
$begingroup$
A bit contrived, I know, but left room for a couple of hints.
$endgroup$
– ElPedro
yesterday
add a comment |
$begingroup$
The property is that
each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.
answered 2 days ago
Deusovi♦Deusovi
63.2k6216272
$endgroup$
2
$begingroup$
That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
$endgroup$
– ElPedro
2 days ago
2
$begingroup$
@ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
$endgroup$
– Flater
yesterday
$begingroup$
@Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
$endgroup$
– ElPedro
yesterday
add a comment |
$begingroup$
Is it
All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers
Thus we have
From ascii code table,
$A = 65 = 64 + 1 = 2^6 + 2^0$
$B = 66 = 64 + 2 = 2^6 + 2^1$
$D = 68 = 64 + 4 = 2^6 + 2^2$
$H = 72 = 64 + 8 = 2^6 + 2^3$
$P = 80 = 64 + 16 = 2^6 + 2^4$
Other letters don't share this property because
64 + 32 = 96 which does not correspond to any letter. The letter
abegins at 97
For the newer hints
$0 = 48 = 32 + 16 = 2^5 + 2^4$
$( = 40 = 32 + 8 = 2^5 + 2^3$
edited yesterday
Eagle
720226
answered 2 days ago
RedBaronRedBaron
42636
$endgroup$
1
$begingroup$
Obviously moving in the right direction with the ASCII table.
$endgroup$
– ElPedro
2 days ago
3
$begingroup$
@ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
$endgroup$
– RedBaron
2 days ago
1
$begingroup$
Still a good answer though :)
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
$endgroup$
– Flater
yesterday
add a comment |
$begingroup$
I think it's:
Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter
This means that:
Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P
answered 2 days ago
SaeleasSaeleas
1612
New contributor
Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
$endgroup$
– ElPedro
2 days ago
add a comment |
$begingroup$
Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.
answered 2 days ago
CStafford-14CStafford-14
16310
New contributor
CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
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5 Answers
5
active
oldest
votes
5 Answers
5
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
The property seems to be related to:
Binary equivalents of the symbols/alphabets etc.
Explanation:
Binary equivalents for the following can be written as:
A -- 01000001
B -- 01000010
D -- 01000100
H -- 01001000
P -- 01010000
0 -- 00110000
( -- 00101000
So the property is,
The sum of digits in the binary equivalents is two
Or
The binary equivalents of all these have two
1s and six0s.
Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property
The title (Thanks to @trolley813):
Two might refer to the sum of the digits, which is indeed two!
Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]
Old (and wrong) answer
The property is:
The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.
And,
There is no other alphabet with the index
1+2+4+8+16+1 = 32
answered 2 days ago
EagleEagle
720226
$endgroup$
1
$begingroup$
You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
@Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
$endgroup$
– trolley813
yesterday
1
$begingroup$
Thanks a lot @trolley813 ! I've edited it
$endgroup$
– Eagle
yesterday
$begingroup$
@trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
$endgroup$
– ElPedro
yesterday
$begingroup$
A bit contrived, I know, but left room for a couple of hints.
$endgroup$
– ElPedro
yesterday
add a comment |
$begingroup$
The property seems to be related to:
Binary equivalents of the symbols/alphabets etc.
Explanation:
Binary equivalents for the following can be written as:
A -- 01000001
B -- 01000010
D -- 01000100
H -- 01001000
P -- 01010000
0 -- 00110000
( -- 00101000
So the property is,
The sum of digits in the binary equivalents is two
Or
The binary equivalents of all these have two
1s and six0s.
Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property
The title (Thanks to @trolley813):
Two might refer to the sum of the digits, which is indeed two!
Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]
Old (and wrong) answer
The property is:
The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.
And,
There is no other alphabet with the index
1+2+4+8+16+1 = 32
answered 2 days ago
EagleEagle
720226
$endgroup$
1
$begingroup$
You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
@Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
$endgroup$
– trolley813
yesterday
1
$begingroup$
Thanks a lot @trolley813 ! I've edited it
$endgroup$
– Eagle
yesterday
$begingroup$
@trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
$endgroup$
– ElPedro
yesterday
$begingroup$
A bit contrived, I know, but left room for a couple of hints.
$endgroup$
– ElPedro
yesterday
add a comment |
$begingroup$
The property seems to be related to:
Binary equivalents of the symbols/alphabets etc.
Explanation:
Binary equivalents for the following can be written as:
A -- 01000001
B -- 01000010
D -- 01000100
H -- 01001000
P -- 01010000
0 -- 00110000
( -- 00101000
So the property is,
The sum of digits in the binary equivalents is two
Or
The binary equivalents of all these have two
1s and six0s.
Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property
The title (Thanks to @trolley813):
Two might refer to the sum of the digits, which is indeed two!
Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]
Old (and wrong) answer
The property is:
The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.
And,
There is no other alphabet with the index
1+2+4+8+16+1 = 32
answered 2 days ago
EagleEagle
720226
$endgroup$
The property seems to be related to:
Binary equivalents of the symbols/alphabets etc.
Explanation:
Binary equivalents for the following can be written as:
A -- 01000001
B -- 01000010
D -- 01000100
H -- 01001000
P -- 01010000
0 -- 00110000
( -- 00101000
So the property is,
The sum of digits in the binary equivalents is two
Or
The binary equivalents of all these have two
1s and six0s.
Looking at the binary equivalents of the alphabets, one can see that no other alphabets share this property
The title (Thanks to @trolley813):
Two might refer to the sum of the digits, which is indeed two!
Title might mean that the sum [of digits in] letters is not different from two [but is equal to two]
Old (and wrong) answer
The property is:
The index if each alphabet is equal to the sum of indices of the preceding alphabets in the sequence +1.
And,
There is no other alphabet with the index
1+2+4+8+16+1 = 32
answered 2 days ago
EagleEagle
720226
edited yesterday
answered 2 days ago
EagleEagle
720226
answered 2 days ago
EagleEagle
720226
answered 2 days ago
EagleEagle
720226
720226
1
$begingroup$
You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
@Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
$endgroup$
– trolley813
yesterday
1
$begingroup$
Thanks a lot @trolley813 ! I've edited it
$endgroup$
– Eagle
yesterday
$begingroup$
@trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
$endgroup$
– ElPedro
yesterday
$begingroup$
A bit contrived, I know, but left room for a couple of hints.
$endgroup$
– ElPedro
yesterday
add a comment |
1
$begingroup$
You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
@Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
$endgroup$
– trolley813
yesterday
1
$begingroup$
Thanks a lot @trolley813 ! I've edited it
$endgroup$
– Eagle
yesterday
$begingroup$
@trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
$endgroup$
– ElPedro
yesterday
$begingroup$
A bit contrived, I know, but left room for a couple of hints.
$endgroup$
– ElPedro
yesterday
1
1
$begingroup$
You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
$endgroup$
– ElPedro
2 days ago
$begingroup$
You've got it. Binary was what I was looking for but there are some other interesting patterns came out of this puzzle. I have added another hint in case anyone wants to have a go without looking at your answer. For the same reason, I'll wait a couple of hours before I accept it. well done!
$endgroup$
– ElPedro
2 days ago
1
1
$begingroup$
@Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
$endgroup$
– trolley813
yesterday
$begingroup$
@Eagle Some refinement about the title, it probably should read "sum [of digits in] letters is not different from two [i.e. equals to 2]"
$endgroup$
– trolley813
yesterday
1
1
$begingroup$
Thanks a lot @trolley813 ! I've edited it
$endgroup$
– Eagle
yesterday
$begingroup$
Thanks a lot @trolley813 ! I've edited it
$endgroup$
– Eagle
yesterday
$begingroup$
@trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
$endgroup$
– ElPedro
yesterday
$begingroup$
@trolley813 - Close but actually more of a play on words. Rot13(Fhz (Fbzr) yrggref ner abg gjb (gbb) qvssrerag) with Rot13(Fhz) and Rot13(gjb) giving clues to what I was looking for ;-)
$endgroup$
– ElPedro
yesterday
$begingroup$
A bit contrived, I know, but left room for a couple of hints.
$endgroup$
– ElPedro
yesterday
$begingroup$
A bit contrived, I know, but left room for a couple of hints.
$endgroup$
– ElPedro
yesterday
add a comment |
$begingroup$
The property is that
each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.
answered 2 days ago
Deusovi♦Deusovi
63.2k6216272
$endgroup$
2
$begingroup$
That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
$endgroup$
– ElPedro
2 days ago
2
$begingroup$
@ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
$endgroup$
– Flater
yesterday
$begingroup$
@Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
$endgroup$
– ElPedro
yesterday
add a comment |
$begingroup$
The property is that
each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.
answered 2 days ago
Deusovi♦Deusovi
63.2k6216272
$endgroup$
2
$begingroup$
That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
$endgroup$
– ElPedro
2 days ago
2
$begingroup$
@ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
$endgroup$
– Flater
yesterday
$begingroup$
@Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
$endgroup$
– ElPedro
yesterday
add a comment |
$begingroup$
The property is that
each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.
answered 2 days ago
Deusovi♦Deusovi
63.2k6216272
$endgroup$
The property is that
each of their alphanumeric values (A=1, B=2, C=3...) is a power of 2.
answered 2 days ago
Deusovi♦Deusovi
63.2k6216272
answered 2 days ago
Deusovi♦Deusovi
63.2k6216272
answered 2 days ago
Deusovi♦Deusovi
63.2k6216272
answered 2 days ago
Deusovi♦Deusovi
63.2k6216272
63.2k6216272
2
$begingroup$
That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
$endgroup$
– ElPedro
2 days ago
2
$begingroup$
@ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
$endgroup$
– Flater
yesterday
$begingroup$
@Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
$endgroup$
– ElPedro
yesterday
add a comment |
2
$begingroup$
That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
$endgroup$
– ElPedro
2 days ago
2
$begingroup$
@ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
$endgroup$
– Flater
yesterday
$begingroup$
@Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
$endgroup$
– ElPedro
yesterday
2
2
$begingroup$
That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
$endgroup$
– ElPedro
2 days ago
$begingroup$
That wasn't what I was looking for but is indeed true and is possibly a side effect of the answer that I was looking for so +1 but I won't mark it as accepted yet.
$endgroup$
– ElPedro
2 days ago
2
2
$begingroup$
@ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
$endgroup$
– Flater
yesterday
$begingroup$
@ElPedro: It is a side effect, but it hinges on rot13(jurer gur nycunorg fgnegf ba gur NFPVV gnoyr. Vtaber gur svefg ovg bs gur NFPVV inyhr (orpnhfr vg vf nyjnlf 1 naq arire punatrf sebz N gb M), ohg QB erzrzore gung vg nyjnlf pbagevohgrf gb bar bs gur gjb 1-ovgf va lbhe vagraqrq nafjre. Vtabevat gur svefg ovg, N rssrpgviryl fgnegf ng ahzrevpny inyhr 1, naq rirel "cbjre bs gjb" yrggre nqqf rknpgyl 1 1-ovg gb gur pbhag, juvpu rkcynvaf jul obgu nafjref ner pbeerpg. Vs N unq fgnegrq ba n qvssrerag NFPVV inyhr, vg znl abg unir orra gur pnfr.)
$endgroup$
– Flater
yesterday
$begingroup$
@Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
$endgroup$
– ElPedro
yesterday
$begingroup$
@Flater - Thanks for the explanation. It makes complete sense. As I said, some pretty interesting things have come out of what I at first though was a pretty simple puzzle :)
$endgroup$
– ElPedro
yesterday
add a comment |
$begingroup$
Is it
All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers
Thus we have
From ascii code table,
$A = 65 = 64 + 1 = 2^6 + 2^0$
$B = 66 = 64 + 2 = 2^6 + 2^1$
$D = 68 = 64 + 4 = 2^6 + 2^2$
$H = 72 = 64 + 8 = 2^6 + 2^3$
$P = 80 = 64 + 16 = 2^6 + 2^4$
Other letters don't share this property because
64 + 32 = 96 which does not correspond to any letter. The letter
abegins at 97
For the newer hints
$0 = 48 = 32 + 16 = 2^5 + 2^4$
$( = 40 = 32 + 8 = 2^5 + 2^3$
edited yesterday
Eagle
720226
answered 2 days ago
RedBaronRedBaron
42636
$endgroup$
1
$begingroup$
Obviously moving in the right direction with the ASCII table.
$endgroup$
– ElPedro
2 days ago
3
$begingroup$
@ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
$endgroup$
– RedBaron
2 days ago
1
$begingroup$
Still a good answer though :)
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
$endgroup$
– Flater
yesterday
add a comment |
$begingroup$
Is it
All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers
Thus we have
From ascii code table,
$A = 65 = 64 + 1 = 2^6 + 2^0$
$B = 66 = 64 + 2 = 2^6 + 2^1$
$D = 68 = 64 + 4 = 2^6 + 2^2$
$H = 72 = 64 + 8 = 2^6 + 2^3$
$P = 80 = 64 + 16 = 2^6 + 2^4$
Other letters don't share this property because
64 + 32 = 96 which does not correspond to any letter. The letter
abegins at 97
For the newer hints
$0 = 48 = 32 + 16 = 2^5 + 2^4$
$( = 40 = 32 + 8 = 2^5 + 2^3$
edited yesterday
Eagle
720226
answered 2 days ago
RedBaronRedBaron
42636
$endgroup$
1
$begingroup$
Obviously moving in the right direction with the ASCII table.
$endgroup$
– ElPedro
2 days ago
3
$begingroup$
@ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
$endgroup$
– RedBaron
2 days ago
1
$begingroup$
Still a good answer though :)
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
$endgroup$
– Flater
yesterday
add a comment |
$begingroup$
Is it
All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers
Thus we have
From ascii code table,
$A = 65 = 64 + 1 = 2^6 + 2^0$
$B = 66 = 64 + 2 = 2^6 + 2^1$
$D = 68 = 64 + 4 = 2^6 + 2^2$
$H = 72 = 64 + 8 = 2^6 + 2^3$
$P = 80 = 64 + 16 = 2^6 + 2^4$
Other letters don't share this property because
64 + 32 = 96 which does not correspond to any letter. The letter
abegins at 97
For the newer hints
$0 = 48 = 32 + 16 = 2^5 + 2^4$
$( = 40 = 32 + 8 = 2^5 + 2^3$
edited yesterday
Eagle
720226
answered 2 days ago
RedBaronRedBaron
42636
$endgroup$
Is it
All the letters, symbols in this group have ASCII codes of form $2^m + 2^n$ where m and n are integers
Thus we have
From ascii code table,
$A = 65 = 64 + 1 = 2^6 + 2^0$
$B = 66 = 64 + 2 = 2^6 + 2^1$
$D = 68 = 64 + 4 = 2^6 + 2^2$
$H = 72 = 64 + 8 = 2^6 + 2^3$
$P = 80 = 64 + 16 = 2^6 + 2^4$
Other letters don't share this property because
64 + 32 = 96 which does not correspond to any letter. The letter
abegins at 97
For the newer hints
$0 = 48 = 32 + 16 = 2^5 + 2^4$
$( = 40 = 32 + 8 = 2^5 + 2^3$
edited yesterday
Eagle
720226
answered 2 days ago
RedBaronRedBaron
42636
edited yesterday
Eagle
720226
edited yesterday
Eagle
720226
edited yesterday
Eagle
720226
720226
answered 2 days ago
RedBaronRedBaron
42636
answered 2 days ago
RedBaronRedBaron
42636
answered 2 days ago
RedBaronRedBaron
42636
42636
1
$begingroup$
Obviously moving in the right direction with the ASCII table.
$endgroup$
– ElPedro
2 days ago
3
$begingroup$
@ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
$endgroup$
– RedBaron
2 days ago
1
$begingroup$
Still a good answer though :)
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
$endgroup$
– Flater
yesterday
add a comment |
1
$begingroup$
Obviously moving in the right direction with the ASCII table.
$endgroup$
– ElPedro
2 days ago
3
$begingroup$
@ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
$endgroup$
– RedBaron
2 days ago
1
$begingroup$
Still a good answer though :)
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
$endgroup$
– Flater
yesterday
1
1
$begingroup$
Obviously moving in the right direction with the ASCII table.
$endgroup$
– ElPedro
2 days ago
$begingroup$
Obviously moving in the right direction with the ASCII table.
$endgroup$
– ElPedro
2 days ago
3
3
$begingroup$
@ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
$endgroup$
– RedBaron
2 days ago
$begingroup$
@ElPedro I guess Akari has formalized the informal property of my answer much better in his answer
$endgroup$
– RedBaron
2 days ago
1
1
$begingroup$
Still a good answer though :)
$endgroup$
– ElPedro
2 days ago
$begingroup$
Still a good answer though :)
$endgroup$
– ElPedro
2 days ago
1
1
$begingroup$
I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
$endgroup$
– Flater
yesterday
$begingroup$
I like the format of this answer more than the accepted one, simply because that's how I internally rephrased the accepted answer before even reading this one :) +1
$endgroup$
– Flater
yesterday
add a comment |
$begingroup$
I think it's:
Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter
This means that:
Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P
answered 2 days ago
SaeleasSaeleas
1612
New contributor
Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
$endgroup$
– ElPedro
2 days ago
add a comment |
$begingroup$
I think it's:
Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter
This means that:
Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P
answered 2 days ago
SaeleasSaeleas
1612
New contributor
Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
$endgroup$
– ElPedro
2 days ago
add a comment |
$begingroup$
I think it's:
Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter
This means that:
Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P
answered 2 days ago
SaeleasSaeleas
1612
New contributor
Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I think it's:
Each letter's alphanumeric value is double its predecessor, which also means, sum two times the alphanumeric value of the previous letter
This means that:
Starting from A=1 we get the sequence 1,2,4,8,16,... which corresponds to the sequence A,B,D,H,P
answered 2 days ago
SaeleasSaeleas
1612
New contributor
Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
SaeleasSaeleas
1612
New contributor
Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
SaeleasSaeleas
1612
answered 2 days ago
SaeleasSaeleas
1612
1612
New contributor
Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Saeleas is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
$endgroup$
– ElPedro
2 days ago
add a comment |
1
$begingroup$
Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
$endgroup$
– ElPedro
2 days ago
1
1
$begingroup$
Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
$endgroup$
– ElPedro
2 days ago
$begingroup$
Welcome! Again, a great answer but not exactly what I am looking for. +1 all the same.
$endgroup$
– ElPedro
2 days ago
add a comment |
$begingroup$
Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.
answered 2 days ago
CStafford-14CStafford-14
16310
New contributor
CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.
answered 2 days ago
CStafford-14CStafford-14
16310
New contributor
CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
$begingroup$
Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.
answered 2 days ago
CStafford-14CStafford-14
16310
New contributor
CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Each time you add the position of the letter (A is 1 and B is 2), the next letter's position is the sum of the previous +1.
Thus, 1+2 is 3, +4 is 7, +8 is 15, +16 is 31. You can't continue the problem because there are only 26 letters in the alphabet.
answered 2 days ago
CStafford-14CStafford-14
16310
New contributor
CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
CStafford-14CStafford-14
16310
New contributor
CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 2 days ago
CStafford-14CStafford-14
16310
answered 2 days ago
CStafford-14CStafford-14
16310
16310
New contributor
CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
CStafford-14 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
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5
$begingroup$
Are you sure B shouldn't be included too?
$endgroup$
– Deusovi♦
2 days ago
$begingroup$
@Deusovi You are indeed correct. I had missed that. I'll update the question. Thanks.
$endgroup$
– ElPedro
2 days ago
1
$begingroup$
Does a
!also share this property?$endgroup$
– Eagle
2 days ago
$begingroup$
@Akari Yes it does. I have not listed them all.
$endgroup$
– ElPedro
2 days ago